/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 A 15 -ft beam weighing 500 lb is... [FREE SOLUTION] | 91Ó°ÊÓ

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A 15 -ft beam weighing 500 lb is lowered by means of two cables unwinding from overhead cranes. As the beam approaches the ground, the crane operators apply brakes to slow the unwinding motion. Knowing that the deceleration of cable \(A\) is \(20 \mathrm{ft} / \mathrm{s}^{2}\) and the deceleration of cable \(B\) is \(2 \mathrm{ft} / \mathrm{s}^{2}\), determine the tension in each cable.

Short Answer

Expert verified
Tension in cable A is 560.6 lb; tension in cable B is 281.06 lb.

Step by step solution

01

Evaluate Forces Acting on the Beam

The beam is supported by two cables (A and B), and we must consider the forces acting on it. The forces are the tensions in cable A \( T_A \) and cable B \( T_B \), along with the gravitational force (weight) acting downward on the beam, which is 500 lb.
02

Draw a Free Body Diagram (FBD)

In the FBD, the weight vector acts downward, while the tension vectors \(T_A\) and \(T_B\) act upward along cables A and B respectively. Assume upward forces are positive.
03

Apply Newton’s Second Law

Use the formula \( F = ma \) for each cable, where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. Since the beam is decelerating, acceleration is negative with values corresponding to cable A (20 ft/s²) and cable B (2 ft/s²). Convert the weight into mass using \( m = weight/g = 500/32.2 \approx 15.53 \text{ slugs}\), since 1 slug = 32.2 lb.
04

Write Equations of Motion

For cable A, the equation using Newton’s law is: \[ T_A - 0.5 \cdot 500 = 15.53 \times (-20) \] Rearrange to find \[ T_A = 0.5 \times 500 - 15.53 \times 20 \]For cable B, the equation is:\[ T_B - 0.5 \cdot 500 = 15.53 \times (-2) \] Rearrange to find\[ T_B = 0.5 \times 500 - 15.53 \times 2 \]
05

Calculate Tensions in Each Cable

For \( T_A \), calculate: \[ T_A = 250 + 310.6 = 560.6 \text{ lb} \]For \( T_B \), calculate:\[ T_B = 250 + 31.06 = 281.06 \text{ lb} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free Body Diagram
A free body diagram (FBD) is a simple yet effective tool used to visualize all the forces acting on an object.
In this exercise, the object is the beam being lowered by the two cables, A and B.
Drawing a free body diagram helps us isolate the beam and identify the forces acting on it.

For the beam problem, you would draw the following elements in the FBD:
  • An arrow pointing downwards representing the weight of the beam, which is 500 lbs.
  • Two arrows pointing upwards, each representing the tensions in cable A and cable B, respectively.
The FBD simplifies complex systems by showing that the total force acting on the beam vertically is the result of these tension forces counteracting the gravitational force.
It is crucial that these forces are noted correctly in the diagram as it sets the stage for applying further physics principles, such as Newton's second law.
Newton's Second Law
Newton’s second law of motion is a fundamental principle in physics and can be succinctly stated with the equation: \( F = ma \), where \( F \) is the net force acting on an object, \( m \) is the mass of the object, and \( a \) is the acceleration (or in this case, the deceleration) of the object.

In the given exercise, Newton's second law is applied to each cable to determine the respective tensions.
This means evaluating the difference between the gravitational force and the tension in each cable as it decelerates:
  • The gravitational force vector is balanced by the upward force of the tension in the cable.
  • The deceleration of each cable changes how this balance is calculated.
By applying Newton's second law to the beam in the scenario of deceleration, we are essentially finding the equilibrium state where these forces result in a net deceleration. The mass of the beam was given by using its weight and the conversion factor, since weight is mass times gravity (\( g \approx 32.2 \, \text{lb/slug} \)). Understanding this law allows students to see how dynamic forces, like tension in a moving cable, interact with static forces, such as gravity.
Cable Deceleration
Deceleration is simply negative acceleration. It occurs when an object slows down, as is the case with the beam being lowered by the cables.
The problem gives two specific deceleration rates for the cables: 20 ft/s² for cable A and 2 ft/s² for cable B.
This information is critical because it influences the calculation of tension in each cable.

Here's what to remember:
  • Deceleration directly affects how much force the cables must exert to slow the beam's descent.
  • The greater the deceleration, the higher the tension required in the cable to achieve that rate of slowing down.
  • Each cable experiences a different amount of deceleration, which must be individually accounted for in the tension calculations.
Understanding deceleration in this context helps illuminate why different tensions result, even though the mass being lowered is the same in both scenarios. It's a clear example of how forces and motion are interrelated and must be carefully analyzed in any mechanics problem.
Force Evaluation
In physics, evaluating forces involves calculating and comparing all the forces acting on an object to understand the net effect.
For the beam held by two cables, this means carefully considering the tension in each cable alongside the beam's weight.

The exercise requires setting equations for each cable based on:
  • The forces acting on the beam from cable tensions and gravity.
  • The effect of given deceleration values on these tensions.
When evaluating these forces, you first express the tension by isolating the force of gravity and the deceleration impact per cable, using Newton’s second law equations.
You solve for the unknown tension by rearranging the formula for each cable situation:
  • Tension in cable A equals the gravitational force minus the product of mass and deceleration for cable A.
  • Similarly, tension in cable B follows the same logic adapted with the specific deceleration for cable B.
By maintaining clear and systematic steps, force evaluation becomes a methodical way to ensure all variables are properly accounted for and the physical dynamics of the beam and cables are clearly understood.

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