Q4.3-44E The graph of the derivative \(f'... [FREE SOLUTION]

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Chapter 53: Q4.3-44E (page 1188)

The graph of the derivative \(f'\) of a continuous function \(f\) is shown
On what intervals is f increasing? Decreasing?
At what values of \(x\) does f have a local maximum? Local minimum?
On what intervals is f concave upward? Concave downward?
State the \(x\)-coordinate(s) of the point(s) of inflection.
Assuming that \(f\left( 0 \right) = 0\), sketch the graph of f.
44.

Short Answer

Expert verified

The function\(f\)is increasing on the interval\(\left( {1,6} \right)\)and \(\left( {8,\infty } \right)\).The function\(f\)is decreasing on the interval\(\left( {0,1} \right)\)and \(\left( {6,8} \right)\).
The function \(f\)contains local maxima at \(x = 6\). \(f\) has local minima at \(x = 1\) and \(x = 8\)
The function \(f\) is concave upward on the interval \(\left( {0,2} \right),\left( {3,5} \right)\), and \(\left( {7,\infty } \right)\).\(f\) is concave downward on the interval \(\left( {2,3} \right)\) and \(\left( {5,7} \right)\).
The point of inflection occurs at \(x = 2,x = 3,x = 5,\) and \(x = 7\).
The graph of \(f\) as shown below:

Step by step solution

Increasing/ Decreasing Test, concavity Test

Theincreasing and decreasing testas shown below:

The function \(f\) is increasingon the interval when \(f'\left( x \right) > 0\) on an interval.
The function \(f\) is decreasingon the interval when \(f'\left( x \right) < 0\) on an interval.

TheConcavity test as shown below:

When \(f''\left( x \right) > 0\) on an interval \(I\)then the graph of \(f\) is said to be concave upwardon \(I\).
When \(f''\left( x \right) < 0\) on an interval \(I\)then the graph of \(f\) is said to be concave downwardon \(I\).

Determine at what interval is \(f\) increasing or decreasing

It is observed from the graph that the function \(f\) is increasing when \(f'\) is positive, therefore on the interval \(\left( {1,6} \right)\) and \(\left( {8,\infty } \right)\).

It is observed from the graph that function \(f\) is decreasing when \(f'\) is negative, therefore on the interval \(\left( {0,1} \right)\) and \(\left( {6,8} \right)\).

Determine the values of x does \(f\) have a local maximum and local minimum

Thesecond derivative test: Let \(f''\) be continuous near \(c\).

When \(f'\left( c \right) = 0\) and \(f''\left( c \right) > 0\) then function \(f\) contain local minimum at \(c\).
When \(f'\left( c \right) = 0\) and \(f''\left( c \right) < 0\) then function \(f\) containslocal maximumat \(c\).

It is observed from the graph that there are changes in \(f'\) from positive to negative at \(x = 6\) such that the function \(f\)contains local maxima.

There are changes in \(f'\) from negative to positive at \(x = 1\) and \(x = 8\) such that the function \(f\) has local minima.

Determine at what interval is \(f\) concave upward and concave downward

It is observed from the graph that the function \(f\) is concave upward (CU) when \(f'\) is increasing, therefore on the interval \(\left( {0,2} \right),\left( {3,5} \right)\), and \(\left( {7,\infty } \right)\).

The function \(f\) is concave downward (CD) when \(f'\) is decreasing, therefore on the interval \(\left( {2,3} \right)\) and \(\left( {5,7} \right)\).

State the x-coordinate(s) of the point(s) of inflection

The point of inflection occurs at \(x = 2,x = 3,x = 5,\) and \(x = 7\) in which the function \(f\) changes in the direction of concavity.

Sketch the graph of f

The point of inflection occurs at \(x = 2,x = 3,x = 5,\) and \(x = 7\). \(f\) is concave upward at \(\left( {0,2} \right),\left( {3,5} \right)\), and \(\left( {7,\infty } \right)\) . \(f\) is concave downward at \(\left( {2,3} \right)\) and \(\left( {5,7} \right)\).

Consider that \(f\left( 0 \right) = 0\). This leads to the point \(\left( {0,0} \right)\).

Use the above condition to sketch the graph of \(f\) as shown below: