/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Gravitational Force. The gravita... [FREE SOLUTION] | 91Ó°ÊÓ

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Gravitational Force. The gravitational force \(F\) between two bodies of masses \(m_{1}\) and \(m_{2}\) is given by the equation $$ F=\frac{G m_{1} m_{2}}{r^{2}} $$ where \(G\) is the gravitational constant \(\left(6.672 \times 10^{-11} \mathrm{~N} \mathrm{~m}^{2} / \mathrm{kg}^{2}\right), m_{1}\) and \(m_{2}\) are the masses of the bodies in kilograms, and \(r\) is the distance between the two bodies. Write a function to calculate the gravitational force between two bodies given their masses and the distance between them. Test your function by determining the force on an \(800-\mathrm{kg}\) satellite in orbit \(38,000 \mathrm{~km}\) above the Earth. (The mass of the Earth is \(5.98 \times 10^{24} \mathrm{~kg}\).)

Short Answer

Expert verified
The gravitational force between Earth and an 800kg satellite in orbit 38,000km above Earth is calculated using the Universal Law of Gravitation with the provided formula: \(F=\frac{G m_{1} m_{2}}{r^{2}}\), where G is the gravitational constant, masses are given in kg, and distance in meters. By plugging in the values, \(F=\frac{6.674 \times 10^{-11} \times 5.98 \times 10^{24} \times 800}{(38000000)^{2}}\), we find the gravitational force to be approximately 3374.34 N.

Step by step solution

01

Understanding the Universal Law of Gravitation

The Universal Law of Gravitation is described by the equation \(F=\frac{Gm_{1}m_{2}}{r^{2}}\), where \(F\) is the force of gravity, \(G\) is the gravitational constant (\(6.674 \times 10^{-11} N(m/kg)^2 \)), \(m_1\) and \(m_2\) are the masses of the two objects, and \(r\) is the distance between the centers of the two objects.
02

Writing a function for gravitational force

The goal is to write a function that takes in the masses of the bodies and the distance between them and returns the gravitational force between them. The function would look something like this in a pseudocode: ``` function gravitational_force(m1, m2, r): G = 6.674 * 10^-11 F = (G * m1 * m2) / (r^2) return F ``` This function is written in pseudocode, an approximate version of the actual code that can be implemented in any specific programming language.
03

Applying the function to the given scenario

We are given that a satellite with a mass of 800kg is in orbit 38000km above Earth (which has a mass of \(5.98 \times 10^{24} kg \)). In order to apply previous function to this scenario, the distance \(r\) needs to be in meters as \(G\) is in \(N(m/kg)^2\). So convert 38000km to meters: \(38000km = 38000000m \) Now, we can use the function as follows: ``` F = gravitational_force(5.98 * 10^24, 800, 38000000) ``` This would calculate the gravitational force on the satellite due to Earth. Remember that the distances and masses need to be in the correct units for this to work properly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Universal Law of Gravitation
Understanding the Universal Law of Gravitation is crucial for calculating the force of attraction between two masses, like a satellite and the Earth. This principle states that every mass in the universe attracts every other mass with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

The equation encompassing this law is an essential part of physics, expressed as \( F = \frac{G m_{1} m_{2}}{r^{2}} \), where \( F \) stands for the gravitational force, \( G \) is the gravitational constant, \( m_{1} \) and \( m_{2} \) are the masses of two objects, and \( r \) is the distance between their centers. By applying this fundamental understanding, it becomes easier to grasp concepts such as orbital mechanics, tides, and the motion of celestial bodies.
MATLAB function writing
In a MATLAB environment, function writing is a powerful tool used for performing repeatable tasks efficiently. To write a function that calculates the gravitational force, you start by defining the function name and then include arguments that represent variables like mass and distance. In our context, the function to calculate gravitational force would be defined in MATLAB as follows:

Function Definition

function F = gravitational_force(m1, m2, r)G = 6.674 * 10^-11; % Gravitational constantF = (G * m1 * m2) / r^2; % Calculating forceend
After defining the function, you can call it with specific values for \( m_{1} \) and \( m_{2} \) and \( r \) to compute the gravitational force. It's important to ensure all variables are in compatible units, like kilograms for mass and meters for distance, to get an accurate result.
Gravitational constant
The gravitational constant, denoted by \( G \), is a key value in the equation for gravitational force. Its value is approximately \( 6.674 \times 10^{-11} \text{N} (\text{m/kg})^2 \). This constant provides the proportionality factor needed to calculate the gravitational force accurately in accordance with the Universal Law of Gravitation.

The magnitude of \( G \) reveals the inherent weakness of gravity compared to other fundamental forces; however, its effects are significant over large distances and masses, which is why planets orbit stars, and galaxies hold together. Without this constant, it would be impossible to predict the gravitational attraction and understand the scale of forces that govern the motion of celestial bodies.
Mass and distance in physics
Mass and distance are essential concepts in physics, especially when dealing with gravitational forces. Mass, measured in kilograms, represents the amount of matter in an object and is a determinant of the gravitational pull an object can exert. In our problem, we had the Earth's mass and the satellite's mass which, when multiplied together, show the combined effect on the gravitational force.

Distance, represented by \( r \) in the law of gravitation, is the separation between the centers of mass of the two objects involved. It is crucial to note that the gravitational force is inversely proportional to the square of the distance, meaning that as distance increases, the force declines rapidly. For example, increasing the altitude of a satellite reduces the gravitational force it experiences from Earth. This interplay of mass and distance governs not only the force exerted but also the dynamics of orbits and is foundational to understanding many principles of astrophysics and cosmology.

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Most popular questions from this chapter

What are the advantages and disadvantages of the pass-by-value scheme used in MATLAB?

Write three MATLAB functions to caiculate the hyperbolic sine, cosine, and tangent functions. $$ \sinh (x)=\frac{e^{x}-e^{-x}}{2}, \cosh (x)=\frac{e^{x}+e^{-x}}{2}, \tanh (x)=\frac{e^{x}-e^{-x}}{e^{x}+e^{-x}} $$ Use your functions to plot the shapes of the hyperbolic sine, cosine, and tangent functions.

Dice Simulation. It is often useful to be able to simulate the throw of a fair die. Write a MATLAB function dice that simulates the throw of a fair die by returning some random integer between 1 and 6 every time that it is called. (Hint: Call randomo to generate a randem number. Divide the possible values out of random0 into six equal intervals, and return the number of the interval that a given random value falls into.)

Rayleigh Distribution. The Rayleigh distribution is another random number distribution that appears in many practical problems. A Rayleighdistributed random value can be created by taking the square root of the sum of the squares of two normally distributed random values. In other words, to generate a Rayleigh-distributed random value \(r\) get two normally distributed random values \(\left(n_{1}\right.\) and \(\left.n_{2}\right)\), and perform the following calculation. $$ r=\sqrt{n_{1}^{2}+n_{2}^{2}} $$ a. Create a function rayleigh \((\mathrm{n}, \mathrm{m})\) that returns an \(\mathrm{n} \mathrm{x} \mathrm{m}\) array of Rayleigh-distributed random numbers. If only one argument is supplied [rayleigh \((\mathrm{n})\) ], the function should return an \(\mathrm{n} \times \mathrm{n}\) array of Rayleigh- distributed random numbers. Be sure to design your function with input argument checking and with proper documentation for the MATLAB help system. b. Test your function by creating an array of 20,000 Rayleigh-distributed random values and plotting a histogram of the distribution. What does the distribution look like? c. Determine the mean and standard deviation of the Rayleigh distribution.

Derivative of a Function. The derivative of a continuous function \(f(x)\) is defined by the equation $$ \frac{d}{d x} f(x)=\lim _{\Delta x=0} \frac{f(x+\Delta x)-f(x)}{\Delta x} $$ In a sampled function, this definition becomes $$ f^{\prime}\left(x_{i}\right)=\frac{f\left(x_{i+1}\right)-f\left(x_{i}\right)}{\Delta x} $$ where \(\Delta x=x_{i+1}-x_{i}\) Assume that a vector vect contains nsamp samples of a function taken at a spacing of \(d x\) per sample. Write a function that will calculate the derivative of this vector from Equation (5.12). The function should check to make sure that \(\mathrm{dx}\) is greater than zero to prevent divide-by-zero errors in the function. To check your function, you should generate a data set whose derivative is known, and compare the result of the function with the known correct answer. A good choice for a test function is \(\sin x\). From elemen\(\operatorname{tary}\) calculus, we know that \(\frac{d}{d x}(\sin x)-\cos x\). Generate an input vector containing 100 values of the function \(\sin x\) starting at \(x=0\) and using a step size \(\Delta x\) of \(0.05\). Take the derivative of the vector with your function, and then compare the resulting answers to the known correct answer. How close did your function come to calculating the correct value for the derivative?

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