/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Assume that the population growt... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Assume that the population growth is described by the Beverton-Holt model. Find all fixed points. \(N_{t+1}=\frac{2 N_{t}}{1+N_{t} / 90}\)

Short Answer

Expert verified
Fixed points are 0 and 90.

Step by step solution

01

Understanding the Beverton-Holt Model

The Beverton-Holt model is a discrete-time population model. It is generally written in the form: \[ N_{t+1} = \frac{r N_{t}}{1+ \frac{N_{t}}{K}} \]where \( r \) is the growth rate and \( K \) is the carrying capacity. In this problem, the model is given by\[ N_{t+1} = \frac{2 N_{t}}{1+ \frac{N_{t}}{90}} \]which implies that \( r = 2 \) and \( K = 90 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete-Time Population Model
The Beverton-Holt model represents a type of discrete-time population model. Unlike continuous models, which update populations continuously over time, discrete models operate in phases or specific time steps, often reflecting changes season by season or year by year. In this case, we see population changes from one time step, denoted as \( N_t \), to the next, \( N_{t+1} \), according to a specific formula. This type of modeling is beneficial for understanding population dynamics in scenarios like wildlife management, where changes are more evident over distinct periods.
One advantage of using a discrete-time model is its simplicity and ease of application in simulations and calculations. It allows scientists and researchers to make predictions about the future population sizes based on current data, while also accounting for factors like initial population and environmental limitations. The Beverton-Holt model, in particular, is useful for predicting carrying capacity and population stabilization over time.
Fixed Points
In the context of the Beverton-Holt model, a fixed point refers to a population size where there is no change from one step to the next. Mathematically, this is when \( N_{t+1} = N_t \). Finding fixed points helps us understand stable population sizes where growth ceases naturally, either due to resource limitations or other environmental factors.
To find a fixed point in the given Beverton-Holt model \( N_{t+1} = \frac{2N_t}{1 + \frac{N_t}{90}} \), you set \( N_{t+1} = N_t \) and solve for \( N_t \). Fixed points often represent equilibrium states where population growth is balanced by available resources, offering insight into long-term sustainability and the effects of parameters like growth rate \( r \) and carrying capacity \( K \). In this exercise, solving results in \( N_t = 0 \) and \( N_t = 90 \), indicating the potential stable populations under given conditions.
Carrying Capacity
Carrying capacity, denoted as \( K \), is a key element in the Beverton-Holt model, and it represents the maximum population size an environment can support indefinitely. This concept is crucial in ecological studies as it reflects the balance between resource availability and population growth.
In the equation \( N_{t+1} = \frac{2N_t}{1 + \frac{N_t}{90}} \), the carrying capacity is 90. Essentially, this means that when the population size reaches 90, the rate of growth will stabilize, and the population will neither increase nor decrease significantly. At this point, resources are optimally utilized, preventing further growth without the risk of degradation to the environment.
  • High growth rates or sudden increases in population size might lead to overshooting carrying capacity, potentially resulting in population crashes.
  • If resources improve, the carrying capacity can increase, allowing for a larger sustainable population.
Understanding carrying capacity helps in designing conservation strategies, ensuring sustainable resource use, and anticipating challenges in changing environments.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Mountain Gorilla Conservation You are trying to build a mathematical model for the size of the population of mountain gorillas in a national park in Uganda. The data in this question are taken from Robbins et al. (2009). (a) You start by writing a word equation relating the population of gorillas \(t\) years after the study begins, \(N_{t}\), to the population \(N_{t+1}\) in the next year: \(N_{t+1}=N_{t}+\begin{array}{l}\text { number of gorillas } \\ \text { born in one year }\end{array}-\begin{array}{l}\text { number of gorillas } \\\ \text { that die in one yeai }\end{array}\) We will derive together formulas for the number of births and the number of deaths. (i) Around half of gorillas are female, \(75 \%\) of females are of reproductive age, and in a given year \(22 \%\) of the females of reproductive age will give birth. Explain why the number of births is equal to: \(\quad 0.5 \cdot 0.75 \cdot 0.22 \cdot N_{t}=0.0825 \cdot N_{t}\) (ii) In a given year \(4.5 \%\) of gorillas will die. Write down a formula for the number of deaths. (iii) Write down a recurrence equation for the number of gorillas in the national park. Assuming that there are 300 gorillas initially (that is \(N_{0}=300\) ), derive an explicit formula for the number of gorillas after \(t\) years. (iv) Calculate the population size after \(1,2,5\), and 10 years. (v) According to the model, how long will it take for population size to double to 600 gorillas? (b) In reality the population size is almost totally stagnant (i.e., \(N_{t}\) changes very little from year to year). Robbins et al. (2009) consider three different explanations for this effect: (i) Increased mortality: Gorillas are dying sooner than was thought. What percentage of gorillas would have to die each year for the population size to not change from year to year? (ii) Decreased female fecundity: Gorillas are having fewer offspring than was thought. Calculate the female birth rate (percentage of reproductive age females that give birth) that would lead to the population size not changing from year to year. Assume that all other values used in part (a) are correct. (iii) Emigration: Gorillas are leaving the national park. What number of gorillas would have to leave the national park each year for the population to not change from year to year?

The sequence \(\mid a_{n}\) \\} is recursively defined. Compute \(a_{n}\) for \(n=1,2, \ldots, 5\) $$ a_{n+1}=-2 a_{n}, a_{0}=1 $$

A population obeys the Beverton-Holt model. You know that \(R_{0}=4\) for this population. One year you measure \(N_{t}=50\). The next year you measure that \(N_{t+1}=40 .\) What value of \(a\) is needed in the model to fit these data?

Use the limit laws to determine \(\lim _{n \rightarrow \infty} a_{n}=a .\) $$ \lim _{n \rightarrow \infty}\left(\frac{3 n^{2}-5}{n}\right) $$

Use the formal definition of limits to show that \(\lim _{n \rightarrow \infty} a_{n}=a ;\) that is, find \(N\) such that for every \(\epsilon>0\), there exists an \(N\) such that \(\left|a_{n}-a\right|<\epsilon\) whenever \(n>N\). $$ \lim _{n \rightarrow \infty} e^{-2 n}=0 $$

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.