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Chapter 25: Problem 14

In a population of 10,000 individuals, where 3600 are \(M M\) 1600 are \(N N,\) and 4800 are \(M N,\) what are the frequencies of the \(M\) alleles and the \(N\) alleles?

Short Answer

Expert verified
Answer: The frequencies of the M alleles and N alleles are 60% and 40%, respectively.

Step by step solution

01

Calculate total number of alleles in the population

Since there are a total of 10,000 individuals and each individual has 2 alleles, the total number of alleles in the population would be 10,000 x 2 = 20,000.
02

Calculate total number of M alleles in the population

The total number of \(M\) alleles found in \(M M\) individuals is 3600 x 2 = 7200 because each \(M M\) individual has two M alleles. The total number of \(M\) alleles found in \(M N\) individuals is 4800 x 1 = 4800 because each \(M N\) individual has one M allele. Combining the two, the total number of M alleles in the population is 7200 + 4800 = 12,000.
03

Calculate the frequency of M alleles

To find the frequency of M alleles, divide the total number of M alleles by the total number of alleles in the population: 12,000 M alleles / 20,000 alleles = 0.60 or 60%.
04

Calculate total number of N alleles in the population

The total number of \(N\) alleles found in \(N N\) individuals is 1600 x 2 = 3200 because each \(N N\) individual has two N alleles. The total number of \(N\) alleles found in \(M N\) individuals is 4800 x 1 = 4800 because each \(M N\) individual has one N allele. Combining the two, the total number of N alleles in the population is 3200 + 4800 = 8,000.
05

Calculate the frequency of N alleles

To find the frequency of N alleles, divide the total number of N alleles by the total number of alleles in the population: 8,000 N alleles / 20,000 alleles = 0.40 or 40%. In this population, the frequencies of the \(M\) alleles and the \(N\) alleles are 60% and 40%, respectively.

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Most popular questions from this chapter

Price et al. (1999. J. Bacteriol. 181: 2358-2362) conducted a genetic study of the toxin transport protein (PA) of Bacillus anthracis, the bacterium that causes anthrax in humans. Within the 2294 -nucleotide gene in 26 strains they identified five point mutations-two missense and three synonyms-among different isolates. Necropsy samples from an anthrax outbreak in 1979 revealed a novel missense mutation and five unique nucleotide changes among ten victims. The authors concluded that these data indicate little or no horizontal transfer between different \(B\). anthracis strains. (a) Which types of nucleotide changes (missense or synonyms) cause amino acid changes? (b) What is meant by horizontal transfer? (c) On what basis did the authors conclude that evidence of horizontal transfer is absent from their data?

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