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Because snapdragons (Antirrhinum) possess the pigment anthocyanin, they have reddish purple petals. Two pure anthocyaninless lines of Antirrhinum were developed, one in California and one in Holland. They looked identical in having no red pigment at all, manifested as white (albino) flowers. However, when petals from the two lines were ground up together in buffer in the same test tube, the solution, which appeared colorless at first, gradually turned red. a. What control experiments should an investigator conduct before proceeding with further analysis? b. What could account for the production of the red color in the test tube? c. According to your explanation for part \(b\), what would be the genotypes of the two lines? d. If the two white lines were crossed, what would you predict the phenotypes of the \(\mathrm{F}_{1}\) and \(\mathrm{F}_{2}\) to be?

Short Answer

Expert verified
The control experiments assess individual color changes. Color is due to complementary genes. Genotypes are aaBB and AAbb. \\( F_1 \\\) is red; \\( F_2 \\\) shows a 9:7 red-to-white ratio.

Step by step solution

01

Identify Control Experiments

Before proceeding with further analysis, control experiments are crucial to validate results and ensure no external factors are influencing the reaction. In this experiment, an investigator should: 1. Mix petals from each line separately in the buffer to confirm no color change occurs individually. 2. Combine known anthocyanin-negative flowers with the buffer to confirm no color change. 3. Add known anthocyanin pigments to the buffer to verify that it can produce a color change.
02

Analyze Color Change Production

To account for the production of the red color in the test tube when mixing the two lines' petals, it is likely that complementary gene action is occurring. This suggests that the two lines are missing different genes necessary for anthocyanin production. By mixing them, the missing enzymes or substrates in one line are supplied by the other, allowing pigment synthesis.
03

Determine Genotypes of the Two Lines

Considering the explanation in part b, the genotypes of the two lines are complementary to each other. Let’s use gene A and gene B to indicate this possibility. One line could be aaBB (lacking functional A) and the other AAbb (lacking functional B). This configuration allows them to complement each other when mixed.
04

Predict Phenotypes of Crosses

When the two lines are crossed, in the \( F_1 \) generation, all offspring will have the genotype AaBb, producing the red phenotype since both functional genes (A and B) are present. In the \( F_2 \) generation, a 9:7 ratio is expected. 9 will exhibit the red phenotype (A-B-), while 7 will remain white (aaB-, A-bb, or aabb), originating from the presence of complementary genes necessary for pigment production.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complementary Gene Action
Complementary gene action is a fascinating concept in genetics, illustrating how two different genes can lead to a particular phenotype when both are present. In the snapdragon experiment, two pure lines lacking anthocyanin (a pigment for red coloration) were mixed, causing the solution in the test tube to turn red. This hints at complementary gene action, where each line compensated for the missing gene in the other.
If line 1 misses gene A but has gene B, and line 2 misses gene B but has gene A, neither can produce anthocyanin on its own. However, when the genes from both lines come together, they complete the gene set needed for anthocyanin production, resulting in a color change. This experiment exemplifies how missing genetic components in one organism can be "complemented" by another, underscoring the interconnectedness of genetic actions.
Phenotypic Ratios
Phenotypic ratios are a vital tool for predicting the outcomes of genetic crosses. In the case of the snapdragon experiment, understanding the phenotypic ratio helps predict what phenotypes will result from crossing two different lines.
For the snapdragon lines, when crossed, the F1 generation will all feature the red phenotype due to the presence of all necessary genes (AaBb). These offspring are a result of obtaining one functional gene from each parent line. Moving to the F2 generation, the expected phenotypic ratio illustrating complementary gene action is 9:7, where 9 will be red, having at least one copy of both genes (A and B), while 7 will be white because they lack one or both functional genes.
  • Red phenotype: At least one functional A and one functional B (A-B-)
  • White phenotype: Missing one or both functional genes (aaB-, A-bb, aabb)
Genotype and Phenotype Prediction
Genotype and phenotype prediction allows us to foresee the physical features (phenotypes) of an organism based on its genetic makeup (genotype).
In snapdragons, prediction involves understanding the genetic combination from both lines. One line has genes aaBB, and the other line has AAbb. When these two lines cross, the F1 generation will all have the genotype AaBb, reflecting the red phenotype. This simultaneous possession of both A and B genes allows for the anthocyanin production.
Predicting the F2 generation phenotypes requires a deeper understanding of Mendelian genetics and gene interaction. The crossing involves both genes re-sorting; hence, there is variation in the expression of flower color. Ratios come into play as the calculations unfold, predicting the range of possibilities—9 red to every 7 white.
Control Experiments in Genetic Research
Control experiments are foundational to genetic research as they help verify the integrity and accuracy of experimental results.
In the snapdragon pigment experiment, different control experiments are necessary to ensure the conclusions are due to actual genetic complementarity, not other factors. Essential controls include:
  • Mixing the petals of each line separately with a buffer to ensure no independent color change occurs.
  • Combining known anthocyanin-negative flowers without pigments to test if red coloration appears without the two specific lines.
  • Adding known anthocyanin pigments to the buffer to ensure the buffer system allows color reactions.
These controls confirm that the observed color change results from mixing the two lines, supporting the hypothesis of complementary gene action. Ensuring these controls provides accuracy and prevents misinterpretation of results.

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Most popular questions from this chapter

Two normal-looking fruit flies were crossed, and, in the progeny, there were 202 females and 98 males. a. What is unusual about this result? b. Provide a genetic explanation for this anomaly. c. Provide a test of your hypothesis.

Several mutants are isolated, all of which require compound G for growth. The compounds (A to E) in the biosynthetic pathway to G are known, but their order in the pathway is not known. Each compound is tested for its ability to support the growth of each mutant (1 to 5). In the following table, a plus sign indicates growth and a minus sign indicates no growth. $$\begin{array}{rcccccc} {5}{c} {\text {compound tested}} \\ \ { 2 - 6 }{1}{c} {} & &\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} & \mathrm{E} & \mathrm{G} \\ \hline \text { Mutant } & 1 & \- & \- & \- & \+ & \- & \+ \\ & 2 & \- & \+ & \- & \+ & \- & \+ \\ & 3 & \- & \- & \- & \- & \- & \+ \\ & 4 & \- & \+ & \+ & \+ & \- & \+ \\ & 5 & \+ & \+ & \+ & \+ & \- & \+ \\ \hline \end{array}$$ a. What is the order of compounds A to Ein the pathway? b. At which point in the pathway is each mutant blocked? c. Would a heterokaryon composed of double mutants 1,3 and 2,4 grow on a minimal medium? Would 1,3 and \(3,4 ?\) Would 1,2 and 2,4 and \(1,4 ?\)

In Drosophila, the autosomal recessive bw causes a dark brown eye, and the unlinked autosomal recessive \(s t\) causes a bright scarlet eye. A homozygote for both genes has a white eye. Thus, we have the following correspondences between genotypes and phenotypes: \(\begin{aligned} s t^{+} / s t^{+} ; b w^{+} / b w^{+} &=\text {red eye (wild type) } \\ s t^{+} / s t^{+} ; b w / b w &=\text { brown eye } \\ s t / s t ; b w^{+} / b w^{+} &=\text {scarlet eye } \\ s t / s t ; b w / b w &=\text { white eye } \end{aligned}\) Construct a hypothetical biosynthetic pathway showing how the gene products interact and why the different mutant combinations have different phenotypes.

In sweet peas, the synthesis of purple anthocyanin pigment in the petals is controlled by two genes, \(B\) and \(D\) The pathway is a. What color petals would you expect in a purebreeding plant unable to catalyze the first reaction? b. What color petals would you expect in a purebreeding plant unable to catalyze the second reaction? c. If the plants in parts \(a\) and \(b\) are crossed, what color petals will the \(\mathrm{F}_{1}\) plants have? d. What ratio of purple: blue:white plants would you expect in the \(\mathrm{F}_{2}\) ?

Consider two blood polymorphisms that humans have in addition to the ABO system. Two alleles \(L^{\mathrm{M}}\) and \(L^{\mathrm{N}}\) deter mine the \(\mathrm{M}, \mathrm{N},\) and \(\mathrm{MN}\) blood groups. The dominant allele \(R\) of a different gene causes a person to have the \(\mathrm{Rh}^{+}\) (rhesus positive) phenotype, whereas the homozygote for \(r\) is \(\mathrm{Rh}^{-}(\text {rhesus negative }) .\) Two men took a paternity dispute to court, each claiming three children to be his own. The blood groups of the men, the children, and their mother were as follows: $$\begin{array}{llll} \text { Person } & {3}{c} {\text { Blood group }} \\ \hline \text { husband } & \mathrm{O} & \mathrm{M} & \mathrm{Rh}^{+} \\ \text {wife's lover } & \mathrm{AB} & \mathrm{MN} & \mathrm{Rh}^{-} \\ \text {wife } & \mathrm{A} & \mathrm{N} & \mathrm{Rh}^{+} \\ \text {child 1 } & \mathrm{O} & \mathrm{MN} & \mathrm{Rh}^{+} \\ \text {child 2 } & \mathrm{A} & \mathrm{N} & \mathrm{Rh}^{+} \\ \text {child 3 } & \mathrm{A} & \mathrm{MN} & \mathrm{Rh}^{-} \\ \hline \end{array}$$ From this evidence, can the paternity of the children be established?

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