Chapter 12: Q11. (page 398)
Calculate and from the following data:
0.1 | 0.34 |
0.2 | 0.53 |
0.4 | 0.74 |
0.8 | 0.91 |
1.6 | 1.04 |
Short Answer
The values of and are and .
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Chapter 12: Q11. (page 398)
Calculate and from the following data:
0.1 | 0.34 |
0.2 | 0.53 |
0.4 | 0.74 |
0.8 | 0.91 |
1.6 | 1.04 |
The values of and are and .
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You are attempting to determine KM by measuring the reaction velocity at different substrate concentrations, but you do not realize thatthe substrate tends to precipitate under the experimental conditions youhave chosen. How would this affect your measurement of KM?
Why might an enzyme鈥檚 substrate, transition state, and product all serve as starting points for the design of a competitive inhibitor?
What distinguishes an inhibitor from an inactivator?
For an enzyme-catalyzed reaction, the presence of 5 nM of a reversible inhibitor yields a Vmax value that is 80% of the value in the absenceof the inhibitor. The KM value is unchanged. (a) What type of inhibition is likely occurring? (b) What proportion of the enzyme molecules have bound inhibitor? (c) Calculate the inhibition constant.
Estimate KI for a competitive inhibitor when [I] = 5mM gives an apparent value of KM that is three times the KM for the uninhibited reaction.
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