Chapter 9: Problem 51
Parameterize the equation of the line given in standard form. $$3 x+2 y-1=0$$
Short Answer
Expert verified
The parametric equations are \(x(t) = 2t\) and \(y(t) = \frac{1}{2} - 3t\).
Step by step solution
01
Identify the Standard Form
The given equation is in the standard form, which is \(Ax + By + C = 0\). In this case, \(A = 3\), \(B = 2\), and \(C = -1\).
02
Convert to Slope-Intercept Form
To find the parameterization, it's helpful to express the equation in slope-intercept form, \(y = mx + b\). Solve for \(y\) by isolating it: \[3x + 2y - 1 = 0 \Rightarrow 2y = -3x + 1 \Rightarrow y = -\frac{3}{2}x + \frac{1}{2}\]So, the slope \(m\) is \(-\frac{3}{2}\) and the y-intercept \(b\) is \(\frac{1}{2}\).
03
Use Parameterization Formulas
Line parameterization can use a parameter \(t\) where \(x\) and \(y\) are functions of \(t\). Choose a point on the line (for convenience, use the y-intercept point \((0, \frac{1}{2})\)) and the direction vector derived from the slope. The direction vector from slope \(m = -\frac{3}{2}\) for change in \(x\) and \(y\) is \( \langle 2, -3 \rangle \).
04
Parameterization of the Line
Using parameter \(t\), parameterize the equations for \(x\) and \(y\): \[\begin{align*}x(t) &= 0 + 2t \y(t) &= \frac{1}{2} - 3t\end{align*}\]Thus, the parametric equations are \(x(t) = 2t\) and \(y(t) = \frac{1}{2} - 3t\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Form Equation
The standard form of an equation for a line is expressed as \(Ax + By + C = 0\). This is a versatile form that highlights the coefficients directly. Here, \(A\), \(B\), and \(C\) represent real numbers. In our equation, \(3x + 2y - 1 = 0\), we specifically identify:
Additionally, equations in this form can work effectively in integer arithmetic, avoiding fractions. However, for graphing purposes, converting to other forms may provide better insights into the line's characteristics.
- \(A = 3\)
- \(B = 2\)
- \(C = -1\)
Additionally, equations in this form can work effectively in integer arithmetic, avoiding fractions. However, for graphing purposes, converting to other forms may provide better insights into the line's characteristics.
Slope-Intercept Form
The slope-intercept form of a linear equation is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. It's highly useful for graphing and understanding how a line behaves visually on a coordinate plane.
From our example, converting \(3x + 2y - 1 = 0\) into slope-intercept form involves solving for \(y\). This yields \(y = -\frac{3}{2}x + \frac{1}{2}\). Here:
From our example, converting \(3x + 2y - 1 = 0\) into slope-intercept form involves solving for \(y\). This yields \(y = -\frac{3}{2}x + \frac{1}{2}\). Here:
- The slope \(m\) is \(-\frac{3}{2}\), indicating the line falls as it moves from left to right.
- The y-intercept \(b\) is \(\frac{1}{2}\), showing where the line crosses the y-axis.
Parametric Equations
Parametric equations describe a line by expressing its coordinates as functions of a parameter \(t\). This method offers a dynamic view of a line or curve. For instance, we use the equations \(x(t) = 2t\) and \(y(t) = \frac{1}{2} - 3t\) from the standard form.
Here's how it works:
Here's how it works:
- Select a point on the line – we use \((0, \frac{1}{2})\), the y-intercept.
- Find a direction vector from the slope \(-\frac{3}{2}\). The vector \(\langle 2, -3 \rangle\) is derived from the change in \(x\) and \(y\).
- Parameter \(t\) represents the movement along the line. While \(t\) changes, \(x(t)\) and \(y(t)\) define points on the line.
- Setting \(t = 0\) gives the base point, while changes in \(t\) map the line's direction and extension.