Chapter 3: Problem 24
A long, uniformly porous cylinder of radius \(R\) exudes fluid at velocity \(U_{0}\) into an unbounded fluid of constant \(\rho\) and \(\mu\). The pressure at the cylinder surface is \(p_{0}\). Assuming purely radial outflow with negligible gravity, find the velocity and pressure distributions in the fluid.
Short Answer
Step by step solution
Formulate Governing Equations
Solve Continuity Equation
Apply Boundary Conditions
Determine Velocity Profile
Derive Pressure Equation
Integrate Pressure Equation
Apply Pressure Boundary Condition
Determine Pressure Profile
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cylindrical Coordinates
- **Radial Component (\(r\)):** Represents the distance from the point to the axis of the cylinder.- **Angular Component (\(\theta\)):** Denotes the angle from a reference direction, typically not necessary for purely radial problems.- **Axial Component (\(z\)):** Represents the height above a certain plane, which may be neglected in problems with no vertical changes.In our problem, since we assume a purely radial flow, we focus on the radial component where velocity and pressure can change. This reduces the complexity and simplifies calculations, allowing us to highlight the effects of flow along the radius of the cylinder while ignoring angular and axial flows.
Continuity Equation
For our problem, using the assumption of purely radial flow, we simplify the continuity equation to:\[\frac{1}{r}\frac{d}{dr}(rv_r) = 0\]This implies that the radial velocity (\(v_r\)) is inversely proportional to the radius. Simplifying further with integration, we found that the radial velocity distribution is:\[v_r = \frac{C}{r}\]where\(C\)is a constant determined via boundary conditions.
By integrating the continuity equation, it becomes apparent that despite the flow spreading farther as it moves outward, the product of the area (proportional to\(r\)and the velocity remains constant, conserving mass.
Navier-Stokes Equation
In the context of radial flow in a cylinder, the radial component of the Navier-Stokes equation is used, which simplifies under certain assumptions:- **Neglect gravity:** As the problem states, gravity is negligible.- **No angular or axial flow:** Only radial components are considered.
Reduced to its essential form in cylindrical coordinates for radial flows, the equation becomes:\[\frac{dp}{dr} = -\rho v_r \frac{d}{dr}(v_r)\]We use this to determine the radial pressure gradient, which shows how pressure changes with radius. This concept is crucial in determining how the fluid is distributed across the radial direction due to the forces acting on it.
Velocity Distribution
From the continuity equation and boundary conditions, we derive the expression for radial velocity as:\[v_r(r) = \frac{U_0 R}{r}\]Here, \(U_0\)is the velocity at the cylinder’s surface, and \(R\)is its radius. This relationship indicates that as you move further from the center, the velocity decreases inversely with the radius.
This decrease occurs because the same amount of fluid must traverse larger circles further from the center, spreading the motion equivalently over a larger area, hence reducing velocity. Understanding this distribution is crucial for predicting how quickly fluid can be transported away from the cylinder.
Pressure Distribution
Utilizing the simplified Navier-Stokes equation, an expression for pressure as a function of radial distance is derived:\[p(r) = p_0 - \frac{\rho U_0^2}{2} + \frac{\rho U_0^2 R^2}{2r^2}\]From this, one can see pressure decreases due to kinetic energy changes as fluid moves outward, then increases again with radius due to the inverse square dependence.
The boundary condition at the cylinder’s surface helps find constants in pressure equations, ensuring the solution fits the physical setup. The result shows a complicated interplay where pressure first falls as kinetic energy increases radially, but then rises at larger \(r\)due to momentum distribution over space, maintaining fluid flow stability.