Q22P Propranolol binds to 尾-adrenerg... [FREE SOLUTION]

Chapter 13: Q22P (page 441)

Propranolol binds to $尾$ -adrenergic receptors with a $K_{I}$ of $8.9 脳 10^{- 9} M$ . What concentration of propranolol would be required to achieve a 50% reduction in the binding of the receptor agonist isoproterenol if the agonist concentration is 10 nM and its dissociation constant for the receptor is $4.8 脳 10^{- 8} M$ ?

Short Answer

Expert verified

Concentration needed to achieve 50% reduction in binding is $1.1 脳 10^{- 7} M.$

Step by step solution

Description

Beta-blockers are a class of medications that includes propranolol. It helps with anxiety, treats cardiac issues, and shields against migraines.Propranolol is a medication that can be used to treat high blood pressure if you have a heart condition.

Calculation of the concentration

The expression that connects the binding affinity of the competing ligand and the binding affinity of the bonded ligand is:

$K_{I} = \frac{{[I]}_{50}}{1 + \frac{[L]}{K_{L}}}$

$K_{I}$ of propranolol is $8.9 脳 10^{- 9} M$ , the concentration of isoproterenol is ${[A] = 10 nM = 10}^{- 8} M$ ,and $K_{L}$ of isoproterenol is $4.8 脳 10^{- 8} M$ .

Final result

So, the result is

$\begin{array}{rcl} I_{50} {=K}_{I} (1 + \frac{[A]}{K_{L}}) \\ = 8.9 脳 10^{- 9} (1 + \frac{{[10}^{- 8}]}{4.8 脳 10^{- 8}}) \\ = 1.1 脳 10^{- 7} M \end{array}$

Therefore, the concentration needed to achieve 50% a reduction in binding is $1.1 脳 10^{- 7} M.$

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Short Answer

Step by step solution

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Calculation of the concentration

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