Chapter 12: Problem 28
A bookstore has 300 science fiction books. Molly wants to buy 5 of the 300 science fiction books. How many selections are there?
Short Answer
Expert verified
There are 20,002,900 ways to select 5 books from 300 science fiction books.
Step by step solution
01
Understanding the Problem
Molly wants to select 5 science fiction books from a total of 300 books available at the bookstore. This problem involves a combination selection where the order of selection doesn't matter.
02
Identifying the Formula
When choosing a certain number of items (in this case, 5 books) from a larger group (300 books) without regard to the order of selection, we use the combination formula. The formula for combinations is: \[ C(n, r) = \frac{n!}{r!(n-r)!} \] where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
03
Substituting the Values
In this problem, \( n = 300 \) and \( r = 5 \). We substitute these values into the combination formula:\[ C(300, 5) = \frac{300!}{5!(300 - 5)!} \]
04
Calculating the Factorials
First, we simplify the expression by calculating the factorials:\( 300! \) is very large, but can be simplified as \[ 300 \times 299 \times 298 \times 297 \times 296 \] because everything else would cancel out with the factorial in the denominator. Then calculate \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \]
05
Simplifying the Calculation
Now substitute these into the simplified expression:\[ C(300, 5) = \frac{300 \times 299 \times 298 \times 297 \times 296}{5 \times 4 \times 3 \times 2 \times 1} \] which simplifies to a numerical answer.
06
Final Calculation
Calculating the fraction gives:\[ C(300, 5) = \frac{300 \times 299 \times 298 \times 297 \times 296}{120} \] Performing this calculation results in a large number of possible selections.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Combination Formula
The combination formula is a key concept in combinatorics used to determine the number of ways to choose a subset of items from a larger set, where the order of selection doesn't matter. It is especially handy when you want to know how many different groups of "r" items can be formed from a larger group of "n" items. The formula is given by:
- \[ C(n, r) = \frac{n!}{r!(n-r)!} \]
- \( n \) is the total number of items to choose from.
- \( r \) is the number of items to be chosen.
- The "!" symbol represents the factorial of a number, which is the product of all positive integers up to that number.
Factorials
Factorials play a foundational role in combinatorics, particularly with the combination formula. The factorial of a number, denoted as \( n! \), is the product of all positive integers less than or equal to \( n \). It’s a way of calculating products for sequences of decreasing natural numbers.
For example:
For example:
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
- \( 3! = 3 \times 2 \times 1 = 6 \)
- \( 0! = 1 \) (by definition)
Permutations
Permutations relate to arranging a subset of a larger set of items where the order does matter. It's different from combinations, where the order does not matter. In permutations, each possible arrangement of the items counts as a unique permutation.
The formula for permutations is:
The formula for permutations is:
- \[ P(n, r) = \frac{n!}{(n-r)!} \]
- \( n \) is the total number of items.
- \( r \) is the number of items to arrange.