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Which side has the scratches? One side of the plastic of your diffraction grating is smooth; the other side has the scratches. You can find out which side has the scratches by looking through it at a white source after rubbing one side of the grating with an oily finger; then clean it and try the other side. What is the explanation?

Short Answer

Expert verified
The side that still shows a clear diffraction pattern after being rubbed with oil has the scratches.

Step by step solution

01

Understanding Diffraction Grating

A diffraction grating is an optical component with a pattern of closely spaced grooves or scratches on its surface. These grooves create an interference pattern of light, allowing us to see spectra.
02

Purpose of Oily Finger

Rubbing one side of the grating with an oily finger makes that side slightly blurrier by filling in the grooves or scratches. This is used to test which side has the scratches because if interference patterns appear when looking through the grating, the light is interacting with those structural grooves.
03

Observing Through Grating

Look through the grating at a white light source after rubbing one side. Note the visibility of diffraction patterns or spectra. Clean the grating and repeat on the other side.
04

Identifying Scratched Side

The side that still shows a clear diffraction pattern after being rubbed with oil is the scratched side. The oil does not disrupt the pattern; thus, light still interacts with the grooves in the same manner.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interference Pattern
When you look through a diffraction grating at a white light, you'll notice something intriguing called an interference pattern. This pattern appears because the diffraction grating contains many closely spaced grooves or scratches. These scratches act like tiny slits, causing the light to spread out, or diffract, and then overlap, or interfere, with each other.
Once the light waves interfere, they either strengthen each other (constructive interference) or cancel each other out (destructive interference). This process creates a pattern of bright and dark areas, which we see as colorful spectra. The visible pattern depends on the wavelengths of the light and the spacing of the scratches.
  • Constructive interference results in bright bands.
  • Destructive interference leads to dark bands.
Identifying such patterns helps determine the structure and quality of the grating, making it a vital tool in scientific and educational applications.
Optical Component
A diffraction grating, often made of plastic or glass, is an optical component used to separate light into its spectral components. It is designed with a surface coated with numerous parallel grooves. This design allows it to manipulate light through interference and diffraction. Here's why diffraction gratings are important:
  • They help separate and analyze different wavelengths of light, crucial in spectrometers.
  • They are used in various optical instruments to measure properties of light.
  • They are pivotal in analyzing light from stars and other celestial objects to determine composition.
By understanding the interaction between light and this optical component, students can gain deeper insights into physical optics and how light behaves under different conditions.
Light Spectrum
The light spectrum is a range of all possible frequencies of electromagnetic radiation. When you pass white light through a diffraction grating, the grating spreads out the light into its component colors or wavelengths, forming a spectrum. Each color within the spectrum represents light at a different wavelength. This concept is fundamental in understanding how we perceive different colors and how they relate to physical phenomena:
  • Visible light ranges from around 380 nm (violet) to 750 nm (red).
  • Each wavelength is diffracted at a specific angle by the grating.
  • The resulting spectrum reveals the unique signature of the light source, useful in spectroscopic analysis.
Thus, a diffraction grating serves as a simple yet powerful tool to explore the light spectrum and to study the properties of light beyond the visible range.

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Most popular questions from this chapter

Use your diffraction grating as follows to measure the wavelengths of the red and green passed by your filters. Put a line (or point) source right next to a wall or door. Make a mark on the wall about a foot to the side of the source. Look at the source through the grating, holding the filter over your grating (or put the filter over the source-but don't melt it!) Move closer and farther from the source until the color of interest appears to be superposed with your mark on the wall. Measure the appropriate distances and calculate \(\lambda\). Thus calibrate the wavelengths transmitted by your red, green, and purple filters. Memorize the results. (Then you can use your filters and the grating to find the wavelengths of other colors when you wish to, without repeating the geometric measurement of this experiment.)

Pour some table salt on a wet knife or spoon (one that you don't mind ruining). Set the knife in the flame of a gas stove. Look at the yellow flame through your diffraction grating (this is easiest at night in a darkened room). Notice that the first-order (and higher-order) images of the yellow sodium flame are as sharp and clear as the zeroth-order "direct" image. That is because the yellow light is a "spectral line" having narrow bandwidth. (Actually the yellow light from sodium is a "doublet" of two lines with wavelengths 5890 and \(5896 \AA\).) Now look at a candle. In zeroth order, it does not look terribly different from the sodium flame; they are both yellow. But in the first-order diffraction image, the candle is very much spread out in color, whereas the sodium remains sharp. The "yellow" of the candle, which is due to hot particles of carbon, has a wavelength spectrum extending over (and beyond) the entire visible range. Here are other convenient sources of sharp spectral lines; look at them through your grating: Mercury vapor: Fluorescent lamps, mercury-vapor street lights, sunlamps. (A sunlamp is convenient in that it screws directly into an ordinary 110 -volt AC socket. It is probably the cheapest source of mercury-vapor spectral lines; the cost is about \(\$ 10 .\).) Neon: Many advertising signs. Neon has a profusion of lines; you see "many signs." A cheap broad monochromatic source is a G.E. bulb NE-34 which screws directly into a 110 -volt AC socket (the cost is about \(\$ 1.60)\). Others are a "circuit continuity tester," which plugs into any wall receptacle and which costs about \(\$ 1\) (at a hardware store), and a neon "night light." Strontium: Strontium chloride salt (available at a chemical supply house for about 25 cents \(/ \mathrm{oz}\) ); dissolve a little in a few drops of water and put it in the gas flame on your ruined spoon. The wavelength of the red line is a famous length standard. Copper: Copper sulfate; availability and technique as for strontium chloride. It gives a beautiful green color. Hydrocarbon: Look at your gas flame in the first-order spectrum. There are a sharp, clear blue image and a sharp, clear green image. The "blue" color of the flame is therefore due to one or more almost monochromatic spectral lines.

A "corner reflector" consists of three plane mirrors joined so as to form an inside corner of a rectangular box. Show that a light beam that strikes a corner reflector is directed back at 180 deg to its original direction, independent of the angle of incidence, as long as it hits all three surfaces.

Near field and far field. How far away should you be from a double slit of slit spacing \(0.1 \mathrm{~mm}\) irradiated with visible light in order to use the far-field approximation without making use of a lens? How far should you be from two microwave antennas having spacing \(10 \mathrm{~cm}\) and emitting \(3-\mathrm{cm}\) microwaves to use the far-field approximation?

A double slit of slit separation \(0.5 \mathrm{~mm}\) is illuminated by a parallel beam from a helium-neon laser that emits monochromatic light of wavelength \(6328 \AA\). Five meters beyond the slits is a screen. What is the separation of the interference fringes on the screen?

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