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If mRNA is complementary to the DNA template strand and the DNA template strand is complementary to the DNA nontemplate strand, then why are base sequences of mRNA and the DNA nontemplate strand not identical? Could they ever be?

Short Answer

Expert verified

Only after the RNA polymerase finds a complementary base pair with the DNA sequence does transcription occur, resulting in an mRNA sequence that can be translated into amino acids. Because DNA and RNA have different nitrogenous bases, the nucleotide sequences of mRNA and a nontemplate strand of DNA can never be discovered to be identical.

Step by step solution

01

step-1: Definition

The template strand is the one used by RNA polymerase to construct the RNA. This strand is also known as the antisense or non-coding strand.

The non-template strand has the same RNA sequence as the template strand (except for the substituion of U for T). This strand is often referred to as the coding or sensing strand.

02

step-2: Introduction

RNA polymerase performs DNA transcription, which is the process of copying information from a DNA strand to mRNA for further translation. Genetic information is converted from DNA to mRNA and then to amino acids, which are then converted to protein, using these two steps.

03

step-3: Explanation

DNA (Deoxyribonucleic acid), which carries genetic information, is not the same as RNA (ribonucleic acid) (Ribonucleic acid). The nitrogenous bases adenine, cytosine, and guanine are found in both DNA and RNA, however DNA differs from RNA when it comes to the fourth nitrogenous base. The fourth nitrogenous base in DNA is thymine, which also contains deoxyribose sugar, but the fourth nitrogenous base in RNA is uracil, which also contains ribose sugar.

The RNA polymerase enzyme, which is complementary to the DNA template, creates the mRNA strand. The transcription initiation complex, which is made up of transcription factors and RNA polymerase, kicks off mRNA synthesis by matching complimentary nucleotides to the DNA template. RNA polymerase copies information from the template strand to the coding strand, replacing C with G, G with C, A with U, and T with A.

Transcription factors and RNA polymerase must find complementary base pairs to begin transcription. For transcribing sequence, RNA polymerase must recognize complementary base pairs on the template strand of DNA.

As a result, the base sequence of mRNA and the non-template strand of DNA can never be the same.

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Most popular questions from this chapter

Which event contradicts the central dogma of molecular biology?

a. Poly-A polymerase enzymes process mRNA in the nucleus.

b. Endonuclease enzymes splice out and repair damaged DNA.

c. Scientists use reverse transcriptase enzymes to make DNA from RNA.

d. Codons specifying amino acids are degenerate and universal.

Discuss how degeneracy of the genetic code makes cells more robust to mutations.

Figure 15.16 Many antibiotics inhibit bacterial protein synthesis. For example, tetracycline blocks the A site on the bacterial ribosome, and chloramphenicol blocks peptidyl transfer. What specific effect would you expect each of these antibiotics to have on protein synthesis?

Tetracycline would directly affect:

a. tRNA binding to the ribosome

b. ribosome assembly

c. growth of the protein chain

Chloramphenicol would directly affect

a. tRNA binding to the ribosome

b. ribosome assembly

c. growth of the protein chain

How do enhancers and promoters differ?

a. Enhancers bind transcription factors to silence gene expression, while promoters activate transcription.

b. Enhancers increase the efficiency of gene expression, but are not essential for transcription. Promoter recognition is essential to transcription initiation.

c. Promoters bind transcription factors to increase the efficiency of transcription. Enhancers bind RNA polymerases to initiate transcription.

d. There is no difference. Both are transcription factor-binding sequences in DNA.

Chronic lymphocytic leukemia patients often harbor nonsense mutations in their spliceosome machinery. Describe how this mutation of the spliceosome would change the final location and sequence of a pre-mRNA.

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