Chapter 9: Problem 52
Parameterize the equation of the line given in standard form. $$x-2 y+5=0$$
Short Answer
Expert verified
The parametric equations are \(x = t\) and \(y = \frac{1}{2}t + \frac{5}{2}\).
Step by step solution
01
Rewrite in Slope-Intercept Form
Start by rewriting the given equation in the slope-intercept form, which is \(y = mx + b\). The standard form equation is \(x - 2y + 5 = 0\). To convert this, solve for \(y\): \[-2y = -x - 5 \]Divide every term by -2:\[y = \frac{x}{2} + \frac{5}{2} \]
02
Identify the Slope and Intercept
From the slope-intercept form equation \(y = \frac{1}{2}x + \frac{5}{2}\), identify the slope \(m\) as \(\frac{1}{2}\) and the y-intercept \(b\) as \(\frac{5}{2}\). These will be used to parameterize the equation.
03
Parameterize the Equation
Parameterize the line using a parameter \(t\). Choose the parameter \(t\) to represent the x-coordinate, so \(x = t\). Substitute \(x\) in terms of \(t\) into the slope-intercept form:\[y = \frac{1}{2}t + \frac{5}{2} \]Now the parametric equations for the line are: \[x = t \]\[y = \frac{1}{2}t + \frac{5}{2} \]where \(t\) is any real number.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form of a linear equation is a way to express lines in the coordinate plane. It makes it easy to identify both the slope of the line and the point where it crosses the y-axis. This form is given by the formula: \( y = mx + b \), where:
- \( m \) represents the slope of the line, which is the rate at which \( y \) changes with respect to \( x \).
- \( b \) is the y-intercept, the point where the line intersects the y-axis.
- First, isolate the term with \( y \) by moving other parts of the equation to the right side. For the equation \( x - 2y + 5 = 0 \), you subtract \( x \) and 5 from both sides, resulting in \( -2y = -x - 5 \).
- Next, divide every term by the coefficient of \( y \); in this case, \(-2\). This simplifies to \( y = \frac{1}{2}x + \frac{5}{2} \).
Parametric Equations
Parametric equations allow us to express the coordinates of points on a line as functions of a variable, typically denoted as \( t \). This approach can give us a more flexible way to describe a linear function, offering insight into the relationship between the variables over a given interval.Consider the line originally expressed in the slope-intercept form: \( y = \frac{1}{2}x + \frac{5}{2} \). To find its parametric form, we choose \( t \) to represent the x-coordinate, meaning \( x = t \). Then the function for \( y \) becomes dependent on the parameter \( t \):
- \( y = \frac{1}{2}t + \frac{5}{2} \)
- \( x = t \)
- \( y = \frac{1}{2}t + \frac{5}{2} \)
Linear Equations
Linear equations in two variables describe straight lines on the coordinate plane. In their simplest form, they capture the relationship between \( x \) and \( y \) with constants. Common forms include the standard form \( Ax + By = C \), the slope-intercept form \( y = mx + b \), and the parametric form previously discussed.Each form serves its purpose:
- The standard form \( Ax + By = C \) is useful for determining intercepts quickly and for certain algebraic manipulations. In our exercise: \( x - 2y + 5 = 0 \), you can readily convert this into different forms to unveil different characteristics of the line.
- The slope-intercept form, as we covered, is instrumental in visualizing the slope and starting point on the graph.
- Parametric equations offer a method to outline all possible points on the line for computational purposes or when the line needs to be traversed systematically.