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In the multiple-allele series that determines coat color in rabbits, \(c^{+}\) encodes agouti, \(c^{\mathrm{ch}}\) encodes chinchilla (a beige coat color), and \(c^{\mathrm{h}}\) encodes Himalayan. Dominance is in the order \(c^{+}>c^{\mathrm{ch}}>c^{\mathrm{h}} .\) In a cross of \(c^{+} / c^{\mathrm{ch}} \times c^{\mathrm{ch} / c^{\mathrm{h}}},\) what proportion of progeny will be chinchilla?

Short Answer

Expert verified
The proportion of progeny that will be chinchilla is \(\frac{1}{2}\).

Step by step solution

01

Determine Parental Genotypes

The parental genotypes are given as \(c^{+} / c^{ ext{ch}}\) and \(c^{ ext{ch} / c^{ ext{h}}}\). This signifies that one rabbit carries the alleles for agouti and chinchilla, and the other rabbit carries the alleles for chinchilla and Himalayan.
02

Determine Possible Gametes

Each parent can produce gametes carrying either of their alleles. The first parent \(c^{+} / c^{ ext{ch}}\) can contribute either \(c^{+}\) or \(c^{ ext{ch}}\). The second parent \(c^{ ext{ch} / c^{ ext{h}}}\) can contribute either \(c^{ ext{ch}}\) or \(c^{ ext{h}}\).
03

Set up the Punnett Square

Construct a Punnett square to combine the gametes from each parent. List \(c^{+}\) and \(c^{ ext{ch}}\) across the top for one parent, and \(c^{ ext{ch}}\) and \(c^{ ext{h}}\) down the side for the other parent.
04

Complete the Punnett Square

Fill in the Punnett square by combining the alleles from each parent's gametes:- Top: \(c^{+}, c^{ ext{ch}}\)- Side: \(c^{ ext{ch}}, c^{ ext{h}}\)| | \(c^{ ext{ch}}\) | \(c^{ ext{h}}\) ||-------|---------------|---------------|| \(c^{+}\) | \(c^{+}c^{ ext{ch}}\) | \(c^{+}c^{ ext{h}}\) || \(c^{ ext{ch}}\) | \(c^{ ext{ch}}c^{ ext{ch}}\) | \(c^{ ext{ch}}c^{ ext{h}}\) |
05

Identify Chinchilla Phenotypes

Examine the genotypes in the Punnett square to determine which result in chinchilla phenotype:- \(c^{+}c^{ ext{ch}}\): agouti (\(c^{+}\) dominates)- \(c^{+}c^{ ext{h}}\): agouti (\(c^{+}\) dominates)- \(c^{ ext{ch}}c^{ ext{ch}}\): chinchilla- \(c^{ ext{ch}}c^{ ext{h}}\): chinchillaChinchilla phenotype appears in \(c^{ ext{ch}}c^{ ext{ch}}\) and \(c^{ ext{ch}}c^{ ext{h}}\) genotypes.
06

Calculate Proportion of Chinchilla Progeny

There are two genotypes resulting in chinchilla coats out of four total possible genotypes (\(c^{ ext{ch}}c^{ ext{ch}}\) and \(c^{ ext{ch}}c^{ ext{h}}\)). Thus, the proportion of chinchilla progeny is \(\frac{2}{4} = \frac{1}{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multiple Alleles
In the realm of genetics, multiple alleles refer to a situation where more than two alleles for a particular gene exist within a population. While humans generally have two alleles for each gene, offspring can inherit these from a larger variety within the gene pool.
In the case of the rabbit coat color, there are three alleles: \(c^{+}\), \(c^{\mathrm{ch}}\), and \(c^{\mathrm{h}}\). Each allele encodes a different coat color: agouti, chinchilla, and Himalayan, respectively.
  • \(c^{+}\) for agouti represents the wild-type color.
  • \(c^{\mathrm{ch}}\) for chinchilla provides a beige coat.
  • \(c^{\mathrm{h}}\) for Himalayan gives the rabbit a special coat that changes with temperature.
All these alleles exist in the rabbit population, which means they can be passed on to offspring. Multiple alleles contribute to genetic diversity, enabling offspring to have a variety of traits in a population.
Dominance Hierarchy
Dominance hierarchy describes how different alleles interact with each other to determine the trait expression in individuals. When alleles do not all contribute equally, some will dominate over others.
In the rabbit example, \(c^{+}\) is dominant over both \(c^{\mathrm{ch}}\) and \(c^{\mathrm{h}}\), while \(c^{\mathrm{ch}}\) is dominant over \(c^{\mathrm{h}}\). The order of dominance is \(c^{+} > c^{\mathrm{ch}} > c^{\mathrm{h}}\).
  • \(c^{+} > c^{\mathrm{ch}}\) means that if \(c^{+}\) is present, the agouti color will show.
  • \(c^{\mathrm{ch}} > c^{\mathrm{h}}\) means that if \(c^{+}\) is absent, \(c^{\mathrm{ch}}\) will produce a chinchilla coat despite the presence of \(c^{\mathrm{h}}\).
  • The least dominant allele, \(c^{\mathrm{h}}\), only expresses the Himalayan trait if both alleles are the same.
Understanding this hierarchy is crucial for predicting the phenotypes of offspring.
Punnett Square
The Punnett square is a visual tool used in genetics to predict the gene combinations in offspring. By organizing the alleles from each parent, it provides a straightforward method of determining the potential genetic outcomes.
For our example with rabbits, constructing a Punnett square helps to predict the variety of coat colors in the offspring. Each parent's possible gametes are listed across the axes:
  • The first parent's alleles (\(c^{+}\) and \(c^{\mathrm{ch}}\)) top the columns.
  • The second parent's alleles (\(c^{\mathrm{ch}}\) and \(c^{\mathrm{h}}\)) head the rows.
The Punnett square looks like this:
  • Top row: \(c^{+}\), \(c^{\mathrm{ch}}\)
  • Side row: \(c^{\mathrm{ch}}\), \(c^{\mathrm{h}}\)
Combining these alleles in the square, you can see all possible genotypes, revealing that offspring can be agouti, chinchilla, or Himalayan, based on the combination of alleles received. This simple tool is invaluable in predicting and understanding genetic inheritance.

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Most popular questions from this chapter

The petals of the plant Collinsia parviflora are normally blue, giving the species its common name, blue-eyed Mary. Two pure-breeding lines were obtained from color variants found in nature; the first line had pink petals, and the second line had white petals. The following crosses were made between pure lines, with the results shown: $$\begin{array}{ccl} \text { Parents } & \mathrm{F}_{1} & \mathrm{F}_{2} \\ \hline \text { blue } \times \text { white } & \text { blue } & 101 \text { blue, } 33 \text { white } \\ \text { blue } \times \text { pink } & \text { blue } & 192 \text { blue, } 63 \text { pink } \\ \text { pink } \times \text { white } & \text { blue } & 272 \text { blue, } 121 \text { white }, 89 \text { pink } \\ \hline \end{array}$$ a. Explain these results genetically. Define the allele symbols that you use, and show the genetic constitution of the parents, the \(\mathrm{F}_{1},\) and the \(\mathrm{F}_{2}\) in each cross. b. \(A\) cross between a certain blue \(F_{2}\) plant and a certain white \(\mathrm{F}_{2}\) plant gave progeny of which \(\frac{3}{8}\) were blue, \(\frac{1}{8}\) were pink, and \(\frac{1}{2}\) were white. What must the genotypes of these two \(\mathrm{F}_{2}\) plants have been?

After irradiating wild-type cells of Neurospora (a haploid fungus), a geneticist finds two leucine-requiring auxotrophic mutants. He combines the two mutants in a heterokaryon and discovers that the heterokaryon is prototrophic. a. Were the mutations in the two auxotrophs in the same gene in the pathway for synthesizing leucine or in two different genes in that pathway? Explain. b. Write the genotype of the two strains according to your model. c. What progeny and in what proportions would you predict from crossing the two auxotrophic mutants? (Assume independent assortment.)

In common wheat, Triticum aestivum, kernel color is determined by multiply duplicated genes, each with an \(R\) and an \(r\) allele. Any number of \(R\) alleles will give red, and a complete lack of \(R\) alleles will give the white phenotype. In one cross between a red pure line and a white pure line, the \(\mathrm{F}_{2}\) was \(\frac{63}{64}\) red and \(\frac{1}{64}\) white. a. How many R genes are segregating in this system? b. Show the genotypes of the parents, the \(\mathrm{F}_{1}\), and the \(\mathrm{F}_{2}\). c. Different \(F_{2}\) plants are backcrossed with the white parent. Give examples of genotypes that would give the following progeny ratios in such backcrosses: (1) 1 red: 1 white (2) 3 red : 1 white, (3) 7 red : 1 white. d. What is the formula that generally relates the number of segregating genes to the proportion of red individuals in the \(\mathrm{F}_{2}\) in such systems?

A woman who owned a purebred albino poodle (an autosomal recessive phenotype) wanted white puppies; so she took the dog to a breeder, who said he would mate the female with an albino stud male, also from a pure stock. When six puppies were born, all of them were black; so the woman sued the breeder, claiming that he replaced the stud male with a black dog, giving her six unwanted puppies. You are called in as an expert witness, and the defense asks you if it is possible to produce black offspring from two pure-breeding recessive albino parents. What testimony do you give?

The production of pigment in the outer layer of seeds of corn requires each of the three independently assorting genes \(A, C,\) and \(R\) to be represented by at least one dominant allele, as specified in Problem \(64 .\) The dominant allele \(P r\) of a fourth independently assorting gene is required to convert the biochemical precursor into a purple pigment, and its recessive allele \(p r\) makes the pigment red. Plants that do not produce pigment have yellow seeds. Consider a cross of a strain of genotype \(A / A ; C / C ; R / R ; p r / p r\) with a strain of genotype \(a / a ; c / c ; r / r ; \operatorname{Pr} / \operatorname{Pr}\) a. What are the phenotypes of the parents? b. What will be the phenotype of the \(\mathrm{F}_{1}\) ? c. What phenotypes, and in what proportions, will appear in the progeny of a selfed \(\mathrm{F}_{1}\) ? d. What progeny proportions do you predict from the testcross of an \(\mathrm{F}_{1}\) ?

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