Chapter 9: Problem 39
Find the equation of the plane through \((0,0,0)\) and perpendicular to \([1,1,1]\) '.
Short Answer
Expert verified
The equation of the plane is \\(x + y + z = 0\\).
Step by step solution
01
Understanding the Problem
The task is to find the equation of a plane given certain conditions. We know the plane passes through the point \(0,0,0\) and is perpendicular to the vector \[1, 1, 1\]. The vector that defines the perpendicular direction is also the normal vector of the plane.
02
Equation of the Plane
The general equation of a plane with a normal vector \(\mathbf{n} = (a, b, c)\) and passing through a point \(P_0(x_0, y_0, z_0)\) is given by \((x-x_0)a + (y-y_0)b + (z-z_0)c = 0\). For this problem, \((x_0, y_0, z_0) = (0,0,0)\), and \((a, b, c) = (1, 1, 1)\).
03
Substituting into the Plane Equation
We substitute the values \(x_0=0\), \(y_0=0\), \(z_0=0\), \(a=1\), \(b=1\), \(c=1\) into the plane equation. This results in \(1(x-0) + 1(y-0) + 1(z-0) = 0\).
04
Simplifying the Equation
Simplifying the equation, we get \(x + y + z = 0\). This equation represents the plane that passes through the origin and is perpendicular to the vector \[1, 1, 1\].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Normal Vector
In three-dimensional geometry, a **normal vector** is a vector that is perpendicular to a given surface, such as a plane. When working with planes, the normal vector is crucial because it defines the plane's orientation in space. For any plane to be uniquely identified by its equation, a normal vector must be provided.
A **normal vector** is generally represented as \((a, b, c)\), where:
A **normal vector** is generally represented as \((a, b, c)\), where:
- \(a\), \(b\), and \(c\) are the vector components that determine the direction of the perpendicular line to the plane.
- These components also become the coefficients in the equation of the plane.
Defining the Perpendicular Vector
A plane is defined such that every vector lying on the plane is **perpendicular** to the normal vector. In geometry, perpendicularity implies a 90-degree angle between two vectors. This perpendicular relationship is fundamental to understanding how planes are situated in three-dimensional space.
To determine if a vector is perpendicular to a plane, consider the following:
To determine if a vector is perpendicular to a plane, consider the following:
- The dot product of the vector with the normal vector of the plane should be zero.
- If the dot product is zero, it confirms that the vector is perpendicular to the plane.
Exploring Three-Dimensional Coordinates
In three-dimensional geometry, points, lines, and planes are described using **three-dimensional coordinates**. These coordinates, typically given as \((x, y, z)\), represent a point's position in three-dimensional space. Understanding these coordinates is essential when dealing with planes, vectors, and other geometrical entities.
The equation of a plane in three dimensions is of crucial importance because:
The equation of a plane in three dimensions is of crucial importance because:
- It helps in differentiating a plane from other surfaces.
- It provides a mathematical way to describe all points lying on the plane.