Chapter 17: Problem 58
Disk \(A,\) of weight 5 lb and radius \(r=3\) in., is at rest when it is placed in contact with a belt that moves at a constant speed \(v=50 \mathrm{ft} / \mathrm{s}\). Knowing that \(\mu_{k}=0.20\) between the disk and the belt, determine the time required for the disk to reach a constant angular velocity.
Short Answer
Step by step solution
Convert Units
Identify Forces and Friction
Calculate Torque
Calculate Moment of Inertia
Plug Values into Angular Acceleration Formula
Calculate Constant Angular Velocity
Determine Time to Reach Constant Angular Velocity
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Torque Calculation
To compute the torque (\( \tau \)), you use the formula:
- \( \tau = F_f \times r \)
To find the frictional force, multiply the coefficient of kinetic friction (\( \mu_k \)) by the normal force. The normal force here is identical to the weight of the disk:
- \( F_f = \mu_k \times \, \text{normal force} = 0.20 \times 5 = 1 \, \text{lb} \)
- \( \tau = 1 \, \text{lb} \times 0.25 \, \text{ft} = 0.25 \, \text{lb-ft} \)
Moment of Inertia
For a disk, the formula to calculate the Moment of Inertia is:
- \(I = \frac{1}{2} m r^2\)
- \( m = \frac{5}{32.2} \, \text{slug} \)
- \( I = \frac{1}{2} \times \frac{5}{32.2} \times (0.25)^2 \)
Kinematic Equations
1. **Angular Acceleration (\( \alpha \))**: This is the rate at which the angular velocity changes. Using the relationship:
- \( \alpha = \frac{\tau}{I} \)
2. **Final Angular Velocity (\( \omega_f \))**: As the disk comes up to speed, it will eventually match the belt's linear velocity. Use:
- \( \omega_f = \frac{v}{r} = \frac{50}{0.25} \)
- \( \omega_f = \alpha \cdot t \)
- To solve for \( t \), rearrange to get \( t = \frac{\omega_f}{\alpha} \)