/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 A female animal with genotype \(... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A female animal with genotype \(A / a \cdot B / b\) is crossed with a double- recessive male \((a / a \cdot b / b) .\) Their progeny include 442 A/a \(\cdot B / b, 458 a / a \cdot b / b, 46 A / a \cdot b / b,\) and 54 \(a / a \cdot B / b .\) Explain these results.

Short Answer

Expert verified
The progeny results suggest linkage between loci A and B, causing more parental-type offspring due to lower recombination frequency.

Step by step solution

01

Understanding the Parent Genotypes and Cross

In this cross, we have a heterozygous female with genotype \(A/a \cdot B/b\) and a double-recessive male with genotype \(a/a \cdot b/b\). The objective is to determine how these parental genotypes lead to the observed progeny ratios.
02

Determine Possible Gametes

The female can produce four types of gametes: \(A/B\), \(A/b\), \(a/B\), and \(a/b\). The male, being homozygous recessive, produces only one type of gamete: \(a/b\).
03

Calculate Expected Progeny Ratios Under Independent Assortment

Under independent assortment, the four gametes from the female should combine with the single male gamete with equal probability, resulting in equal numbers of the four progeny genotypes: \(A/a \cdot B/b\), \(A/a \cdot b/b\), \(a/a \cdot B/b\), and \(a/a \cdot b/b\). However, the observed ratios are not equal, suggesting some other genetic phenomenon is at play.
04

Analyze the Observed Progeny Ratios

The progeny counts are as follows: 442 \(A/a \cdot B/b\), 458 \(a/a \cdot b/b\), 46 \(A/a \cdot b/b\), and 54 \(a/a \cdot B/b\). The significantly higher numbers of \(A/a \cdot B/b\) and \(a/a \cdot b/b\) compared to \(A/a \cdot b/b\) and \(a/a \cdot B/b\) indicate that the alleles are linked, and the dominant configuration \(A-B\) and \(a-b\) are passing together more frequently.
05

Identify Genetic Linkage and Recombination

The significant excess of the parental types \(A/a \cdot B/b\) and \(a/a \cdot b/b\) over the recombinant types \(A/a \cdot b/b\) and \(a/a \cdot B/b\) suggests that the loci are linked and close together on the same chromosome, resulting in fewer recombinants due to a lower recombination frequency.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recombination Frequency
Recombination frequency is a term used to describe how often two genes will recombine, or cross over, during the formation of gametes. In the given exercise, we observe different proportions of progeny genotypes which hint at low recombination between the genes in question. This is evident from the larger numbers of parental phenotypes compared to recombinant types.

The recombination frequency (\( r \)) is calculated by dividing the number of recombinant progeny by the total number of progeny. In this exercise, the recombinant progeny types are \( A/a \cdot b/b \) and \( a/a \cdot B/b \) with totals of 46 and 54, respectively, making a combined total of 100 recombinants out of 1000 total progeny. Therefore, the recombination frequency is calculated as:
  • \( r = \frac{46 + 54}{1000} = 0.1 \) or 10%.
This low recombination frequency indicates that the genes are likely linked and reside close to each other on the same chromosome. The closer two genes are physically, the less likely they are to be separated by crossing over during meiosis.
Progeny Ratios
The progeny ratios refer to the distribution of different genetic types that result from a genetic cross. In this exercise, the progeny does not appear in expected Mendelian ratios because the alleles are linked.

Under normal conditions without linkage, we'd expect to see equal numbers of all genotypic combinations if the genes assorted independently. Yet, we observe 442 \( A/a \cdot B/b \) and 458 \( a/a \cdot b/b \), which suggests these are parental types appearing more frequently than the recombinant types, \( A/a \cdot b/b \) (46) and \( a/a \cdot B/b \) (54).

This asymmetric distribution in progeny ratios signals linkage in genetic loci. In these circumstances, some combinations of alleles are inherited together more often than others due to their physical proximity on a chromosome.
Independent Assortment
Independent assortment is a fundamental principle of genetics that Gregor Mendel described, stating that the alleles of different genes get distributed into gametes independently. This means that the inheritance of one trait generally does not affect the inheritance of another, assuming the traits are controlled by genes on different chromosomes or far apart on the same chromosome.

In an ideal scenario without linkage, the four different types of progeny from a dihybrid cross like \( A/a \cdot B/b \) should appear in a 1:1:1:1 ratio. However, in this exercise, the assumption of independent assortment does not hold due to genetic linkage. Instead of equal numbers, we find substantial evidence of linkage due to the non-random distribution of the progeny genotypes. Parental types \( A/a \cdot B/b \) and \( a/a \cdot b/b \) occur significantly more frequently than expected under independent assortment.

This deviation provides evidence that the genes involved are linked, which means they are located near each other on the same chromosome, reducing the probability of being separated by recombination during meiosis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A rice breeder obtained a triple heterozygote carrying the three recessive alleles for albino flowers \((a l),\) brown awns \((b),\) and fuzzy leaves \((f u),\) all paired with their normal wild-type alleles. This triple heterozygote was testcrossed. The progeny phenotypes were \(170 \quad\) wild type \(150 \quad\) albino, brown, fuzzy \(5 \quad\) brown 3 albino, fuzzy \(710 \quad\) albino \(698 \quad\) brown, fuzzy \(42 \quad\) fuzzy \(38 \quad\) albino, brown a. Are any of the genes linked? If so, draw a map labeled with map distances. (Don't bother with a correction for multiple crossovers.) b. The triple heterozygote was originally made by crossing two pure lines. What were their genotypes?

A plant of genotype $$\begin{array}{cc}A & B \\\\\hline \hline a & b\end{array}$$ is testcrossed with $$\begin{array}{cc}a & b \\\\\hline \hline a & b\end{array}$$ If the two loci are \(10 \mathrm{m}\). \(u\). apart, what proportion of progeny will be \(A B / a b ?\)

The \(A\) locus and the \(D\) locus are so tightly linked that no recombination is ever observed between them. If \(A d / A d\) is crossed with \(a D / a D\) and the \(F_{1}\) is intercrossed, what phenotypes will be seen in the \(\mathrm{F}_{2}\) and in what proportions?

In a haploid organism, the \(C\) and \(D\) loci are 8 m.u. apart. From a cross \(C d \times c D,\) give the proportion of each of the following progeny classes: (a) \(C D ;\) (b) \(c d ;(\mathbf{c}) C d\) (d) all recombinants.

In a tetrad analysis, the linkage arrangement of the \(p\) and \(q\) loci is as follows: Assume that in region i, there is no crossover in 88 percent of meioses and there is a single crossover in 12 percent of meioses; in region ii, there is no crossover in 80 percent of meioses and there is a single crossover in 20 percent of meioses; and there is no interference (in other words, the situation in one region does not affect what is going on in the other region) What proportions of tetrads will be of the following types? (a) \(\mathrm{M}_{\mathrm{f}} \mathrm{M}_{\mathrm{I}}, \mathrm{PD}\) \((\mathbf{b}) \mathrm{M}_{1} \mathrm{M}_{\mathrm{l}}, \mathrm{NPD}\) \((\mathbf{c}) M_{1} M_{11}, T ;\) (d) \(\mathrm{M}_{\mathrm{D}} \mathrm{M}_{\mathrm{l}}, \mathrm{T}\) \((\mathbf{e}) M_{1} M_{\Perp}, P D\) \((\mathbf{f}) M_{11} M_{11}, N P D ;\) (g) \(\mathrm{M}_{\mathrm{II}} \mathrm{M}_{\mathrm{U}}\), T. (Note: Here the M pattern written first is the one that pertains to the \(p\) locus.) Hint: The easiest way to do this problem is to start by calculating the frequencies of asci with crossovers in both regions, region i, region ii, and neither region. Then determine what \(\mathrm{M}_{1}\) and \(\mathrm{M}_{\mathrm{II}}\) patterns result.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.