Chapter 2: Problem 109
The sequence \(\left\\{a_{n} \mid\right.\) is recursively defined. Find all fixed points of \(\left[a_{n}\right\\} .\) $$ a_{n+1}=\sqrt{5 a_{n}} $$
Short Answer
Expert verified
The fixed points are 0 and 5.
Step by step solution
01
Understanding Fixed Points
A fixed point for a sequence or function is a value that remains unchanged when applied to the function. For the given sequence, we are looking for a value of \(a_n\) such that it is equal to \(a_{n+1}\). This means we need to solve the equation \(a_n = \sqrt{5a_n}\).
02
Setting Up the Equation
To find the fixed points, set \(a_n = \sqrt{5a_n}\). This will give us an equation we can solve to find all values of \(a_n\) that satisfy this condition.
03
Solve the Equation
Start by squaring both sides of the equation to eliminate the square root: \[ a_n^2 = 5a_n \] Rearrange the equation: \[ a_n^2 - 5a_n = 0 \] Factor the quadratic equation: \[ a_n(a_n - 5) = 0 \] This gives us two possible solutions: either \(a_n = 0\) or \(a_n = 5\).
04
Validate the Fixed Points
Check if these solutions are indeed fixed points. For \(a_n = 0\): The condition becomes \(a_{n+1} = \sqrt{5 imes 0} = 0\). For \(a_n = 5\): The condition becomes \(a_{n+1} = \sqrt{5 imes 5} = \sqrt{25} = 5\). Both conditions hold, so \(a_n = 0\) and \(a_n = 5\) are indeed fixed points.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Recursive Sequences
A recursive sequence is a sequence in which each term is defined using one or more of the previous terms. This type of sequence gives us a powerful way to create functions and model behaviors where each step or term depends on the preceding ones. In our specific example, a recursive sequence is expressed with the formula \( a_{n+1} = \sqrt{5a_n} \), where each term \( a_{n+1} \) depends on the term before it, \( a_n \). There are important aspects to understand in recursive sequences:
- **Initial Condition**: To generate a recursive sequence, typically an initial term (or terms) must be given, which becomes the basis for generating the rest of the sequence.
- **Recursive Formula**: The rule or formula, which in our case is \( a_{n+1} = \sqrt{5a_n} \), describes how to calculate the next term based on previous terms.
- **Fixed Points**: These are special values within a sequence that remain constant when applied in the recursive formula, leading to a steady state.
Quadratic Equations
A quadratic equation is a second-degree polynomial, generally written as \( ax^2 + bx + c = 0 \). This type of equation is essential in many mathematical problems because they often appear when modeling real-world phenomena or solving problems involving squared terms. In our exercise, after applying the recursive formula, we derive a quadratic equation: \[ a_n^2 - 5a_n = 0 \]Here's how we approach solving it:
- **Factoring**: The expression is factored to \( a_n(a_n - 5) = 0 \), providing two potential solutions. This method involves expressing the quadratic in terms of two products equaling zero.
- **Zero Product Property**: Once factored, each factor is set to zero. This property states that if a product of factors equals zero, at least one of the factors must be zero. Hence, we find the solutions \( a_n = 0 \) or \( a_n = 5 \).
Square Roots
The square root operation is finding a number which, when multiplied by itself, gives the original number. It's commonly represented using the radical symbol \( \sqrt{} \). In this exercise, we're dealing with square roots through the recursive formula \( a_{n+1} = \sqrt{5a_n} \).Understanding square roots involves:
- **Principal Square Root**: This is the non-negative square root of a number. For example, \( \sqrt{16} = 4 \), because 4 is non-negative and \( 4^2 = 16 \).
- **Rational and Irrational Roots**: The results can be either rational (like \( \sqrt{25} = 5 \)) or irrational (like \( \sqrt{2} \)), depending on whether the original number is a perfect square.
- **Application in Functions**: In our fixed points problem, square roots are used to transform the sequence, impacting \( a_{n+1} \) directly. Manipulating equations involving square roots often requires caution such as squaring both sides to simplify, as done when solving for fixed points.