Chapter 9: Problem 44
Show that the inverse of $$A=\left[\begin{array}{rrr} 2 & -1 & 0 \\ -1 & 2 & -1 \\ 0 & -1 & 2 \end{array}\right]$$ is $$A^{-1}=\left[\begin{array}{ccc} \frac{3}{4} & \frac{1}{2} & \frac{1}{4} \\ \frac{1}{2} & 1 & \frac{1}{2} \\ \frac{1}{4} & \frac{1}{2} & \frac{3}{4} \end{array}\right]$$
Short Answer
Step by step solution
Confirm Matrix Dimensions
Find the Determinant of A
Use Adjugate Method to Find Inverse
Calculate Cofactor Matrix
Form the Adjugate Matrix
Calculate the Inverse Matrix
Verify the Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
3x3 matrix
The matrix you are dealing with here is:
- Row 1: \( [2, -1, 0] \)
- Row 2: \( [-1, 2, -1] \)
- Row 3: \( [0, -1, 2] \)
determinant calculation
- \( a, b, c \)
- \( d, e, f \)
- \( g, h, i \)
- \( A = \begin{bmatrix} 2 & -1 & 0 \ -1 & 2 & -1 \ 0 & -1 & 2 \end{bmatrix} \)
- \[ \text{det}(A) = 2(4 - 1) - (-1)(-2+0) \]
- \[ = 2 \times 3 - 1 = 5 \]
adjugate method
- First, create the cofactor matrix, where each element is the determinant of the 2x2 matrices after removing one row and one column.
- Next, transpose the cofactor matrix to get the adjugate matrix.
- Finally, the inverse matrix is calculated by taking \( \frac{1}{\text{det}(A)} \) of the adjugate matrix.
cofactor matrix
- Identify the minor for each element.
- Calculate the determinant of these minors.
- Apply a positive or negative sign based on the position using the formula \((-1)^{i+j}\), where \(i\) and \(j\) correspond to the row and column indices.