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Use the limit laws to determine \(\lim _{n \rightarrow \infty} a_{n}=a .\) $$ \lim _{n \rightarrow \infty}\left(\frac{n+1}{n^{2}-1}\right) $$

Short Answer

Expert verified
The limit is 0.

Step by step solution

01

Identify the Dominant Terms

Examine the expression \( \frac{n+1}{n^2-1} \). In the numerator, the dominant term as \( n \to \infty \) is \( n \). In the denominator, the dominant term is \( n^2 \). Thus, this fraction behaves like \( \frac{n}{n^2} = \frac{1}{n} \).
02

Apply the Limit Laws

Using limit laws, split the fraction into its dominant terms to simplify \( \lim_{n \to \infty} \frac{n+1}{n^2-1} \) to \( \lim_{n \to \infty} \frac{1}{n} \), since lower degree terms \( +1 \) or \( -1 \) become negligible in infinity.
03

Calculate the Limit of the Dominant Terms

Calculate \( \lim_{n \to \infty} \frac{1}{n} \). As \( n \) approaches infinity, \( \frac{1}{n} \to 0 \). Hence, the original limit \( \lim_{n \to \infty} \frac{n+1}{n^2-1} = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Dominant Terms
When evaluating limits, especially as variables approach infinity, grasping which terms dominate is crucial. Dominant terms are those that grow significantly faster relative to others as the value of the variable increases. For the expression \(\frac{n+1}{n^2-1}\), recognizing dominant terms simplifies the limit calculation.- **Numerator Dominance**: In \(n+1\), as \(n\) approaches infinity, \(n\) is far more significant than \(+1\). Thus, \(n\) is the dominant term in the numerator. - **Denominator Dominance**: For \(n^2-1\), \(n^2\) increases much more quickly than \(-1\) as \(n\) grows. Therefore, \(n^2\) dominates the denominator.Realizing the dominance allows simplification. The fraction acts like \(\frac{n}{n^2} = \frac{1}{n}\). This reduced form makes it easier to calculate the limit as \(n\) grows.
The Concept of Infinity
Infinity is a fundamental idea in calculus that students often encounter when dealing with limits. To visualize infinity, we consider a number that keeps getting larger without bound. As \(n\) approaches infinity, it represents a direction rather than a specific number.- **Understanding Growth**: For polynomials, the higher the degree of the term, the faster it grows as \(n\) increases. For example, \(n^2\) grows faster than \(n\), which is why \(n^2\) is the dominant term in the denominator.- **The Behavior of Fractions**: As seen in \(\frac{1}{n}\), as \(n\) becomes extremely large, the fraction's value approaches zero. This behavior illustrates why smaller degree terms become negligible, allowing significant simplifications when finding limits at infinity.Recognizing the behavior of terms at infinity solidifies the concept of why certain terms dominate and others fade into insignificance.
Application of Limit Laws
Limit laws provide powerful shortcuts to find limits. They allow simplification of complex expressions into easily manageable parts. By applying these laws to the expression \(\lim_{n \to \infty} \frac{n+1}{n^2-1}\), the process becomes streamlined.- **Simplification**: We can observe that each term in the expression can be individually approached using rules like sum, product, and quotient laws. Here, dominant terms rule the behavior around infinity, thus the \(+1\) in the numerator and \(-1\) in the denominator become negligible.- **Resulting Limit**: Applying the laws leads us to consider \(\lim_{n \to \infty} \frac{1}{n}\), which is simpler to evaluate. Since \(\frac{1}{n}\) approaches zero as \(n\) tends towards infinity, the limit simplifies to zero.Understanding and utilizing these laws effectively reduce the complexity of finding limits, especially as they relate to dominant terms and the concept of infinity.

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Most popular questions from this chapter

In Problems 101-110, the sequence \(\left\\{a_{n} \mid\right.\) is recursively defined. Find all fixed points of \(\left[a_{n}\right\\} .\) $$ a_{n+1}=\frac{1}{2} a_{n}+2 $$

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