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A strawberry farmer determines that the average weight of individual strawberries produced by plants in his garden is 2 g. He selects the 10 plants that produce the largest strawberries; the average weight of strawberries produced by these selected plants is 6 g. He interbreeds these selected plants. The progeny of these selected plants produce strawberries that weigh an average of 5 g. If the farmer were to select plants that produce strawberries with an average weight of \(4 \mathrm{~g}\), what would be the predicted weight of strawberries produced by the progeny of those selected plants?

Short Answer

Expert verified
The predicted weight of the progeny is 3.5 g.

Step by step solution

01

Understanding the Breeder's Equation

The farmer is using selective breeding to increase the average weight of strawberries. We can use the breeder's equation, which calculates the response to selection based on heritability, to predict the next generation's trait value. The formula is:\[ R = h^2 imes S \]where \( R \) is the response to selection, \( S \) is the selection differential, and \( h^2 \) is the heritability of the trait.
02

Calculating Selection Differential \( S \)

The selection differential \( S \) is the difference between the mean trait value of the selected parents and the population mean. Initially, the population mean is 2 g and the selected plants produce strawberries weighing 6 g.\[ S = 6 ext{ g} - 2 ext{ g} = 4 ext{ g} \]
03

Calculating Response to Selection \( R \)

The response to selection \( R \) can be calculated using the change in the average weight of strawberries from the parental generation (6 g) to the progeny (5 g).\[ R = 5 ext{ g} - 2 ext{ g} = 3 ext{ g} \]
04

Estimating Heritability \( h^2 \)

Using the breeder's equation, solve for heritability \( h^2 \).\[ h^2 = \frac{R}{S} = \frac{3 ext{ g}}{4 ext{ g}} = 0.75\]This means 75% of the phenotypic variation in strawberry weight is due to genetic factors under selection.
05

Predicted Response for New Selection

Now calculate the response for selecting plants with 4g average strawberry weight.\[ S_{new} = 4 ext{ g} - 2 ext{ g} = 2 ext{ g} \]
06

Predicting Progeny Weight

Use heritability estimated earlier to calculate the response:\[ R_{new} = h^2 \times S_{new} = 0.75 \times 2 ext{ g} = 1.5 ext{ g} \]Add this response to the original population mean to find the predicted progeny weight:\[ ext{Predicted weight} = 2 ext{ g} + 1.5 ext{ g} = 3.5 ext{ g} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trait Heritability
Trait heritability is a key concept in understanding how a particular trait can be passed from one generation to the next. It is a measure of how well differences in people's genes account for differences in their traits. In the context of selective breeding, heritability (\(h^2\)) is a crucial factor that influences the success of breeding for a desired characteristic, such as larger strawberries.
Heritability is expressed as a fraction between 0 and 1. A high heritability close to 1 means that most of the variation in a trait is due to genetic factors, while a lower heritability close to 0 suggests that environmental factors have a larger influence. In the example of strawberries, a heritability of 0.75 tells us that 75% of the variations in strawberry weight in our farmer's garden are attributable to genetics, leaving 25% to environmental variations.
For successful selective breeding, understanding and estimating heritability allows farmers or breeders to predict how well traits can be passed from parents to offspring. Knowing this can help them make more informed decisions about which plants or animals to select for breeding.
Breeder's Equation
The breeder's equation is an essential tool used to predict the outcome of selective breeding. It helps in estimating the potential improvement or change in a trait due to selection. The breeder's equation is given by:\[ R = h^2 \times S \]Here, \(R\) represents the response to selection, which is the change in the trait value in the next generation, \(h^2\) is the heritability of the trait, and \(S\) is the selection differential.
In our strawberry example, the farmer wishes to increase the average strawberry weight through selective breeding. By applying the breeder's equation, we can calculate the expected weight of strawberries in the next generation. Given the heritability of 0.75 and the selection differential of 4 g in the initial choice, the equation estimates that the response to selection \(R\) would be 3 g. This means the offspring will, on average, weigh 3 g more than the original population's mean.
Using the breeder's equation, breeders can anticipate the genetic gain they can achieve and evaluate the effectiveness of their selection strategies. It is a cornerstone concept for those interested in genetics and selective breeding.
Selection Differential
The selection differential (\(S\)) is a crucial part of understanding selective breeding. It's the difference between the average trait value of those selected for breeding and the average trait value of the entire population. Let's break it down with a simple example.
Imagine a strawberry farmer measuring the average weight of strawberries from the entire garden, which is 2 g. The farmer then selects the best plants, producing strawberries averaging 6 g. The selection differential is the difference between these two averages:\[ S = 6 \, \text{g} - 2 \, \text{g} = 4 \, \text{g} \]This selection differential of 4 g indicates the average superiority of the chosen plants over the initial population. It essentially reflects how much better the selected individuals are compared to the rest. It is used in conjunction with heritability in the breeder's equation to predict improvements in the next generation.
Understanding the selection differential allows breeders to measure the intensity of their selection and, when used with heritability, to estimate the genetic gain they can achieve through selective breeding.

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Most popular questions from this chapter

A characteristic has a narrow-sense heritability of 0.6 . a. If the dominance variance \(\left(V_{\mathrm{D}}\right)\) increases and all other variance components remain the same, what will happen to narrow-sense heritability? Will it increase, decrease, or remain the same? Explain. b. What will happen to broad-sense heritability? Explain. c. If the environmental variance \(\left(V_{\mathrm{E}}\right)\) increases and all other variance components remain the same, what will happen to narrow- sense heritability? Explain. d. What will happen to broad-sense heritability? Explain.

The narrow-sense heritability of wing length in a population of Drosophila melanogaster is \(0.8 .\) The narrow-sense heritability of head width in the same population is \(0.9 .\) The genetic correlation between wing length and head width is \(-0.86 .\) If a geneticist selects for increased wing length in these flies, what will happen to head width?

What information do the mean and variance provide about a distribution?

Many researchers have estimated the heritability of human traits by comparing the correlation coefficients of monozygotic and dizygotic twins (see pp. \(747-748\) ). One of the assumptions made in using this method is that monozygotic twin pairs experience environments that are no more similar to each other than those experienced by dizygotic twin pairs. How might this assumption be violated? Give some specific examples of how the environments of two monozygotic twins might be more similar than the environments of two dizygotic twins.

Three characteristics in beef cattle-body weight, fat content, and tenderness- are measured, and the following variance components are estimated: $$ \begin{array}{lccc} & \begin{array}{c} \text { Body } \\ \text { weight } \end{array} & \begin{array}{c} \text { Fat } \\ \text { content } \end{array} & \text { Tenderness } \\ \hline V_{\mathrm{A}} & 22 & 45 & 12 \\ \hline V_{\mathrm{D}} & 10 & 25 & 5 \\ \hline V_{1} & 3 & 8 & 2 \\ \hline V_{\mathrm{E}} & 42 & 64 & 8\\\ \hline V_{\mathrm{GE}} & 0 & 0 & 1\\\ \end{array} $$ In this population, which characteristic would respond best to selection? Explain your reasoning.

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