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In the first step of glycolysis, what is glucose transformed into? a. glucose----phosphate b. fructose- \(1,6\) -bisphosphate c. dihydroxyacetone phosphate d. phosphoenolpyruvate

Short Answer

Expert verified
a. glucose----phosphate

Step by step solution

01

Understand Glycolysis

Glycolysis is the process of breaking down glucose into pyruvate to release energy. It consists of many steps, each transforming the molecule further.
02

Identify the First Step of Glycolysis

The first step of glycolysis involves the phosphorylation of glucose. Here, a phosphate group is added to glucose to form glucose-6-phosphate.
03

Analyze the Answer Choices

Look at the provided options: a. glucose----phosphate b. fructose-1,6-bisphosphate c. dihydroxyacetone phosphate d. phosphoenolpyruvate. Out of these, the correct product formed in the first step is glucose-6-phosphate.
04

Select the Correct Answer

Based on the analysis, the closest answer provided in the list is a. glucose----phosphate. This refers to glucose-6-phosphate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Glucose Phosphorylation
In the first step of glycolysis, glucose undergoes phosphorylation. This is a crucial initial step in the metabolic process that breaks down glucose to release energy. During glucose phosphorylation, a phosphate group from ATP is transferred to the glucose molecule. This process is catalyzed by the enzyme hexokinase. Hexokinase facilitates the transfer by binding both ATP and glucose and helping the phosphate group make the jump. As a result of this transfer, ATP (adenosine triphosphate) is converted into ADP (adenosine diphosphate). The phosphorylated glucose molecule is now known as glucose-6-phosphate.
This modification is significant because it helps trap the glucose molecule inside the cell, as glucose-6-phosphate cannot easily pass through the cell membrane. It is also key because it makes the glucose molecule more reactive, facilitating its further breakdown in the subsequent steps of glycolysis.
Glucose-6-Phosphate
After glucose is phosphorylated, it is transformed into a molecule known as glucose-6-phosphate. This compound plays a pivotal role not only in glycolysis but also in other metabolic pathways like the pentose phosphate pathway and glycogenesis. Glucose-6-phosphate is a six-carbon sugar with a phosphate group attached to the sixth carbon atom. This phosphorylation is strategically essential:
  • It prevents the molecule from leaving the cell.
  • It marks the molecule for further processing in the glycolysis sequence.
  • It increases the energy potential of the molecule, making it more amenable to subsequent enzymatic actions.
The enzyme that catalyzes this reaction, hexokinase, has a high affinity for glucose, ensuring the efficient processing of even small amounts of glucose that enter the cell. Additionally, this step uses one molecule of ATP, showcasing the role of ATP as an energy-investing molecule early in glycolysis.
Energy Release in Glycolysis
Energy release is the primary purpose of glycolysis, which includes multiple enzyme-catalyzed steps to systematically break down glucose. Though the pathway starts with an energy investment phase, where ATP is consumed, the later stages lead to a net gain of energy. This breakdown process results in the production of two molecules of pyruvate, along with a net gain of two ATP molecules and two NADH molecules.
The energy release occurs in the latter stages through substrate-level phosphorylation, where a phosphate group is directly transferred to ADP, forming ATP. This occurs twice in one cycle of glycolysis, doubling the ATP yield from the initial investment. Also, NAD+ is reduced to NADH, capturing high-energy electrons, which can produce more ATP in the electron transport chain, though this occurs outside glycolysis. Therefore, glycolysis serves as a fundamental mechanism for energy extraction from glucose, providing quick ATP while setting the stage for more efficient energy production in cellular respiration.

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Most popular questions from this chapter

What compound receives electrons from NADH? a. FMN b. ubiquinone c. cytochrome c1 d. oxygen

How do the roles of ubiquinone and cytochrome c differ from the other components of the electron transport chain? a. CoQ and cytochrome c are mobile electron carriers while NADH dehydrogenase and succinate dehydrogenase are bound to the inner mitochondrial membrane. b. CoQ and cytochrome covalently bind electrons while NADH dehydrogenase and succinate dehydrogenase are bound to the inner mitochondrial membrane. c. CoQ and cytochrome c are bound to the inner mitochondrial membrane while NADH dehydrogenase and succinate dehydrogenase are mobile electron carriers. d. CoQ and cytochrome c covalently bind electrons while NADH dehydrogenase and succinate dehydrogenase are mobile electron carriers.

27\. Which statement best explains how electrons are transferred and the role of each species. Remember that \(\mathrm{R}\) represents a hydrocarbon molecule and \(\mathrm{RH}\) represents the same molecule with a particular hydrogen identified. \(\mathrm{RH}+\mathrm{NAD}^{+} \rightarrow \mathrm{N} \mathrm{ADH}+\mathrm{R}\) a. \(\mathrm{RH}\) acts as a reducing agent and donates its electrons to the oxidizing agent \(\mathrm{NAD}^{+}\) forming \(\mathrm{NADH}\) and \(\mathrm{R}\) . b. \(\mathrm{NAD}^{+}\) , the oxidizing agent, donates its electrons to the reducing agent \(\mathrm{RH},\) forming \(\mathrm{R}\) and \(\mathrm{NADH}\) . c. \(\mathrm{RH}\) acts as an oxidizing agent and donates electrons to the reducing agent \(\mathrm{NAD}^{+}\) producing \(\mathrm{NADH}\) and \(\mathrm{R}\) . d. \(\mathrm{NAD}^{+},\) the reducing agent, accepts electrons from the oxidizing agent \(\mathrm{RH}\) , producing NADH and \(\mathrm{R} .\)

How many ATP molecules are used and produced per molecule of glucose during glycolysis? a. The first half of glycolysis uses 2 ATPs, and the second half of glycolysis produces 4 ATPs. b. The first half of glycolysis produces 2 ATPs, and the second half of glycolysis uses 4 ATPs. c. The first half of glycolysis uses 4 ATPs, and the second half of glycolysis produces 2 ATPs. d. The first half of glycolysis produces 4 ATPS, and the second half of glycolysis uses 2 ATPs.

How does citrate from the citric acid cycle affect glycolysis? a. Citrate and ATP are negative regulators of phosphofructokinase-1. b. Citrate and ATP are negative regulators of hexokinase. c. Citrate and ATP are positive regulators of phosphofructokinase-1. d. Citrate and ATP are positive regulators of hexokinase.

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