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A triangle has vertices at coordinates \(P=(0,0), Q=(0,3)\), and \(R=(4,3)\). (a) Use basic trigonometry to compute the lengths of all three sides and the measures of all three angles. (b) Use the results of this section to repeat (a).

Short Answer

Expert verified
Side lengths: 3, 4, 5. Angles: \(90^\circ\), \(36.87^\circ\), \(53.13^\circ\).

Step by step solution

01

Determine Side Lengths

To find the lengths of each side of the triangle, use the distance formula: \[ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \]For side \(PQ\): \[ PQ = \sqrt{(0-0)^2 + (3-0)^2} = 3 \]For side \(QR\): \[ QR = \sqrt{(4-0)^2 + (3-3)^2} = 4 \]For side \(RP\): \[ RP = \sqrt{(4-0)^2 + (3-0)^2} = 5 \]
02

Determine Angles Using Trigonometry

Next, we use trigonometry to find the angles of the triangle. The triangle is right-angled at \(Q\), use the definitions of sine, cosine, and tangent for triangles:- For \(\angle PQR\) (right angle): It's \(90^\circ\).- For \(\angle QRP\), use \(\tan^{-1}(\text{opposite} / \text{adjacent})\) \[ \angle QRP = \tan^{-1}(3/4) = 36.87^\circ \]- For \(\angle PRQ\), use \(180^\circ - 90^\circ - 36.87^\circ = 53.13^\circ\).
03

Double-check using the Pythagorean Theorem

As a consistency check, we can apply the Pythagorean theorem. Since the calculated sides are: \[PQ^2 + QR^2 = RP^2\]\[3^2 + 4^2 = 5^2\]\[9 + 16 = 25\]The equation holds, confirming a right triangle.
04

Short Answer Summary

The lengths of the triangle sides are 3, 4, and 5 units, and the angles are \(90^\circ\), \(36.87^\circ\), and \(53.13^\circ\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance Formula
The distance formula is a crucial tool in geometry, particularly when you're dealing with coordinates on a plane. This formula allows you to calculate the distance between two points. If you have two points, say \(A = (x_1, y_1)\) and \(B = (x_2, y_2)\), the distance \(d\) between them can be calculated using the formula: \[ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \] This formula is derived from the Pythagorean theorem (which we'll explore later), by considering the line between the two points as the hypotenuse of a right triangle.
In our exercise, we used the distance formula to determine the lengths of the sides of the triangle with vertices \(P=(0,0), Q=(0,3),\) and \(R=(4,3)\). For example, to find the length of side \(PQ\) you calculate: \[ PQ = \sqrt{(0-0)^2 + (3-0)^2} = 3 \]
This straightforward approach reveals how the distance formula helps in determining side lengths accurately without any complex calculations.
Pythagorean Theorem
The Pythagorean theorem is fundamental in trigonometry and relates to right triangles. It states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
So, in a triangle with sides \(a\), \(b\), and hypotenuse \(c\), the theorem is represented as: \[ a^2 + b^2 = c^2 \]
This theorem is not only useful for proving right triangle relationships but also for solving various geometric problems. In the given exercise, after computing the side lengths, we verified the triangle is right-angled using Pythagorean theorem: \[ PQ^2 + QR^2 = RP^2 \]\[ 3^2 + 4^2 = 5^2 \]
The left-hand side sums to 25, confirming that \(RP = 5\) matches as the hypotenuse. Such verification provides not only an answer but also confidence in the calculation process.
Right Triangle
A right triangle is a type of triangle that has one angle equal to \(90^\circ\). Right triangles are fundamental in trigonometry because they allow us to define and understand trigonometric ratios for angles.
  • The side opposite the right angle is called the hypotenuse and is the longest side in the triangle.
  • The other two sides are known as the legs, which can be referred to as base and height depending on orientation.

In our exercise, the triangle \(PQR\) was identified as a right triangle with the right angle situated at point \(Q\). This makes \(RP\) the hypotenuse and sides \(PQ\) and \(QR\) the legs. Using this information, we not only calculated side lengths with the distance formula but also verified angles using trigonometric functions. The classification of triangles, like identifying \(PQR\) as a right triangle, helps in understanding geometric properties and making calculations more intuitive.

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Most popular questions from this chapter

Find the eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) and corresponding eigenvectors \(\mathrm{v}_{1}\) and \(\mathrm{v}_{2}\) for each matrix A. Determine the equations of the lines through the origin in the direction of the eigenvectors \(\mathrm{v}_{1}\) and \(\mathrm{v}_{2}\), and graph the lines together with the eigenvectors \(\mathrm{v}_{1}\) and \(\mathrm{v}_{2}\) and the vectors \(\mathrm{Av}_{1}\) and \(\mathrm{Av}_{2}\) $$A=\left[\begin{array}{rr}-1 & 2 \\ 4 & 1\end{array}\right]$$

Find the equation of the line through \((1,-2)\) and perpendicular to \([4,1]^{\prime}\).

Assume that a population is divided into three age classes and that \(80 \%\) of the females age 0 and \(10 \%\) of the females age present at time \(t\) survive until time \(t+1\). Assume further that females age 1 have an average of \(1.6\) female offspring and females age 2 have an average of \(3.9\) female offspring. If, at time 0 , the population consists of 1000 females age 0,100 females age 1 , and 20 females age 2 , find the Leslie matrix and the number of females in each age class at time \(3 .\)

A population is divided into four age classes. \(65 \%\) of the females age \(0,40 \%\) of the females age 1 , and \(30 \%\) of the females age 2 present at time \(t\) survive until time \(t+1\). Assume that females age 1 have an average of \(2.8\) female offspring, females age 2 have an average of \(7.6\) female offspring, and females age 3 have an average of \(2.4\) female offspring. If, at time 0 , the population consists of 1000 females age 0,500 females age 1,200 females age 2, and 50 females age 3, find the Leslie matrix and the number of females in each age class at time \(3 .\)

Find the eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) and corresponding eigenvectors \(\mathrm{v}_{1}\) and \(\mathrm{v}_{2}\) for each matrix A. Determine the equations of the lines through the origin in the direction of the eigenvectors \(\mathrm{v}_{1}\) and \(\mathrm{v}_{2}\), and graph the lines together with the eigenvectors \(\mathrm{v}_{1}\) and \(\mathrm{v}_{2}\) and the vectors \(\mathrm{Av}_{1}\) and \(\mathrm{Av}_{2}\) $$A=\left[\begin{array}{rr}-1 & 0 \\ 4 & 3\end{array}\right]$$

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