/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 If a eukaryotic chromosome has 2... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 11: Problem 24

If a eukaryotic chromosome has 25 origins of replication, how many replication forks does it have at the beginning of DNA replication?

Short Answer

Expert verified
The eukaryotic chromosome has 50 replication forks at the beginning of DNA replication.

Step by step solution

01

Understand Origins of Replication

An origin of replication is a particular sequence in a genome at which replication is initiated. In the eukaryotic chromosome, each origin of replication forms a bubble and replication occurs in both directions using both strands of the DNA.
02

Understand Replication Forks

In each replication bubble, there are two ends where the DNA is being unwound. These are called replication forks. Each origin of replication has two replication forks.
03

Calculate the number of Replication Forks

Since each origin of replication has two replication forks, to find the total number of forks we multiply the number of origins by two. Given 25 origins of replication, \[ 25 \text{ origins} \times 2 \text{ forks/origin} = 50 \text{ forks} \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Single-strand binding proteins keep the two parental strands of DNA separated from each other until DNA polymerase has an opportunity to replicate the strands. Suggest how single-strand binding proteins keep the strands separated and yet do not impede the ability of DNA polymerase to replicate the strands.

C1. What key structural features of the DNA molecule underlie its ability to be faithfully replicated?

The compound known as nitrous acid is a reactive chemical that replaces amino groups \(\left(-\mathrm{NH}_{2}\right)\) with keto groups \((=\mathrm{O})\). When nitrous acid reacts with the bases in DNA, it can change cytosine to uracil and change adenine to hypoxanthine. A DNA double helix has the following sequence: TTGGATGCTGG AACCTACGACC A. What would be the sequence of this double helix immediately after reaction with nitrous acid? Let the letter \(\mathrm{H}\) represent hypoxanthine and \(U\) represent uracil. B. Let's suppose this DNA was treated with nitrous acid. The nitrous acid was then removed, and the DNA was replicated for two generations. What would be the sequences of the DNA products after the DNA had replicated twice? Your answer should contain the sequences of four double helices. Note: During DNA replication, uracil hydrogen bonds with adenine, and hypoxanthine hydrogen bonds with cytosine.

In eukaryotes, what is meant by the term DNA replication licensing? How does the process occur?

Discuss the similarities and differences in the synthesis of DNA in the lagging and leading strands. What is the advantage of a primosome and a replisome as opposed to having all replication enzymes functioning independently of each other?
See all solutions

Recommended explanations on Biology Textbooks

Communicable Diseases

Read Explanation

Heredity

Read Explanation

Biological Structures

Read Explanation

Cellular Energetics

Read Explanation

Plant Biology

Read Explanation

Chemistry of Life

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.