Chapter 14: Problem 6
Test significance and find effect sizes (if significant) for the following tests: 1\. \(N=19, R=3, C=2, \chi 2(2)=7.89, \alpha=.05\) 2\. \(N=12, R=2, C=2, \chi 2(1)=3.12, \alpha=.05\) 3\. \(N=74, R=3, C=3, \chi 2(4)=28.41, \alpha=.01\)
Short Answer
Expert verified
Tests 1 and 3 are significant with effect sizes 0.643 and 0.439, respectively.
Step by step solution
01
Determine Degree of Freedom (df) for Test 1
The degrees of freedom for a chi-square test are calculated using the formula \(df = (R - 1) \times (C - 1)\). For Test 1, where \(R = 3\) and \(C = 2\), we have \(df = (3 - 1) \times (2 - 1) = 2\).
02
Compare Test 1 Chi-Square Value with Critical Value
Using \(df = 2\) and \(\alpha = 0.05\), the critical chi-square value from the table is approximately 5.99. Since \(\chi^2 = 7.89\) is greater than 5.99, we reject the null hypothesis, indicating a significant result.
03
Calculate Effect Size for Test 1 (Cramér's V)
Cramér's V is given by \( V = \sqrt{\frac{\chi^2}{N \times (\min(R,C) - 1)}}\), where \(N = 19\), \(R = 3\), and \(C = 2\). Calculate \( V = \sqrt{\frac{7.89}{19 \times (2 - 1)}} = \sqrt{\frac{7.89}{19}} = 0.643\).
04
Determine Degree of Freedom (df) for Test 2
For Test 2, \(R = 2\) and \(C = 2\), so \(df = (2 - 1) \times (2 - 1) = 1\).
05
Compare Test 2 Chi-Square Value with Critical Value
Using \(df = 1\) and \(\alpha = 0.05\), the critical chi-square value is approximately 3.84. Since \(\chi^2 = 3.12\) is less than 3.84, we do not reject the null hypothesis, indicating the result is not significant.
06
Degree of Freedom (df) and Comparison for Test 3
For Test 3, \(R = 3\) and \(C = 3\), the degrees of freedom are \(df = (3 - 1) \times (3 - 1) = 4\). With \(\alpha = 0.01\), the critical chi-square value is approximately 13.28. Since \(\chi^2 = 28.41\) is greater than 13.28, we reject the null hypothesis, indicating a significant result.
07
Calculate Effect Size for Test 3 (Cramér's V)
Using the formula \( V = \sqrt{\frac{\chi^2}{N \times (\min(R,C) - 1)}}\), where \(\chi^2 = 28.41\), \(N = 74\), \(R = 3\), and \(C = 3\), we find \( V = \sqrt{\frac{28.41}{74 \times (3 - 1)}} = \sqrt{\frac{28.41}{148}} = 0.439\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
chi-square critical value
The chi-square critical value is a key component in statistical hypothesis testing, especially when performing a chi-square test. This value acts as a threshold to determine whether the result of your test is significant or not. In simple terms, it's a cutoff point derived from the chi-square distribution table, which tells you how extreme a test statistic must be to reject the null hypothesis in favor of the alternative hypothesis.
To find the chi-square critical value, you'll need two things:
To find the chi-square critical value, you'll need two things:
- The level of significance, denoted as \( \alpha \), which reflects the probability of rejecting the null hypothesis when it's true (also known as Type I error). Common choices are \( \alpha = 0.05 \) or \( \alpha = 0.01 \).
- The degrees of freedom (df), which we calculate based on the number of categories in our data.
degrees of freedom in statistics
Degrees of freedom are a fundamental concept in many statistical analyses, not just the chi-square test. In statistics, they refer to the number of values in a calculation that are free to vary. When it comes to chi-square tests, the degrees of freedom are determined by the structure of the categorical data.
The formula to find degrees of freedom in a chi-square test is \( df = (R - 1) \times (C - 1) \), where \( R \) is the number of rows and \( C \) is the number of columns in a contingency table.
The formula to find degrees of freedom in a chi-square test is \( df = (R - 1) \times (C - 1) \), where \( R \) is the number of rows and \( C \) is the number of columns in a contingency table.
- For Test 1 with \( R = 3 \) and \( C = 2 \), we calculated \( df = (3 - 1) \times (2 - 1) = 2 \).
- For Test 2, given \( R = 2 \) and \( C = 2 \), \( df = (2 - 1) \times (2 - 1) = 1 \).
- For Test 3, with \( R = 3 \) and \( C = 3 \), \( df = (3 - 1) \times (3 - 1) = 4 \).
Cramér's V effect size
Cramér's V is an effect size measurement used to quantify the strength of association between two categorical variables in a chi-square test. It's particularly valuable because it provides insight beyond mere statistical significance.
Statistical significance, shown by surpassing the chi-square critical value, only tells us whether an association exists. Cramér's V offers additional detail about how strong that association is. The formula for Cramér's V is:\[V = \sqrt{\frac{\chi^2}{N \times (\min(R, C) - 1)}}\]where \( \chi^2 \) is the chi-square statistic, \( N \) is the total number of observations, and \( \min(R, C) \) is the smaller of the number of rows or columns.
Statistical significance, shown by surpassing the chi-square critical value, only tells us whether an association exists. Cramér's V offers additional detail about how strong that association is. The formula for Cramér's V is:\[V = \sqrt{\frac{\chi^2}{N \times (\min(R, C) - 1)}}\]where \( \chi^2 \) is the chi-square statistic, \( N \) is the total number of observations, and \( \min(R, C) \) is the smaller of the number of rows or columns.
- In Test 1, we calculated \( V = 0.643 \), indicating a moderate to strong association.
- In Test 3, \( V = 0.439 \) shows a moderate strength of association.