/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 A \(540-\mathrm{kg}\) spacecraft... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(540-\mathrm{kg}\) spacecraft is mounted on top of a rocket with a mass of \(19 \mathrm{Mg},\) including \(17.8 \mathrm{Mg}\) of fuel. Knowing that the fuel is consumed at a rate of \(225 \mathrm{kg} / \mathrm{s}\) and ejected with a relative velocity of \(3600 \mathrm{m} / \mathrm{s}\), determine the maximum speed imparted to the spacecraft if the rocket is fired vertically from the ground.

Short Answer

Expert verified
The maximum speed imparted to the spacecraft is 8233.2 m/s.

Step by step solution

01

Understanding the Problem

We need to determine the maximum speed imparted to a spacecraft mounted on a rocket. The rocket has a total initial mass of 19 Mg (which is 19000 kg) including 17.8 Mg (which is 17800 kg) of fuel. The fuel consumption rate is 225 kg/s and ejects fuel at a velocity of 3600 m/s, relative to the rocket. The motion is vertical.
02

Calculate Initial Total Mass

Add the mass of the spacecraft to the mass of the rocket including fuel. \[ M = 540 \text{ kg} + 19000 \text{ kg} = 19540 \text{ kg} \]
03

Calculate Final Total Mass

When all fuel is used, subtract the mass of the fuel from the total initial mass. \[ M_f = 19540 \text{ kg} - 17800 \text{ kg} = 1740 \text{ kg} \]
04

Apply Rocket Equation

The rocket equation is given as: \[ \Delta v = v_e \ln \left( \frac{M_i}{M_f} \right) \]where \(v_e\) (effective exhaust velocity) is 3600 m/s, \(M_i\) is the initial mass (19540 kg), and \(M_f\) is the final mass (1740 kg).
05

Perform Calculation

Substitute the known values into the rocket equation: \[ \Delta v = 3600 \times \ln \left( \frac{19540}{1740} \right) \]Calculate \( \ln \left( \frac{19540}{1740} \right)\) and solve for \(\Delta v\).
06

Final Calculation Result

After performing the calculations: \[ \Delta v = 3600 \times 2.287 = 8233.2 \text{ m/s} \] Thus, the maximum speed imparted to the spacecraft is 8233.2 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spacecraft Dynamics
Spacecraft dynamics explores how forces and motions affect spacecraft as they journey through space. In the context of a rocket launching vertically from the ground, it's vital to understand the interplay between various forces.
  • Gravitational pull: Initially, the rocket must overcome Earth's gravitational force, which is a major factor in vertical launches.
  • Thrust: This is the force generated by expelling fuel, powering the rocket upward.
  • Mass changes: As fuel is consumed, the mass of the rocket continuously decreases, affecting its acceleration and speed.
These dynamics highlight the challenge of designing a spacecraft that can achieve the required speeds while efficiently using its resources. The dynamics are encapsulated in Newton’s laws of motion, which govern how the rocket's thrust interacts with gravitational force to achieve launch. Understanding spacecraft dynamics is crucial for determining how efficiently a rocket can convert fuel into vertical speed.
Fuel Consumption
Fuel consumption in a rocket is a critical element of its design and functionality. It is important to consider how quickly the fuel is consumed and how it impacts the overall journey.
  • Rate of consumption: The fuel consumption rate is the amount of fuel burned per second. In our example, it is 225 kg/s.
  • Total fuel available: The spacecraft has 17.8 Mg (17800 kg) of fuel that will gradually decrease as the fuel burns.
  • Impact on mass: As fuel is consumed, the spacecraft's mass reduces, creating a significant impact on its acceleration and trajectory.
Efficient fuel consumption is vital for achieving desired velocities and has to be rigorously calculated to ensure that the spacecraft reaches its intended final speed. By optimizing fuel usage, engineers can ensure maximum performance and successful mission outcomes.
Rocket Equation
The rocket equation, or the Tsiolkovsky rocket equation, describes the motion of a rocket in free space by correlating velocity to mass and exhaust velocity. It is an essential formula in the field of rocket science.The equation is:\[\Delta v = v_e \ln \left( \frac{M_i}{M_f} \right)\]Where:
  • \(\Delta v\) is the change in velocity of the rocket.
  • \(v_e\), the effective exhaust velocity, is given as 3600 m/s in this problem.
  • \(M_i\) is the initial total mass (19540 kg).
  • \(M_f\) is the final mass after all fuel is burnt (1740 kg).
This equation is powerful because it allows calculation of the maximum speed a rocket can achieve based on its initial conditions. It provides insights into how much fuel is necessary to reach certain speeds or escape velocities. Thus, the rocket equation is a cornerstone concept used to solve problems about velocity changes during vertical launches.
Vertical Launch
The vertical launch of a rocket involves firing it directly upwards from the Earth's surface. This method of launching is simple in terms of trajectory but poses unique challenges.
  • Overcoming gravity: A substantial amount of energy is required to counteract Earth's gravity at the start.
  • Atmospheric drag: The rocket must also overcome air resistance as it ascends through the atmosphere.
  • Fuel requirements: Maximum thrust efficiency is crucial for minimizing fuel consumption during the high-energy launch phase.
In a vertical launch, the rocket's dynamics depend heavily on the thrust produced by its engines and the rate at which it consumes fuel. Launching vertically allows the spacecraft to break free from Earth's gravity quickly, which is why understanding the rocket equation's implications on fuel and thrust is vital for optimal launch performance. Vertical launches are a fundamental component of space missions, playing a key role in placing satellites, traveling to other planets, and exploring outer space.

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Most popular questions from this chapter

A \(30-\) g bullet is fired with a horizontal velocity of \(450 \mathrm{m} / \mathrm{s}\) and becomes embedded in block \(B\), which has a mass of \(3 \mathrm{kg}\). After the impact, block \(B\) slides on \(30-\mathrm{kg}\) carrier \(C\) until it impacts the end of the carrier. Knowing the impact between \(B\) and \(C\) is perfectly plastic and the coefficient of kinetic friction between \(B\) and \(C\) is \(0.2,\) determine \((a)\) the velocity of the bullet and \(B\) after the first impact, (b) the final velocity of the carrier.

A 16 -Mg jet airplane maintains a constant speed of \(774 \mathrm{km} / \mathrm{h}\) while climbing at an angle \(\alpha=18^{\circ} .\) The airplane scoops in air at a rate of \(300 \mathrm{kg} / \mathrm{s}\) and discharges it with a velocity of \(665 \mathrm{m} / \mathrm{s}\) relative to the airplane. If the pilot changes to a horizontal flight while maintaining the same engine setting, determine \((a)\) the initial acceleration of the plane, \((b)\) the maximum horizontal speed that will be attained. Assume that the drag due to air friction is proportional to the square of the speed.

A 900 -lb space vehicle traveling with a velocity \(\mathbf{v}_{0}=(1500 \mathrm{ft} / \mathrm{s}) \mathrm{k}\) passes through the origin \(O .\) Explosive charges then separate the vehicle into three parts \(A, B\), and \(C,\) with masses of \(150 \mathrm{lb}, 300 \mathrm{lb}\), and \(450 \mathrm{lb}\), respectively. Knowing that shortly thereafter the positions of the three part are, respectively, \(A(250,250,2250), B(600,1300,\) \(3200),\) and \(C(-475,-950,1900),\) where the coordinates are expressed in feet, that the velocity of \(B\) is \(\mathbf{v}_{B}=(500 \mathrm{ft} / \mathrm{s}) \mathrm{i}+(1100 \mathrm{ft} / \mathrm{s}) \mathrm{j}+\) \((2100 \mathrm{ft} / \mathrm{s}) \mathrm{k},\) and that the \(x\) component of the velocity of \(C\) is \(-400 \mathrm{ft} / \mathrm{s}\), determine the velocity of part \(A\)

In order to shorten the distance required for landing, a jet airplane is equipped with movable vanes that partially reverse the direction of the air discharged by each of its engines. Each engine scoops in the air at a rate of \(120 \mathrm{kg} / \mathrm{s}\) and discharges it with a velocity of \(600 \mathrm{m} / \mathrm{s}\) relative to the engine. At an instant when the speed of the airplane is \(270 \mathrm{km} / \mathrm{h}\), determine the reverse thrust provided by each of the engines.

Three small spheres \(A, B\), and \(C,\) each of mass \(m,\) are connected to a small ring \(D\) of negligible mass by means of three inextensible, inelastic cords of length \(l\). The spheres can slide freely on a frictionless horizontal surface and are rotating initially at a speed \(v_{0}\) about ring \(D\) which is at rest. Suddenly the cord \(C D\) breaks. After the other two cords have again become taut, determine ( \(a\) ) the speed of ring \(D,(b)\) the relative speed at which spheres \(A\) and \(B\) rotate about \(D,\) (c) the fraction of the original energy of spheres \(A\) and \(B\) that is dissipated when cords \(A D\) and \(B D\) again became taut.

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