/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 113 The slender rod \(A B\) of lengt... [FREE SOLUTION] | 91Ó°ÊÓ

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The slender rod \(A B\) of length \(L=1 \mathrm{m}\) forms an angle \(\beta=30^{\circ}\) with the vertical as it strikes the frictionless surface shown with a vertical velocity \(\overline{\mathbf{v}}_{1}=2 \mathrm{m} / \mathrm{s}\) and no angular velocity. Knowing that the coefficient of restitution between the rod and the ground is \(e=0.8,\) determine the angular velocity of the rod immediately after the impact.

Short Answer

Expert verified
The angular velocity immediately after impact is approximately 5.2 rad/s.

Step by step solution

01

Understand the Problem

We need to find the angular velocity of the rod immediately after impact. The rod strikes a frictionless surface and has an initial vertical velocity of 2 m/s, forming an angle of 30° with the vertical. The coefficient of restitution is 0.8.
02

Apply the Coefficient of Restitution

The coefficient of restitution provides the relationship between the pre-impact and post-impact vertical velocities of the rod's center of mass. The formula is \( v_{2y} = -e \cdot v_{1y} \), where \( v_{1y} = -2 \) m/s (since the rod moves downward). Thus, \( v_{2y} = -0.8 \times (-2) = 1.6 \) m/s.
03

Determine the Post-Impact Linear Velocity of the Center of Mass

The velocity of the center of mass immediately after impact in the vertical direction is 1.6 m/s upward. Since the horizontal velocity remains unchanged by the impact due to the frictionless surface, it remains 0 m/s.
04

Calculate the Angular Velocity of the Rod

The impact causes an increase in angular velocity. Initially, there is no angular velocity, but the change in velocity due to impact introduces one. Considering the rod pivots about the point at which it strikes the surface.Using the conservation of angular momentum about the point of contact, where angular momentum before impact equals angular momentum after impact:\[ m imes v_1 \times \frac{L}{2} \times \cos(\beta) = m imes \left( \frac{L^2}{3} \right) \times \omega_2 \]Substituting the known values, where \( \cos(30°) = \frac{\sqrt{3}}{2} \) and solving, we have:\[ m imes 2 \times \frac{1}{2} \times \frac{\sqrt{3}}{2} = m \times \frac{1^2}{3} \times \omega_2 \]Solving for the angular velocity, \( \omega_2 \), gives \( \omega_2 = 3\sqrt{3} \; \text{rad/s} \approx 5.2 \; \text{rad/s}. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is the measure of how fast an object rotates or spins around a particular axis. In this exercise, the angular velocity of the rod immediately after impact is what we are trying to find. When the slender rod strikes the frictionless surface, it creates a pivotal moment at the point of contact. This causes the rod to begin rotating around that pivot point.
To calculate this new angular velocity, we use the principle of angular momentum conservation. Angular momentum before the impact is equal to the angular momentum after the impact. Initially, the angular momentum is generated by the vertical motion of the rod because it has no rotation. After the impact, the rod gains angular velocity. This conversion from linear motion to rotational motion helps us find the rod's subsequent behavior in terms of its angular speed.
The final expression allows us to determine that the angular velocity \( \omega \approx 5.2 \; \text{rad/s} \). This means that the rod spins at approximately 5.2 radians per second in the time immediately following impact.
Coefficient of Restitution
The coefficient of restitution, often denoted as \( e \), is a measure of how "bouncy" a collision is. It ranges from 0 to 1, with 1 indicating a perfectly elastic collision (no energy loss) and 0 indicating a perfectly inelastic collision (maximum energy loss).
In practical terms, the coefficient of restitution helps us understand how much of the energy from the impact is conserved in the motion of the colliding objects. In this exercise, the coefficient of restitution is 0.8, which suggests that 80% of the vertical speed of the rod’s center of mass is retained post-impact. The other 20% is lost to factors like sound, heat, and deformation.
To find the post-impact velocity, we use the formula:
  • \( v_{2y} = -e \cdot v_{1y} \)
  • With \( e = 0.8 \) and \( v_{1y} = -2 \; \text{m/s} \), we calculate \( v_{2y} = 1.6 \; \text{m/s} \) upward.
Understanding the coefficient of restitution is crucial for predicting how the rod will move immediately after hitting the surface.
Kinematics of Rotating Bodies
Kinematics is the branch of mechanics that deals with motion without considering the forces that cause that motion. When discussing the kinematics of rotating bodies, we focus on understanding rotational motion factors such as angular displacement, angular velocity, and angular acceleration.
In the case of the slender rod, we have an initial condition where the rod has no angular velocity, but as it strikes the surface, it begins rotating due to its altered velocity components. The impact creates a rotational kinematic scenario where linear kinetic energy is converted into rotational kinetic energy. This provides the rod with an angular displacement and angular acceleration after impact.
To fully grasp this transformation, it's important to look at how both linear and rotational movements interact in the context of the rod's motion. The inertial forces that act at the point of contact give rise to angular momentum. Considering rotational inertia and the effects of impact, kinematics shows us the path and spin speed post-collision. This understanding is pivotal in solving the problem and determining the rod's subsequent angular velocity.

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Most popular questions from this chapter

The uniform \(4-\mathrm{kg}\) cylinder \(A\) with a radius of \(r=150 \mathrm{mm}\) has an angular velocity of \(\omega_{0}=50 \mathrm{rad} / \mathrm{s}\) when it is brought into contact with an identical cylinder \(B\) that is at rest. The coefficient of kinetic friction at the contact point \(D\) is \(\mu_{k}\). After a period of slipping, the cylinders attain constant angular velocities of equal magnitude and opposite direction at the same time. Knowing that cylinder \(A\) executes three revolutions before it attains a constant angular velocity and cylinder \(B\) executes one revolution before it attains a constant angular velocity, determine (a) the final angular velocity of each cylinder, \((b)\) the coefficient of kinetic friction \(\mu_{k} .\)

A small rubber ball of radius \(r\) is thrown against a rough floor with a velocity \(\overline{\mathbf{v}}_{A}\) of magnitude \(\mathbf{v}_{0}\) and a backspin \(\omega_{A}\) of magnitude \(\omega_{0}\). It is observed that the ball bounces from \(A\) to \(B\), then from \(B\) to \(A\), then from \(A\) to \(B,\) etc. Assuming perfectly elastic impact, determine the required magnitude \(\omega_{0}\) of the backspin in terms of \(\bar{v}_{0}\) and \(r .\)

Each of the gears A and B has a mass of 675 g and a radius of gyration of 40 mm, while gear C has a mass of 3.6 kg and a radius of gyration of 100 mm. Assume that kinetic friction in the bearings of gears A, B, and C produces couples of constant magnitude 0.15 N?m, 0.15 N?m, and 0.3 N?m, respectively. Knowing that the initial angular velocity of gear C is 2000 rpm, determine the time required for the system to come to rest.

In a game of pool, ball \(A\) is rolling without slipping with a velocity \(\overline{\mathbf{v}}_{0}\) as it hits obliquely ball \(B,\) which is at rest. Denoting by \(r\) the radius of each ball and by \(\mu_{k}\) the coefficient of kinetic friction between a ball and the table, and assuming perfectly elastic impact, determine (a) the linear and angular velocity of each ball immediately after the impact, (b) the velocity of ball \(B\) after it has started rolling uniformly.

A slender rod of length \(l\) is pivoted about a point \(C\) located at a distance \(b\) from its center \(G .\) It is released from rest in a horizontal position and swings freely. Determine \((a)\) the distance \(b\) for which the angular velocity of the rod as it passes through a vertical position is maximum, \((b)\) the corresponding values of its angular velocity and of the reaction at \(C .\)

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