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Chapter 4: Problem 2

Find the derivative at the indicated point from the graph of \(y=f(x)\). \(f(x)=-3 x ; x=-2\)

Short Answer

Expert verified
The derivative at \(x = -2\) is \(-3\).

Step by step solution

01

Identify the Function

First, we identify the given function that we will be working with. The function is \(f(x) = -3x\). This is a linear function.
02

Recall the Derivative of a Linear Function

The derivative of a function \(f(x) = mx + b\), where \(m\) and \(b\) are constants, is simply the slope \(m\) of the line. Since \(f(x) = -3x\), the derivative \(f'(x)\) is \(-3\).
03

Evaluate the Derivative at the Point

Now that we know the derivative of the function is \(-3\), we evaluate it at the point \(x = -2\). For linear functions, the derivative is constant, so \(f'(x) = -3\) for any value of \(x\). Therefore, at \(x = -2\), \(f'(-2) = -3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Function
A linear function is a mathematical expression that creates a straight line when graphed on a coordinate plane. The general form of a linear function is given by \( f(x) = mx + b \), where:
  • \( m \) represents the slope of the line
  • \( b \) represents the y-intercept鈥攖he point where the line crosses the y-axis
Linear functions are simple because their graphs are always straight lines. In the given exercise, the function \( f(x) = -3x \) is linear.
Here, the line has a slope of \( -3 \) and passes through the origin, since \( b = 0 \). With no y-intercept other than zero, the line is diagonal through the origin. Linear functions with just one variable like this one are the building blocks for understanding relationships in algebra.
Slope
The slope of a line is a measure of its steepness. It tells us how much the y-value of the function changes for a change in the x-value. For a linear function \( f(x) = mx + b \), the slope is represented by the coefficient \( m \).
In simple terms:
  • If the slope is positive, the line rises as it moves from left to right.
  • If the slope is negative, the line falls as it moves from left to right.
  • A larger absolute value of the slope means a steeper line.
For \( f(x) = -3x \), the slope \( m = -3 \) indicates that the line is falling or decreasing at a constant rate. The negative sign shows that as you move rightward across the graph, the line goes downward. Understanding slope is crucial for predicting changes and analyzing the function's behavior.
Evaluate the Derivative
Evaluating the derivative of a function at a certain point gives the rate of change at that point. For linear functions, this process is simplified since the derivative is constant and equals the slope of the line.
In the exercise, we have the linear function \( f(x) = -3x \). The derivative, therefore, is the slope \( f'(x) = -3 \). This means the rate of change maintains a consistent value.
  • Since this function is linear, the derivative \( f'(x) = -3 \) holds true for any \( x \).
  • Thus, evaluating the derivative at \( x = -2 \) simply confirms that the rate of change at this specific point also is \(-3\).
For linear functions, the derivative is an intuitive way to reinforce that the slope and rate of change are inherently connected, remaining constant across the function's domain.

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Most popular questions from this chapter

Use the quotient rule to show that $$ \frac{d}{d x} \csc x=-\csc x \cot x $$

Use the formula $$f(x) \approx f(a)+f^{\prime}(a)(x-a)$$ to approximate the value of the given function. Then compare your result with the value you get from a calculator. \(\sqrt[3]{124}\)

Calculate the linear approximation for \(f(x)\) : $$f(x) \approx f(a)+f^{\prime}(a)(x-a)$$ \(f(x)=e^{-3 x}\) at \(a=0\)

Use the quotient rule to show that $$ \frac{d}{d x} \cot x=-\csc ^{2} x $$

Use the identity $$\cos (\alpha+\beta)=\cos \alpha \cos \beta-\sin \alpha \sin \beta$$ and the definition of the derivative to show that $$ \frac{d}{d x} \cos x=-\sin x $$
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