/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 130 Write each sum in sigma notation... [FREE SOLUTION] | 91Ó°ÊÓ

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Write each sum in sigma notation. \(\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\cdots+\frac{1}{2^{n}}\)

Short Answer

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\( \sum_{k=0}^{n} \frac{1}{2^k} \)

Step by step solution

01

Identify the Pattern

The sequence given is \( \frac{1}{1}, \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \cdots \). Each term can be expressed as \( \frac{1}{2^k} \), where \( k \) starts at 0 and increases by 1 for each subsequent term. The general term is therefore \( \frac{1}{2^k} \).
02

Determine the Range of the Summation Index

The terms start with \( \frac{1}{2^0} \) and continue up to \( \frac{1}{2^n} \). Hence, the index \( k \) should range from 0 to \( n \) to cover all terms from \( \frac{1}{2^0} \) to \( \frac{1}{2^n} \).
03

Write in Sigma Notation

Using the pattern and the range identified, the series can be expressed in sigma notation as: \[ \sum_{k=0}^{n} \frac{1}{2^k}. \] This denotes the sum of \( \frac{1}{2^k} \) from \( k = 0 \) to \( k = n \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sequences
Sequences are lists of numbers arranged in a particular, orderly fashion. In mathematical terms, they follow a specific rule or formula. Every number in the list is called a 'term'. Sequences can be either finite or infinite, depending on whether they have an end.
For example, in our provided sequence \( \frac{1}{1}, \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \cdots \), we see a pattern that each term is half of the previous one. This clear pattern demonstrates a well-defined sequence.
Understanding the pattern and rule of a sequence is the first step to solving problems like expressing them in sigma notation. It provides a gateway to analyzing and understanding more complex mathematical concepts such as series and sums.
Exploring Series
When we talk about a series, we refer to the sum of the terms of a sequence. If you’re adding up the numbers in a sequence, then you’re working with a series. Series are an essential concept in mathematics because they allow us to sum infinite sequences under certain rules.
Imagine our sequence transformed into a series: \( \frac{1}{1} + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots \). What we have now is an infinite series if it continues indefinitely. If it stops at a certain point, like at \( \frac{1}{2^n} \), it's a finite series.
Understanding series gives us the ability to explore their summations, find convergence, and analyze their behavior over large sequences.
Decoding the Summation Index
The summation index is a critical component when writing series in sigma notation. This index defines which terms in the series you are summing. It's essentially the guide post for your sum.
In the sigma notation \( \sum_{k=0}^{n} \frac{1}{2^k} \), \( k \) represents our summation index. Here it begins at 0 and goes up to \( n \). For each value of \( k \), the formula \( \frac{1}{2^k} \) gives us a specific term in the series.
By understanding the range and role of the summation index, you can better construct and interpret series written in sigma notation. It ensures no term is left out when calculating the total sum.
The Magic of Geometric Progression
Geometric progression is a specific type of sequence where each term is obtained by multiplying the previous term by a fixed, non-zero number called the 'common ratio'.
Our sequence \( \frac{1}{1}, \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \cdots \) is a perfect example of a geometric progression with the common ratio of \( \frac{1}{2} \). Each successive term is half of the previous term.
Recognizing a sequence as a geometric progression allows you to use formulas to find specific terms or the sum of terms in a series. For instance, the sum of the first \( n \) terms of a geometric series can be calculated using specific formulas, aiding in comprehensive analysis and simplification of complex problems.

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Most popular questions from this chapter

Mountain Gorilla Conservation You are trying to build a mathematical model for the size of the population of mountain gorillas in a national park in Uganda. The data in this question are taken from Robbins et al. (2009). (a) You start by writing a word equation relating the population of gorillas \(t\) years after the study begins, \(N_{t}\), to the population \(N_{t+1}\) in the next year: \(N_{t+1}=N_{t}+\begin{array}{l}\text { number of gorillas } \\ \text { born in one year }\end{array}-\begin{array}{l}\text { number of gorillas } \\\ \text { that die in one yeai }\end{array}\) We will derive together formulas for the number of births and the number of deaths. (i) Around half of gorillas are female, \(75 \%\) of females are of reproductive age, and in a given year \(22 \%\) of the females of reproductive age will give birth. Explain why the number of births is equal to: \(\quad 0.5 \cdot 0.75 \cdot 0.22 \cdot N_{t}=0.0825 \cdot N_{t}\) (ii) In a given year \(4.5 \%\) of gorillas will die. Write down a formula for the number of deaths. (iii) Write down a recurrence equation for the number of gorillas in the national park. Assuming that there are 300 gorillas initially (that is \(N_{0}=300\) ), derive an explicit formula for the number of gorillas after \(t\) years. (iv) Calculate the population size after \(1,2,5\), and 10 years. (v) According to the model, how long will it take for population size to double to 600 gorillas? (b) In reality the population size is almost totally stagnant (i.e., \(N_{t}\) changes very little from year to year). Robbins et al. (2009) consider three different explanations for this effect: (i) Increased mortality: Gorillas are dying sooner than was thought. What percentage of gorillas would have to die each year for the population size to not change from year to year? (ii) Decreased female fecundity: Gorillas are having fewer offspring than was thought. Calculate the female birth rate (percentage of reproductive age females that give birth) that would lead to the population size not changing from year to year. Assume that all other values used in part (a) are correct. (iii) Emigration: Gorillas are leaving the national park. What number of gorillas would have to leave the national park each year for the population to not change from year to year?

\(\lim _{n \rightarrow \infty} a_{n}=a\). Find the limit \(a\), and determine \(N\) so that \(\left|a_{n}-a\right|<\epsilon\) for all \(n>N\) for the given value of \(\epsilon\) $$ a_{n}=2^{-n}, \epsilon=0.01 $$

Use the limit laws to determine \(\lim _{n \rightarrow \infty} a_{n}=a .\) $$ \lim _{n \rightarrow \infty}\left(\frac{n^{2}+1}{n^{2}}\right) $$

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