Chapter 4: Problem 21
(a) Use the formal definition of the derivative to find the derivative of \(y=2 x^{2}\) at \(x=-1\). (b) Show that the point \((-1,2)\) is on the graph of \(y=2 x^{2}\), and find the equation of the tangent line at the point \((-1,2)\). (c) Graph \(y=2 x^{2}\) and the tangent line at the point \((-1,2)\) in the same coordinate system.
Short Answer
Step by step solution
Use the Definition of Derivative
Expand and Simplify
Factor and Simplify the Expression
Substitute and Evaluate at x = -1
Verify the Point is on the Graph
Find the Equation of the Tangent Line
Graph the Function and Tangent Line
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Formal Definition of Derivative
\[ f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h}. \]
Here, \( h \) is a small increment in \( x \), and the expression measures the average rate of change over that small interval. As \( h \) approaches zero, this rate becomes instantaneous, giving us the derivative.
For the function \( y = 2x^2 \), plugging it into the formula involves expanding the binomial \((x+h)^2\), simplifying, and taking the limit as \( h \to 0 \). After this process, you find that the derivative, or the rate of change of \( y = 2x^2 \), is \(4x\). This tells us how steep the curve is at any point \( x \). At \( x = -1 \), this slope becomes \(-4\), indicating a steep downward slope.
Tangent Line
For the point \((-1, 2)\) on the function \( y = 2x^2 \), we discover the slope of the tangent line using our derivative: the slope is \(-4\). The tangent line is then defined using the point-slope form of a line equation:
\[ y - y_1 = m(x - x_1), \]where \( m \) is the slope and \((x_1, y_1)\) is the point of tangency.
By applying this to the point \((-1, 2)\) with \( m = -4 \), we derive the line equation \( y = -4x - 2 \). This equation represents the precise tangent line that "kisses" the parabola at the point where \( x = -1 \) and \( y = 2 \).
Graphing Functions
When graphing \( y = 2x^2 \), one key aspect is to plot significant points accurately, such as the vertex and any points of interest like \((-1, 2)\), to delineate the curve's shape effectively.
To highlight the relationship between the function and its tangent line, graph \( y = -4x - 2 \) alongside the parabola. This line appears to just "touch" the parabola at the point \((-1, 2)\) without cutting through it. Such visualizations help demonstrate how the tangent line represents the exact slope of the function at that point, reinforcing your understanding of derivatives and tangents in a real, visible manner.