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In polygenic systems, how many phenotypic classes corresponding to number of polygene "doses" are expected in selfs a. of strains with four heterozygous polygenes? b. of strains with six heterozygous polygenes?

Short Answer

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a. 9 phenotypic classes; b. 13 phenotypic classes.

Step by step solution

01

Understanding Polygenic Inheritance

In polygenic systems, multiple genes (polygenes) contribute to a single trait. Each gene can have two alleles, providing 'doses' of the contributing allele. Heterozygous genes have one allele each of the two forms (e.g., Aa), contributing one dose per allele.
02

Formula for Calculating Phenotypic Classes

The number of phenotypic classes in a polygenic self cross is calculated by using the formula: \( 2n + 1 \), where \( n \) is the number of heterozygous polygenes. Each class represents a distinct number of doses.
03

Apply Formula to Four Heterozygous Polygenes

For four heterozygous polygenes, set \( n = 4 \). Using the formula \( 2n + 1 \), substitute \( n \) to get the number of phenotypic classes: \( 2(4) + 1 = 9 \). Thus, there are 9 phenotypic classes.
04

Apply Formula to Six Heterozygous Polygenes

For six heterozygous polygenes, set \( n = 6 \). Using the formula \( 2n + 1 \), substitute \( n \) to find the number of phenotypic classes: \( 2(6) + 1 = 13 \). Thus, there are 13 phenotypic classes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phenotypic Classes
In polygenic inheritance, the term 'phenotypic classes' refers to the different observable traits that result from the combination of various polygenes.
Unlike traits controlled by a single gene, polygenic traits often show a range of variations.
Each small variation or class is called a phenotypic class. The number of phenotypic classes can be calculated using the formula \(2n + 1\), where \(n\) is the number of heterozygous polygenes.
This formula is a representation of all the possible combinations of gene doses that can be contributed by each allele.
  • A higher number of phenotypic classes means more subtle variations can be observed, creating a smooth gradient rather than distinct categories.
  • For example, with four heterozygous polygenes, there are nine phenotypic classes, while six heterozygous polygenes result in thirteen classes.
This wide range is what provides the continuous variation of characteristics such as height, skin color, and eye color in humans.
Heterozygous Polygenes
Polygenes are genes that collectively contribute to a single trait, and when we refer to heterozygous polygenes, we mean those that have two different alleles.
For instance, in a genetic notation, this might appear as \(Aa\), where one allele is dominant and the other is recessive.
Heterozygous polygenes play a pivotal role in determining the number of phenotypic classes.
  • Each heterozygous polygene provides one 'dose' of the trait value, thus contributing to the overall phenotypic expression.
  • Multiple heterozygous polygenes can combine to produce a wide range of phenotypic outcomes as each contributes incrementally to the trait manifestation.
The aggregation of these different doses from multiple heterozygous polygenes determines the breadth of possible traits.
Genetic Traits
Genetic traits are characteristics that an organism can pass on to its offspring through its genes. In polygenic inheritance, these traits are determined by multiple genes.
These traits exhibit continuous variation, meaning individuals can show a range of phenotypical expressions partially due to the different combinations of alleles they possess.
This is where the blend of multiple genes, or polygenic inheritance, leads to genetic traits that are incredibly variable.
  • Traits such as human height, skin color, and hair color are influenced by polygenic inheritance, which involves the accumulation of small effects from multiple genes.
  • Unlike single-gene traits that fall into clear-cut categories, polygenic traits display a range of manifestations, contributing to the diversity observed within a population.
Understanding these traits helps us to explain and predict the differences and similarities we observe in living organisms.

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Most popular questions from this chapter

It has been shown that when a thin beam of light is aimed at a nucleus, the amount of light absorbed is proportional to the cell's DNA content. Using this method, the DNA in the nuclei of several different types of cells in a corn plant were compared. The following numbers represent the relative amounts of DNA in these different types of cells: \\[ 0.7,1.4,2.1,2.8, \text { and } 4.2 \\] Which cells could have been used for these measurements? (Note: In plants, the endosperm part of the seed is often triploid, \(3 n .\) )

When a cell of genotype \(A / a ; B / b ; C / c\) having all the genes on separate chromosome pairs divides mitotically, what are the genotypes of the daughter cells?

In a natural population of annual plants, a single plant is found that is sickly looking and has yellowish leaves. The plant is dug up and brought back to the laboratory. Photosynthesis rates are found to be very low. Pollen from a normal darks green-leaved plant is used to fertilize emasculated flowers of the yellowish plant. A hundred seeds result, of which only 60 germinate. All the resulting plants are sickly yellow in appearance. a. Propose a genetic explanation for the inheritance pattern. b. Suggest a simple test for your model. c. Account for the reduced photosynthesis, sickliness, and yellowish appearance.

A presumed dihybrid in Drasophila, \(B / b ; F / f,\) is testcrossed with \(b / b ; f / f\). \((B=\text { black body } ; b=\) brown body \(F=\text { forked bristles } f=\text { unforked bristles. })\) The results are black, forked \(230 \quad\) brown, forked \(\quad 240\) black, unforked \(210 \quad\) brown, unforked 250 Use the \(x^{2}\) test to determine if these results fit the results expected from testcrossing the hypothesized dihybrid.

From a presumed testcross \(A / a \times a / a,\) in which \(A\) represents red and \(a\) represents white, use the \(x^{2}\) test to find out which of the following possible results would fit the expectations: a. 120 red, 100 white b. 5000 red, 5400 white c. 500 red, 540 white d. 50 red, 54 white

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