Chapter 12: Problem 28
Fit a linear regression line through the given points and compute the coefficient of determination. \((0,0.1),(1,-1.3),(2,-3.5),(3,-5.7),(4,-5.8)\)
Short Answer
Expert verified
The regression line is \(y = -1.48x - 0.28\) with \(R² \approx 0.976\).
Step by step solution
01
Understand the Given Points
We have a set of data points: \((0, 0.1), (1, -1.3), (2, -3.5), (3, -5.7), (4, -5.8)\). These points need a linear regression line that best fits them.
02
Calculate Mean of x and y
Calculate the mean of x values: \(\bar{x} = \frac{0 + 1 + 2 + 3 + 4}{5} = 2\). Calculate the mean of y values: \(\bar{y} = \frac{0.1 + (-1.3) + (-3.5) + (-5.7) + (-5.8)}{5} = -3.24\).
03
Calculate Slope (m)
Use the formula for the slope: \(m = \frac{\sum{(x_i - \bar{x})(y_i - \bar{y})}}{\sum{(x_i - \bar{x})^2}}\). Calculating this: \(m = \frac{(0-2)(0.1+3.24) + (1-2)(-1.3+3.24) + (2-2)(-3.5+3.24) + (3-2)(-5.7+3.24) + (4-2)(-5.8+3.24)}{(0-2)^2 + (1-2)^2 + (2-2)^2 + (3-2)^2 + (4-2)^2}\). This gives \(m = -1.48\).
04
Calculate Y-Intercept (b)
The equation of the line is \(y = mx + b\). Substitute the means and slope to find \(b\): \(b = \bar{y} - m \bar{x} = -3.24 - (-1.48)(2) = -0.28\).
05
Write the Regression Line Equation
Substitute the slope and intercept into the equation of the regression line: \(y = -1.48x - 0.28\).
06
Compute the Coefficient of Determination (R²)
Find the total sum of squares (SST), the regression sum of squares (SSR), and the residual sum of squares (SSE). SST = \(\sum{(y_i - \bar{y})^2}\), SSE = \(\sum{(y_i - (mx_i + b))^2}\), and R² = \(1 - \frac{SSE}{SST}\). Substitute and calculate the values to get \(R² \approx 0.976\).
07
Conclude with the Regression Result
The best-fit line through the points is \(y = -1.48x - 0.28\) with a coefficient of determination \(R² \approx 0.976\), meaning around 97.6% of the data variation is explained by this line.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coefficient of Determination
The Coefficient of Determination, often denoted as R², is a key metric in linear regression and statistics. It indicates how well data fits a statistical model, specifically a linear regression model like the one we work with here.
R² ranges from 0 to 1. A value of 0 suggests that the line does not explain any of the variability of the data points, while a value of 1 indicates the line perfectly explains all of the variability. In practical terms, the closer R² is to 1, the better the line fits the data.
For our linear regression exercise, we computed an R² value of approximately 0.976. This high value indicates that the best-fit line quite effectively models the data. About 97.6% of the variance in the y-values is accounted for by the regression line, signifying a substantial relationship between the variables. Understanding R² helps in evaluating the predictive power and accuracy of your linear model.
Slope and Intercept Calculation
Calculating the slope and y-intercept is crucial for establishing the equation of the best-fit line in linear regression. The slope, represented by the letter \( m \), quantifies the change in the y-value for each unit change in the x-value. The y-intercept, denoted by \( b \), is the value of y when x is zero.
- To determine the slope \( m \), we use the formula:\[ m = \frac{\sum{(x_i - \bar{x})(y_i - \bar{y})}}{\sum{(x_i - \bar{x})^2}} \]In our exercise, this calculation gives us \( m = -1.48 \), indicating a negative relationship between x and y.
- The y-intercept \( b \) is calculated using:\[ b = \bar{y} - m \bar{x} \]Substituting the values from our data, we find \( b = -0.28 \).
Best-Fit Line
Creating a best-fit line is a foundational step in analyzing data using linear regression. A best-fit line provides a visual representation of the relationship between two variables on a scatter plot. It minimizes the deviations of the data points from the line, providing an optimal representation of the data set's trend. For our set of points \((0,0.1),(1,-1.3),(2,-3.5),(3,-5.7),(4,-5.8)\), the goal is to find the line that best describes their linear relationship. The equation we derive, \( y = -1.48x - 0.28 \), is a direct outcome of calculating the slope and intercept.You might wonder why we bother with a best-fit line. This line is the foundation for predictions, allowing us to estimate new y-values for given x-values. It also helps in understanding the correlation strength between variables. Overall, the best-fit line enhances the comprehension of data trends, making linear regression a powerful tool for data analysis.