/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Find the dot product of \(\mathb... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the dot product of \(\mathbf{x}=[2,-3,1]^{\prime}\) and \(\mathbf{y}=[3,1,-2]\).

Short Answer

Expert verified
The dot product is 1.

Step by step solution

01

Write Down the Dot Product Formula

The dot product of two vectors \( \mathbf{x} \) and \( \mathbf{y} \) is denoted by \( \mathbf{x} \cdot \mathbf{y} \) and is calculated as follows: \[ \mathbf{x} \cdot \mathbf{y} = x_1y_1 + x_2y_2 + x_3y_3 \] where \( x_1, x_2, x_3 \) are the components of vector \( \mathbf{x} \), and \( y_1, y_2, y_3 \) are the components of vector \( \mathbf{y} \).
02

Identify Components of Vectors

Identify the components of vectors \( \mathbf{x} \) and \( \mathbf{y} \). For vector \( \mathbf{x} = [2, -3, 1]' \), the components are \( x_1 = 2 \), \( x_2 = -3 \), and \( x_3 = 1 \). For vector \( \mathbf{y} = [3, 1, -2] \), the components are \( y_1 = 3 \), \( y_2 = 1 \), and \( y_3 = -2 \).
03

Substitute Components into the Formula

Substitute the identified components into the dot product formula: \[ \mathbf{x} \cdot \mathbf{y} = (2)(3) + (-3)(1) + (1)(-2) \].
04

Calculate Each Term

Calculate each term in the expression from Step 3: 1. \( (2)(3) = 6 \).2. \( (-3)(1) = -3 \).3. \( (1)(-2) = -2 \).
05

Sum the Results

Add up all the calculated terms from Step 4: \[ 6 + (-3) + (-2) = 6 - 3 - 2 \].
06

Simplify the Expression

Simplify the expression to find the dot product: \[ 6 - 3 - 2 = 1 \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vectors
Vectors are fundamental entities in mathematics and physics that represent both a magnitude and a direction. They are often visualized as arrows, where the length of the arrow corresponds to its magnitude, and the direction of the arrow indicates its direction. In a coordinate system, vectors are described using components, each representing the vector's projection along the corresponding axis.

In our example, we have two vectors, \( \mathbf{x} = [2, -3, 1] \) and \( \mathbf{y} = [3, 1, -2] \). These vectors are three-dimensional, meaning they have components along the \( x \), \( y \), and \( z \) axes.

To fully understand vectors, it's important to recognize their properties and how they differ from scalars, which have only magnitude and no direction. Vectors enable you to perform various operations such as addition, subtraction, and particularly the dot product, which we explore in the next sections.
Components
The components of a vector are the building blocks that define its position within a coordinate space. These components tell us how far along each axis the vector extends. Examining a vector's components allows us to conduct operations like addition and the calculation of the dot product.

For instance, in vector \( \mathbf{x} = [2, -3, 1] \):
  • Component along x-axis: \( x_1 = 2 \)
  • Component along y-axis: \( x_2 = -3 \)
  • Component along z-axis: \( x_3 = 1 \)
Similarly, vector \( \mathbf{y} = [3, 1, -2] \) has components:
  • Component along x-axis: \( y_1 = 3 \)
  • Component along y-axis: \( y_2 = 1 \)
  • Component along z-axis: \( y_3 = -2 \)
Each component is crucial because it allows us to apply operations that manipulate the vector mathematically, leading to useful calculations like the dot product.
Mathematical Operations
Mathematical operations involving vectors can greatly vary, with the dot product being one of the most common and useful. The dot product, or scalar product, is an operation that takes two equal-length sequences of numbers (usually coordinate vectors) and returns a single number.

For vectors \( \mathbf{x} = [2, -3, 1]' \) and \( \mathbf{y} = [3, 1, -2] \), the dot product is calculated as:
  • Multiply the corresponding components: \((2)(3), (-3)(1), (1)(-2)\).
  • Sum these products together: \(6 + (-3) + (-2)\).
  • The result: \(1\), a scalar.
The dot product is particularly useful in physics for calculating work, as it provides a measure of how much one vector goes in the direction of another. Additionally, it can be used to determine the angle between two vectors or check if two vectors are orthogonal (perpendicular).

Through understanding and performing the dot product, we see how mathematical operations can be used to derive meaningful information from vectors in applied mathematics and physics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume that the Leslie matrix is $$ L=\left[\begin{array}{ll} 0 & 2 \\ 0.6 & 0 \end{array}\right] $$ Suppose that, at time \(t=0, N_{0}(0)=5\) and \(N_{1}(0)=1\). Find the population vectors for \(t=0,1,2, \ldots, 10 .\) Compute the successive ratios $$ q_{0}(t)=\frac{N_{0}(t)}{N_{0}(t-1)} \text { and } q_{1}(t)=\frac{N_{1}(t)}{N_{1}(t-1)} $$ for \(t=1,2, \ldots, 10 .\) Do \(q_{0}(t)\) and \(q_{1}(t)\) converge? Compute the fraction of females age 0 for \(t=0,1, \ldots, 10 .\) Describe the longterm behavior of \(q_{0}(t)\).

Find the parametric equation of the line in \(x-y-z\) space that goes through the given points. \((5,4,-1)\) and \((2,0,3)\)

Assume the given Leslie matrix L. Determine the number of age classes in the population, the fraction of one-year-olds present at time \(t\) that survive to time \(t+1\), and the average number of female offspring of a two-year-old female. $$L=\left[\begin{array}{lll}0 & 5 & 0 \\ 0.8 & 0 & 0 \\ 0 & 0.4 & 0\end{array}\right]$$

Let $$ A=\left[\begin{array}{rr} 5 & 7 \\ -2 & -4 \end{array}\right] $$ Find $$ A^{20}\left[\begin{array}{l} -3 \\ -2 \end{array}\right] $$ without using a calculator.

A population is divided into four age classes. \(70 \%\) of the females age \(0,50 \%\) of the females age 1, and \(10 \%\) of the females age 2 present at time \(t\) survive until time \(t+1\). Assume that females age 2 have an average of \(4.6\) female offspring and females age 3 have an average of \(3.7\) female offspring. If, at time 0 , the population consists of 1500 females age 0,500 females age 1,250 females age 2, and 50 females age 3, find the Leslie matrix and the number of females in each age class at time \(3 .\)

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.