/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Mice of the genotypes \(A / A ; ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Mice of the genotypes \(A / A ; B / B ; C / C ; D / D ; S / S\) and \(a / a ; b / b ; c / c ; d / d ; s / s\) are crossed. The progeny are intercrossed. What phenotypes will be produced in the \(\mathrm{F}_{2}\) and in what proportions? (The allele symbols stand for the following: \(A=\) agouti, \(a=\) solid (nonagouti) \(; B\) \(=\) black pigment, \(b=\) brown; \(C=\) pigmented, \(c=\) albino; \(D=\) nondilution, \(d=\) dilution (milky color); \(S=\) unspotted, \(s=\) pigmented spots on white background.)

Short Answer

Expert verified
The F2 generation will show a variety of phenotypic combinations, primarily following independent assortment laws. Expected phenotype ratios are complex, around 81/256 agouti, black, pigmented, nondiluted, unspotted.

Step by step solution

01

Determine Genotypes of F1 Generation

When the mice of genotypes \(A / A ; B / B ; C / C ; D / D ; S / S\) are crossed with \(a / a ; b / b ; c / c ; d / d ; s / s\), all the progeny in the \(F_1\) generation will be heterozygous for each gene. Thus, the \(F_1\) generation will have the genotype \(A / a ; B / b ; C / c ; D / d ; S / s\).
02

Evaluate Phenotypic Expression

Each allele pair exhibits complete dominance, so the phenotype expressed in \(F_1\) will be the dominant trait for each pair: Agouti (\(A\)), Black pigment (\(B\)), Pigmented (\(C\)), Non-diluted (\(D\)), and Unspotted (\(S\)).
03

Determine F2 Genotypes and Phenotypes

In the \(F_2\) generation, each allele pair segregates independently, producing a variety of combinations. The phenotypic expression for each trait depends on the following: - **A or a:** Agouti or solid with a 3:1 ratio, Agouti:Solid. - **B or b:** Black or brown pigment with a 3:1 ratio, Black:Brown. - **C or c:** Pigmented or albino with a 3:1 ratio, Pigmented:Albino. - **D or d:** Non-diluted or diluted with a 3:1 ratio, Nondilution:Dilution. - **S or s:** Unspotted or spotted with a 3:1 ratio, Unspotted:Spotted.
04

Calculate Combined Phenotypic Ratios

Since each trait segregates independently, we can multiply the proportion of each trait's phenotype to determine the proportion of each combined phenotype. Therefore, only individual phenotypes allocated to the offspring that results in a nonzero part of a 1/16 combine into a final fraction. Thus, the expected proportion of offspring phenotype to be agouti, black, pigmented, nondiluted, unspotted will be \( 9/256 \) per combination. Other possible combinations follow similar fraction calculations.
05

Calculate Specific Fractions by Traits

To find aggregate numbers, the ratio for each trait is multiplied together for four desired trait categories. Overall, taking into account the dominance across pigment, dilution and spotting, some offspring will be albino \(9:3:3:1\). Consistently intercrossing a second generation yields 3 Agouti, Brown/Black, Pigmented/Unpigmented and Dd/dD Nondiluted/Spotted, similar by odds any phenotype consistent fractions, culminating in an extreme frequency ratios.
06

Sum All Possible Phenotypic Outcomes

Sum all possible phenotypic outcomes to calculate the full range. Calculate aggregate values for repeated traits leading to selected total combinations allocated with notable: agouti, black, pigmented, nondiluted, unspotted or swapped for any achieved aesthetic. This resultant proportion counts 81 in 256 or the subsequent figure of larger equation for accounting total gamut.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Genotype
In genetics, a "genotype" refers to the genetic makeup of an organism, specifically the combination of alleles, which code for a particular trait. In our exercise, the purebred parent mice have genotypes like \(A/A\) indicating they have two agouti alleles. When these parent mice are crossed, the offspring (\(F_1\) generation) will be heterozygous, meaning they possess one allele from each parent for every gene, such as \(A/a\).
This concept is crucial in understanding inheritance, as it is the combination of alleles that influence how a trait is expressed in the phenotype. The genotype, \(A/a ; B/b ; C/c ; D/d ; S/s\), in the \(F_1\) generation represents this hybrid vigor, containing one dominant and one recessive allele for each trait, which paves the way for diverse expressions in the \(F_2\) generation.
Phenotype
"Phenotype" refers to the observable characteristics of an organism, which result from the expression of the genotype in a given environment. In simpler terms, phenotype is what you see. For instance, a mouse with the genotype \(A/a\) will exhibit the "agouti" fur pattern, as the "A" allele is dominant over the "a" allele, resulting in the agouti phenotype.
In the \(F_1\) generation, all mice exhibit the dominant phenotypes due to the presence of at least one dominant allele from the parent genes. Therefore, the visible traits in these mice are agouti, black pigment, pigmented, non-diluted color, and unspotted fur. The phenotype is a direct reflection of the genotype masked by dominance, demonstrating how alleles interact to create the observable traits of an organism.
Independent Assortment
The concept of "independent assortment" originates from Mendel's laws of inheritance. It explains how different genes independently separate from one another when reproductive cells develop. This principle means that the distribution of alleles for one trait does not affect the distribution of alleles for another.
For example, in the \(F_2\) generation, the alleles for agouti fur ( \(A/a\)) will segregate independently from those for pigment color ( \(B/b\)), and the same applies to the remaining traits. Thus, the possible combinations of genotypes in the \(F_2\) generation are produced from the random assortment of these allele pairs. This process results in a wide variety of genetic combinations, which contribute to the diversity seen in phenotypic traits of offspring.
Genetic Ratios
Genetic ratios are a way of predicting the likelihood of different genotypes and phenotypes in offspring. They represent the probability of the different possible outcomes.
In our mouse exercise, genetic ratios manifest in outcomes like the classic \(3:1\) ratio for dominant to recessive traits, observed in traits such as agouti versus solid fur. When combining all traits assuming independent assortment, these ratios combine multiplicatively. This leads to more complex ratios such as \(9:3:3:1\) when two traits are considered at once.
  • For single traits, each allele pair follows a Mendelian \(3:1\) ratio due to dominant/recessive dynamics.
  • When calculating combined phenotypes across multiple traits, multiplying these ratios provides the proportions of resulting combinations like 81/256 for certain composite phenotypes.
This method allows geneticists to forecast the distribution of traits in large populations, providing a clear framework to understand genetic outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If a man of blood-group AB marries a woman of bloodgroup A whose father was of blood-group \(\mathrm{O}\), to what different blood groups can this man and woman expect their children to belong?

A plant of phenotype 1 was selfed, and, in the progeny, there were 100 plants of phenotype 1 and 60 plants of an alternative phenotype \(2 .\) Are these numbers compatible with expected ratios of 9: 7,\(13: 3,\) and \(3: 1 ?\) Formulate a genetic hypothesis on the basis of your calculations.

An al-lele \(A\) that is not lethal when homozygous causes rats to have yellow coats. The allele \(R\) of a separate gene that assorts independently produces a black coat. Together, \(A\) and \(R\) produce a grayish coat, whereas \(a\) and \(r\) produce a white coat. A gray male is crossed with a yellow female, and the \(\mathrm{F}_{1}\) is \(\frac{3}{8}\) yellow, \(\frac{3}{8}\) gray, \(\frac{1}{8}\) black, and \(\frac{1}{8}\) white. Determine the genotypes of the parents.

The production of eye-color pigment in Drosophila requires the dominant allele \(A\). The dominant allele \(P\) of a second independent gene turns the pigment to purple, but its recessive allele leaves it red. A fly producing no pigment has white eyes. Two pure lines were crossed with the following results: \(\mathrm{P} \quad\) red-eyed female \(\times\) white-eyed male \\[ 1 \\] \(\mathrm{F}_{1}\) purple-eyed females red-eyed males \\[ \mathrm{F}_{1} \times \mathrm{F}_{1} \\] \(\mathrm{F}_{2} \quad\) both males and females: \(\frac{3}{8}\) purple eyed \(\frac{3}{8}\) red eyed \(\frac{2}{8}\) white eyed Explain this mode of inheritance and show the genotypes of the parents, the \(\mathrm{F}_{1},\) and the \(\mathrm{F}_{2}\).

In corn, three dominant alleles, called \(A, C,\) and \(R\) must be present to produce colored seeds. Genotype \(A /-; C /-; R /-\) is colored; all others are colorless. A colored plant is crossed with three tester plants of known genotype. With tester \(a / a ; c / c ; R / R,\) the colored plant produces 50 percent colored seeds; with \(a / a ; C / C ; r / r,\) it produces 25 percent colored; and with \(A / A ; c / c ; r / r,\) it produces 50 percent colored. What is the genotype of the colored plant?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.