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Chapter 15: Q15.3-3CC (page 306)

Gene A, B, and C are located on the same chromosome. Test crosses show that the recombination frequency between A and B is 28% and that between A and C is 12%. Can you determine the linear order of these genes?

Short Answer

Expert verified

There are two possibilities of arranging the genes, such as A-C-B or C-A-B. It is difficult to determine the linear order without the recombination frequency between B and C being predicted.

Step by step solution

01

Definition of gene and chromosome

The portion of DNA that is coding for a particular protein is known as a gene. The chromosomes are the linear structure that is composed of DNA and protein-bound towards each other.

02

Description of recombination frequency

In two genes, the frequency that corresponds to the single chromosome cross is known as recombination frequency. The unit of recombination frequency is the centimorgan. It is denoted by the symbol of 胃.

03

Prediction of recombinant frequency in the gene A, B, and C.

The recombination frequency of test crosses between the gene A and B is 28%. The recombination frequency of the other two genes, A and C, is 12%.

The linear order of gene arrangement can take place in two ways, such as A-C-BorC-A-B. It is difficult to predict the exact linear formation formed from these two combinations. It is necessary to know the recombination frequency of another pair, such as B and C.

Hence, the recombination frequency of another pair, such as B and C, is necessary to determine the linear order of the genes.

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Most popular questions from this chapter

Consider what you learned about dominant and recessive alleles in Concept 14.1. If a disorder were caused by a dominant X-linked allele, how would the inheritance pattern differ from what we see for recessive X-linked disorders?

Using the information from problem 4, scientists do a further testcross using a heterozygote for height and nose morphology. The offspring are tall upturned snout, 40; dwarf upturned snout, 9; dwarf downturned snout, 42; tall downturned snout, 9. Calculate the recombination frequency from these data, and then use your answer from problem 4 to determine the correct order of the three linked genes.

When two genes are located on the same chromosome, what is the physical basis for the production of recombinant offspring in a testcross between a dihybrid parent and a double-mutant (recessive) parent?

The goodness of fit is measured by\({\chi ^{^2}}\). This statistic measures the amounts by which the observed values differ from their respective predictions to indicate how closely the two sets of values match. The formula for calculating this value is

\({\chi ^{}} = \sum \frac{{{{\left( {o - e} \right)}^2}}}{e}\)

Where o=observed and e= expected. Calculate the\({\chi ^{^2}}\)value for the data using the table below. Fill out the table, carrying out the operations indicated in the top row. Then add up the entries in the last column to find the\({\chi ^{^2}}\)value.

Testcross Offspring

Expected

(e)

Observed

(o)

Deviation

(o-e)

(o-e)2

(o-e)2/e

(A-B-)

220

(aaB-)

210

(A-bb)

231

(aabb)

239

\({\chi ^2}\) =sum

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