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When true-breeding brown dogs are mated with certain true-breeding white dogs, all the \(F_{1}\) pups are white. The \(\mathrm{F}_{2}\) progeny from some \(\mathrm{F}_{1} \times \mathrm{F}_{1}\) crosses were 118 white, 32 black, and 10 brown pups. What is the genetic basis for these results?

Short Answer

Expert verified
Epistasis, where the white (W) gene is dominant and masks brown (b) and black interactions.

Step by step solution

01

Understand True-Breeding

True-breeding means that the organism, when self-crossed or crossed with an identical type, produces offspring identical to the parent. In genetics, a true-breeding organism is homozygous for the trait in question.
02

Analyze F1 Generation

When true-breeding brown dogs are mated with true-breeding white dogs and all the F1 offspring are white, it suggests that white is the dominant trait. Thus, the white dogs can be represented as WW (homozygous dominant) and brown as bb (homozygous recessive). The F1 generation would be Wb (heterozygous), showing the dominant white trait.
03

Examine F2 Generation

The F2 progeny result from F1 generation (Wb) crossed with itself. The progeny distribution is 118 white, 32 black, and 10 brown pups, which suggests multiple alleles being involved and possible epistasis affecting the phenotypic expression.
04

Identify Possible Genetic Model

One model might include incomplete dominance or another modifier allele. However, the predominant result (118 white pups) supports a model where white either masks the other colors due to dominance or additional allelic interactions.
05

Determine Genetic Ratios

Use a Punnett Square for a dihybrid cross. Consider interacting genes where W- is white, B- is black, and bb with no W gene appears as brown. The expected F2 ratios might stem from a 9:3:4 epistatic ratio which matches 118:32:10 relatively closely after scaling.
06

Conclude with Genetic Basis

It appears that epistasis is at play, where the white gene (W) dominates, regardless of the other color genes unless it is absent. Black shows up as an interaction between the potential second allele (B) and brown (b), but only one allele of W is needed to mask both.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Epistasis
Epistasis is a fascinating genetic phenomenon that occurs when the effect of one gene is dependent on the presence of one or more 'modifier genes'. Unlike simple Mendelian inheritance, where each trait is determined by a pair of alleles—one from each parent—epistasis happens when different genes influence the outcome of a single trait.

In the context of our dog scenario, white was the dominant trait masking other colors, suggesting epistasis. The allele for white (W) may be epistatic, meaning it overrides or alters the expression of alleles that would otherwise give black (B) or brown (b) fur.

Understanding epistasis helps explain why we see unexpected ratios in offspring. While traditional Mendelian genetics might predict a straightforward inheritance pattern, epistasis adds complexity and leads to phenotypic outcomes that deviate from simple expectations.
Dominant and Recessive Traits
Dominant and recessive traits are fundamental concepts in genetics that determine the characteristics expressed in an organism. A dominant trait is one where only one allele is needed for it to be apparent in the organism's phenotype.

In contrast, a recessive trait requires two copies of the same allele for its characteristics to be visible. This is true in our example, where the white color (W) is dominant, while black and brown are influenced by recessive interactions.

In the mating of true-breeding white (WW) and brown (bb) dogs, the dominance of the white allele is evident in the F1 generation, where all dogs appeared white. Thus, the presence of the dominant white trait in F1 masks other potential colorations.
  • The white fur trait is phenotypically apparent even if one white allele is present.
  • Recessive traits like brown only appear when the dominant allele is not present.
Dominance and recessiveness are key to understanding how certain traits are passed and expressed through generations.
Dihybrid Cross
A dihybrid cross is a tool used by geneticists to predict the genotypic and phenotypic outcomes of offspring for traits determined by two different genes. In dihybrid crosses, the focus is on looking at two contrasting traits at the same time.

In our dog example, a dihybrid cross helps explain the 118 white, 32 black, and 10 brown pups observed in the F2 generation. The white (W) gene appears to be epistatic, but considering the presence of black and brown dogs indicates a second locus influencing color.
  • The hypothetical alleles here could be W (white), B (black), and b (brown).
  • The dihybrid cross of Wb x Wb predicts outcomes and provides insight through a 9:3:4 ratio, indicative of epistatic interaction.
By employing a dihybrid cross, the complexity of interacting genes and their outcomes become more predictable, despite the intricate nature of epistasis and multi-gene interactions. This approach can reveal genetic patterns across generations and predict possible variants in offspring.

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Most popular questions from this chapter

In a maternity ward, four babies become accidentally mixed up. The ABO types of the four babies are known to be \(\mathrm{O}, \mathrm{A}, \mathrm{B},\) and \(\mathrm{AB}\). The \(\mathrm{ABO}\) types of the four sets of parents are determined. Indicate which baby belongs to each set of parents: (a) \(A B \times O,(b) A \times O,(c) A x\) \(\mathrm{AB},(\mathrm{d}) \mathrm{O} \times \mathrm{O}\).

The production of pigment in the outer layer of seeds of corn requires each of the three independently assorting genes \(A, C,\) and \(R\) to be represented by at least one dominant allele, as specified in Problem \(64 .\) The dominant allele \(P r\) of a fourth independently assorting gene is required to convert the biochemical precursor into a purple pigment, and its recessive allele \(p r\) makes the pigment red. Plants that do not produce pigment have yellow seeds. Consider a cross of a strain of genotype \(A / A ; C / C ; R / R ; p r / p r\) with a strain of genotype \(a / a ; c / c ; r / r ; P r / P r\). a. What are the phenotypes of the parents? b. What will be the phenotype of the \(\mathrm{F}_{1}\) ? c. What phenotypes, and in what proportions, will appear in the progeny of a selfed \(\mathrm{F}_{1}\) ? d. What progeny proportions do you predict from the testcross of an \(\mathrm{F}_{1}\) ?

A plant of phenotype 1 was selfed, and, in the progeny, there were 100 plants of phenotype 1 and 60 plants of an alternative phenotype \(2 .\) Are these numbers compatible with expected ratios of 9: 7,\(13: 3,\) and \(3: 1 ?\) Formulate a genetic hypothesis on the basis of your calculations.

Wild-type strains of the haploid fungus Neurospora can make their own tryptophan. An abnormal allele \(t d\) renders the fungus incapable of making its own tryptophan. An individual of genotype \(t d\) grows only when its medium supplies tryptophan. The allele su assorts independently of \(t d ;\) its only known effect is to suppress the \(t d\) phenotype. Therefore, strains carrying both \(t d\) and su do not require tryptophan for growth. a. If a \(t d ; s u\) strain is crossed with a genotypically wild-type strain, what genotypes are expected in the progeny and in what proportions? b. What will be the ratio of tryptophan-dependent to tryptophan-independent progeny in the cross of part \(a\) ?

In the multiple-allele series that determines coat color in rabbits, \(c^{+}\) encodes agouti, \(c^{\mathrm{ch}}\) encodes chinchilla (a beige coat color), and \(c^{\mathrm{h}}\) encodes Himalayan. Dominance is in the order \(c^{+}>c^{c h}>c^{h} .\) In a cross of \(c^{+} / c^{c h} \times\) \(c^{\mathrm{ch}} / c^{\mathrm{h}},\) what proportion of progeny will be chinchilla?

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