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In Drosophila, the autosomal recessive bw causes a dark brown eye, and the unlinked autosomal recessive \(s t\) causes a bright scarlet eye. A homozygote for both genes has a white eye. Thus, we have the following correspondences between genotypes and phenotypes: \(\begin{aligned} s t^{+} / s t^{+} ; b w^{+} / b w^{+} &=\text {red eye (wild type) } \\ s t^{+} / s t^{+} ; b w / b w &=\text { brown eye } \\ s t / s t ; b w^{+} / b w^{+} &=\text {scarlet eye } \\ s t / s t ; b w / b w &=\text { white eye } \end{aligned}\) Construct a hypothetical biosynthetic pathway showing how the gene products interact and why the different mutant combinations have different phenotypes.

Short Answer

Expert verified
The pathway uses \( bw \) and \( st \) wild types to produce red eyes; mutations restrict specific pigments resulting in brown, scarlet, or white eyes based on affected pathways.

Step by step solution

01

Understand the Gene Interaction

The problem provides two genes: `bw` and `st`, with their respective dominant and recessive alleles: \( bw^+ \) (normal) and \( bw \) (mutant), and \( st^+ \) (normal) and \( st \) (mutant). Both are autosomal recessive. The presence of recessive alleles affects eye color in Drosophila, creating phenotypes based on their combination.
02

Identify the Wild-type Pathway

The wild type for both genes, \( st^+ / st^+ ; bw^+ / bw^+ \), leads to a red eye color. This suggests that the normal products of these genes contribute to or maintain the wild-type red pigment.
03

Analyze the Mutant Combinations

Each genotype represents a different combination: \( st^+/st^+; bw/bw \) (brown eye), \( st/st; bw^+/bw^+ \) (scarlet eye), and \( st/st; bw/bw \) (white eye). The presence of \( bw \) alone results in a brown phenotype, indicating \( bw \) interruptions affect red pigment production, leading to brown. The \( st \) mutation leads to a scarlet phenotype, suggesting interrupted pigment production, but not complete absence. The complete absence is seen in \( st/st; bw/bw \), hence white eyes.
04

Construct the Pathway

Consider a pigment biosynthesis pathway starting with a precursor, leading two paths: one for brown pigment affected by `bw` and one for scarlet pigment affected by `st`. Each wild-type gene allows the pathway to complete and result in a red pigment. Combos of mutants inhibit the pathway partially or completely, resulting in brown, scarlet, or white, based on which pigments are not produced.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Drosophila Eye Color
In Drosophila melanogaster, also known as the fruit fly, eye color is a classic example of how genetics can affect phenotypic traits. Eye color in these flies can vary, primarily resulting from the interplay of mutant and normal alleles of two genes, `bw` (brown) and `st` (scarlet). These genes are responsible for the pigmentation pathway that leads to different eye colors. The fruit fly is a model organism used extensively in genetic studies due to its simple genetic makeup and the ease with which it can be bred in large numbers.
In the wild-type condition, dominant alleles ( bw^+ ) and ( st^+ ) result in the characteristic red eye color. The red eye color is considered the wild type or 'normal' phenotype for Drosophila.
The red eye is dependent on the correct functioning of pathways involved in the production of pigments. When these pathways are disrupted by mutations, different eye colors such as brown, scarlet, or white may appear.
  • Brown Eye: Results from the ( bw/bw ) recessive genotype, affecting pigment saturation.
  • Scarlet Eye: Occurs when the ( st/st ) genotype is recessive, stopping some pigment production.
  • White Eye: Emerges if both ( bw ) and ( st ) are recessive, halting pigment production altogether.
Understanding Drosophila eye color provides insights into genetic pathways and interactions, essential for grasping broader genetic concepts.
Autosomal Recessive Traits
Autosomal recessive traits are genetic characteristics that manifest only when an individual inherits two copies of the recessive allele - one from each parent. In the case of Drosophila eye color, both `bw` and `st` are autosomal recessive traits, meaning that their effects on eye color are only observable when both alleles in a pair are mutant (i.e., homozygous recessive).
This type of inheritance can lead to a diversity of phenotypes when different combinations of alleles are present. The main feature here is that the recessive genotype (e.g., ( bw/bw ) or ( st/st ) ) results in a particular phenotype such as brown or scarlet eyes, only when both recessive alleles are paired within an individual.
  • Phenotypic Expression: Autosomal recessive traits are not expressed in the presence of a dominant allele.
  • Carrier Concept: Parents may carry one recessive allele without displaying any traits, passing it on to offspring.
  • Genotypic Ratio: In typical scenarios, crossing two heterozygous individuals will yield a 25% chance of autosomal recessive trait expression in offspring.
Through analyzing autosomal recessive traits, one gains a deeper understanding of genetic inheritance patterns that are fundamental to fields such as genetics and biology.
Biosynthetic Pathway Analysis
Biosynthetic pathway analysis is crucial to understanding how genes directly affect phenotypes by controlling the production of specific molecules necessary for biological function. In Drosophila, the interplay between `bw` and `st` in the biosynthesis of eye pigments illustrates this concept.
The eye color in Drosophila results from biochemical pathways that produce pigments necessary for different eye colors. The product of one reaction becomes the substrate for the next, creating a pathway or sequence of chemical reactions.
  • Functionality of Pathways: Both wild-type genes permit the full pathway to function, leading to red pigment production.
  • Affected Reactions: Recessive mutants like ( bw ) disrupt certain steps, blocking pigment chains and thus affecting color.
  • Pathway Maps: Specific mutations cause enzyme deficiencies, halting pathways and preventing certain pigment formations.
An example would be a pathway where a precursor converts into an intermediate, which can go down two branches:
One branch, affected by the `bw` mutation, might lead to a brown pigment, and the other branch affected by the `st` mutation can result in a scarlet pigment. In the absence of such pathways due to dual mutations, the precursor doesn't convert into either pigment, resulting in a white phenotype.
Grasping biosynthetic pathway analysis not only helps in understanding Drosophila genetics but also has implications in broader gene function and metabolic processes across different organisms.

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Most popular questions from this chapter

On a fox ranch in Wisconsin, a mutation arose that gave a "platinum" coat color. The platinum color proved very popular with buyers of fox coats, but the breeders could not develop a pure-breeding platinum strain. Every time two platinums were crossed, some normal foxes appeared in the progeny. For example, the repeated matings of the same pair of platinums produced 82 platinum and 38 normal progeny. All other such matings gave similar progeny ratios. State a concise genetic hypothesis that accounts for these results.

In sweet peas, the synthesis of purple anthocyanin pigment in the petals is controlled by two genes, \(B\) and \(D\) The pathway is a. What color petals would you expect in a purebreeding plant unable to catalyze the first reaction? b. What color petals would you expect in a purebreeding plant unable to catalyze the second reaction? c. If the plants in parts \(a\) and \(b\) are crossed, what color petals will the \(\mathrm{F}_{1}\) plants have? d. What ratio of purple: blue:white plants would you expect in the \(\mathrm{F}_{2}\) ?

The production of pigment in the outer layer of seeds of corn requires each of the three independently assorting genes \(A, C,\) and \(R\) to be represented by at least one dominant allele, as specified in Problem \(64 .\) The dominant allele \(P r\) of a fourth independently assorting gene is required to convert the biochemical precursor into a purple pigment, and its recessive allele \(p r\) makes the pigment red. Plants that do not produce pigment have yellow seeds. Consider a cross of a strain of genotype \(A / A ; C / C ; R / R ; p r / p r\) with a strain of genotype \(a / a ; c / c ; r / r ; \operatorname{Pr} / \operatorname{Pr}\) a. What are the phenotypes of the parents? b. What will be the phenotype of the \(\mathrm{F}_{1}\) ? c. What phenotypes, and in what proportions, will appear in the progeny of a selfed \(\mathrm{F}_{1}\) ? d. What progeny proportions do you predict from the testcross of an \(\mathrm{F}_{1}\) ?

In humans, the disease galactosemia causes mental retardation at an early age. Lactose (milk sugar) is broken down to galactose plus glucose. Normally, galactose is broken down further by the enzyme galactose- phate uridyltransferase (GALT). However, in patients with galactosemia, GALT is inactive, leading to a buildup of high levels of galactose, which, in the brain, causes mental retardation. How would you provide a secondary cure for galactosemia? Would you expect this disease phenotype to be dominant or recessive?

After irradiating wild-type cells of Neurospora (a haploid fungus), a geneticist finds two leucine-requiring auxotrophic mutants. He combines the two mutants in a heterokaryon and discovers that the heterokaryon is prototrophic. a. Were the mutations in the two auxotrophs in the same gene in the pathway for synthesizing leucine or in two different genes in that pathway? Explain. b. Write the genotype of the two strains according to your model. c. What progeny and in what proportions would you predict from crossing the two auxotrophic mutants? (Assume independent assortment.)

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