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Explain why a constant per capita rate of growth (r) for a population produces a curve that is J-shaped.

Short Answer

Expert verified

The population size (N) is not constant. It is either decreasing or increasing. The development of the population shows acceleration and produces a J-shaped curve when the per capita rate of growth is applied to a population that is growing exponentially.

Step by step solution

01

Change in population size

The number of resources available for members of the population determines the increase and decrease in the population size. For example, a population living in an unlimited and ideal environment shows an increase in population size.

They have all access to energy and ability to grow and reproduce. A population living with limited resources does not show rapid growth.

02

Exponential growth

Exponential growth is the pattern of growth that shows a constant increase in the size of the population at each instant time. This type of growth pattern is seen in a population that lives in an unlimited and ideal environment. The equation that represents exponential growth is \(\frac{{dN}}{{dt}} = rN\)

03

Exponential growth curve

In the equation \(\frac{{dN}}{{dt}} = rN\), the rate of increase of population size is denoted by \(\frac{{dN}}{{dt}}\) and \(rN\) represents current population size (N) multiplied with constant (r). The population, which shows exponential growth, increases at a constant rate per member.

Therefore, when population size is compared with time, it shows a J-shaped growth curve even though the per capita rate of population growth is constant. Over time, more individuals are added to the population, which results in progressively steeper curves.

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Most popular questions from this chapter

The graph of the derivative \(f'\) of a continuous function \(f\) is shown

  1. On what intervals is f increasing? Decreasing?
  2. At what values of \(x\) does f have a local maximum? Local minimum?
  3. On what intervals is f concave upward? Concave downward?
  4. State the \(x\)-coordinate(s) of the point(s) of inflection.
  5. Assuming that \(f\left( 0 \right) = 0\), sketch the graph of f.

44.

To estimate which age cohort in a population of females produces the most female offspring, you need information about the number of offspring produced per capita within that cohort and the number of individuals alive in the cohort. Make this estimate for Belding’s ground squirrels by multiplying the number of females alive at the start of the year (column 2 in Table 53.1) by the average number of female offspring produced per female (column 5 in Table 53.1). Draw a bar graph with female age in years on the x-axis (0–1, 1–2, and so on) and total number of female offspring produced for each age cohort on the y-axis. Which cohort of female Belding’s ground squirrels produces the most female young?

(a) Find the intervals of increase or decrease.

(b) Find the local maximum and minimum values.

(c) Find the intervals of concavity and the inflection points.

(d) Use the information from parts (a)–(c) to sketch the graph.

You may want to check your work with a graphing calculator or computer.

58. \(S\left( x \right) = x - \sin x,{\rm{ 0}} \le x \le 4\pi \)

According to the logistic growth equation\(\frac{{dN}}{{dt}} = rN\frac{{(K - N)}}{K}\)

(A) the number of individuals added per unit time is greatest when Nis close to zero.

(B) the per capita population growth rate increases as Napproaches K.

(C) population growth is zero when Nequals K.

(D) the population grows exponentially when Kis small

  1. Find the intervals of increase or decrease.
  2. Find the local maximum and minimum values.
  3. Find the intervals of concavity and the inflection points.
  4. Use the information from parts (a)-(c) to sketch the graph. You may want to check your work with a graphing calculator or computer.

48. \(g\left( x \right) = 200 + 8{x^3} + {x^4}\)

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