Chapter 4: Problem 2
Differentiate the functions with respect to the independent variable. \(f(x)=e^{-2 x}\)
Short Answer
Expert verified
The derivative of \(f(x) = e^{-2x}\) is \(f'(x) = -2e^{-2x}\).
Step by step solution
01
Identify Function and Variable
The given function is \(f(x) = e^{-2x}\), and we need to differentiate this function with respect to the independent variable \(x\).
02
Apply the Derivative Rule for Exponentials
Recall that the derivative of \(e^{u}\) with respect to \(x\) is \(e^{u} \cdot \frac{du}{dx}\). In this case, \(u = -2x\), so we need to find \(\frac{du}{dx}\).
03
Differentiate the Exponent
Differentiate \(-2x\) with respect to \(x\). This gives us \(\frac{d(-2x)}{dx} = -2\).
04
Combine the Results
Substitute \(u = -2x\) and \(\frac{du}{dx} = -2\) back into the exponential derivative rule. Thus, the derivative of \(f(x) = e^{-2x}\) is \(e^{-2x} \cdot (-2)\).
05
Simplify the Expression
Simplify the expression \(-2 \cdot e^{-2x}\). This results in \(f'(x) = -2e^{-2x}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
Exponential functions are a special type of mathematical function where the variable appears in the exponent. They have the form \(f(x) = a^{x}\), but when the base is the natural exponential number \(e\), it becomes \(f(x) = e^{x}\). Here, the function grows or decays at a constant rate, making them very useful in modeling real-world phenomena such as population growth, radioactive decay, and continuously compounded interest.
- The number \(e\) is approximately equal to 2.71828 and is the base of natural logarithms.
- In exponential functions, changes in \(x\) cause rapid increases or decreases in the function's value.
- Exponential functions are continuous and smooth, meaning they have no breaks, holes, or sharp corners.
Chain Rule
The Chain Rule is a critical differentiation technique used when dealing with composite functions, where one function is nested inside another. It's a rule that allows us to differentiate the outer function and the inner function separately.Consider a function \(f(g(x))\), where \(f\) is the outer function and \(g\) is the inner function. The chain rule states that the derivative \(\frac{d}{dx} f(g(x)) = f'(g(x)) \cdot g'(x)\).
- Identify the outer and inner functions correctly to apply the rule.
- Differentiate the outer function leaving the inner function unchanged.
- Multiply by the derivative of the inner function.
Differentiation Steps
Differentiation is the process of finding the derivative of a function, which represents the rate at which the function's value changes as the variable changes. It is one of the most fundamental operations in calculus. Here are the steps for differentiating a composite function with an exponential component, as seen in the exercise:1. **Identify the Function and Variable**: Locate the function to be differentiated and the variable with respect to which differentiation will occur. In our case, \(f(x) = e^{-2x}\), where the variable is \(x\).2. **Apply the Derivative Rule for Exponentials**: Use the rule \(\frac{d}{dx} e^{u} = e^{u} \cdot \frac{du}{dx}\), which requires the chain rule for differentiation.3. **Differentiate the Exponent**: Calculate \(\frac{du}{dx}\), which involves differentiating the exponent \(-2x\). This results in \(-2\).4. **Combine the Results**: Substitute back \(-2x\) and \(-2\) into the derivative expression \(e^{u} \cdot \frac{du}{dx}\).5. **Simplify the Expression**: Simplify the result; in this example, multiplying gives \(-2e^{-2x}\). These steps ensure clarity and accuracy in differentiation processes, especially when dealing with complex composite functions.