/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 93 A rocket sled burns fuel at the ... [FREE SOLUTION] | 91Ó°ÊÓ

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A rocket sled burns fuel at the constant rate of \(120 \mathrm{lb} / \mathrm{s}\). The initial weight of the sled is \(1800 \mathrm{lb}\), including \(360 \mathrm{lb}\) of fuel. Assume that the track is lubricated and the sled is aerodynamically designed so that air resistance and friction are negligible. (a) Derive a formula for the acceleration \(a\) of the sled as a function of time \(t\) and the exhaust velocity \(v_{\mathrm{ex}}\) of the burned fuel relative to the sled. Plot the ratio \(a / v_{\mathrm{c}}\) versus time \(t\) for the range \(0

Short Answer

Expert verified
The acceleration formula is \( a(t) = \frac{-120 v_{\mathrm{ex}}}{1800 - 120t} \), and \( \frac{v_b}{v_{\mathrm{ex}}} = \ln\left(\frac{5}{4}\right) \).

Step by step solution

01

Define the Mass as a Function of Time

Initially, the total mass of the sled, including fuel, is 1800 lb. Given the fuel burns at a rate of 120 lb/s, the mass of the fuel at time \( t \) is \( 360 - 120t \). The total mass of the sled as a function of time is \( m(t) = 1800 - 120t \).
02

Appropriate Formula for Acceleration

The rocket equation relates the acceleration of the sled to the exhaust velocity and its rate of mass loss. This is given by:\[ a(t) = \frac{1}{m(t)} \cdot v_{\mathrm{ex}} \cdot \frac{dm}{dt} \]Where \( \frac{dm}{dt} = -120 \) lb/s (negative due to loss of mass). Therefore, substituting \( m(t) \) and \( \frac{dm}{dt} \) gives:\[ a(t) = \frac{1}{1800 - 120t} \cdot v_{\mathrm{ex}} \cdot (-120) \]Which simplifies to:\[ a(t) = \frac{-120 v_{\mathrm{ex}}}{1800 - 120t} \]
03

Plot the Ratio \( \frac{a}{v_{\mathrm{ex}}} \)

The ratio \( \frac{a}{v_{\mathrm{ex}}} \) is given by:\[ \frac{a}{v_{\mathrm{ex}}} = \frac{-120}{1800 - 120t} \]Plot this function for \( 0 < t < 4 \) seconds. At \( t = 0 \), the slope is steepest because the denominator is largest, indicating initial high acceleration. At \( t = 4 \), the slope is shallower because the mass of the sled is less, causing smaller changes in acceleration.
04

Determine Burnout Velocity Ratio \( \frac{v_b}{v_{\mathrm{ex}}} \)

From the integrated rocket equation, the change in velocity \( v_b \) at burnout can be found by integrating:\[ \Delta v = \int_0^{t_b} - \frac{v_{\mathrm{ex}}}{m(t)} (-120) \, dt \]Which simplifies to:\[ \Delta v = \int_0^{3} \frac{120 \, v_{\mathrm{ex}}}{1800 - 120t} \, dt \]Let \( x = 1800 - 120t \), hence \(-120 dt = dx\), and compute:\[ \Delta v = 120 \, v_{\mathrm{ex}} \int_{1800}^{1440} \frac{1}{x} \frac{(-1)}{120} \, dx = v_{\mathrm{ex}} [\ln(x)]_{1800}^{1440} \]\[ \Delta v = v_{\mathrm{ex}} \ln\left(\frac{1800}{1440}\right) \]This ratio simplifies to the equation for \( v_b = \ln\left(\frac{5}{4}\right) v_{\mathrm{ex}} \) after evaluating the limits.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Formula
The acceleration formula is crucial for understanding how the sled speeds up or slows down over time. In the context of a rocket sled, acceleration is influenced by the mass of the sled and the velocity at which the fuel is expelled. For this sled, the formula for acceleration at any given time \( t \) is derived from the famous rocket equation.
To find the acceleration, we begin by considering the change in mass over time, which, in this case, is due to the fuel being burned. The sled's initial mass is 1800 lb, and it loses mass at a rate of 120 lb/s. Thus, the mass at time \( t \) is \( m(t) = 1800 - 120t \).
The acceleration \( a(t) \) is then related to the rate of change of this mass and the exhaust velocity \( v_{\mathrm{ex}} \), with the formula:\[a(t) = \frac{-120 v_{\mathrm{ex}}}{1800 - 120t}\]This formula shows us how the acceleration depends inversely on the decreasing mass of the sled.
Rocket Equation
The rocket equation is a fundamental principle in rocket dynamics. It helps us understand how rockets gain velocity as they lose mass due to burning fuel.
This equation considers the conservation of momentum. As the sled expels exhaust, it gains forward momentum. The changing mass of the sled affects this gain. Mathematically, the rocket equation can be described as:\[\Delta v = \int_0^{t_b} - \frac{v_{\mathrm{ex}}}{m(t)} \left(\frac{dm}{dt}\right) dt\]This integral gives the total change in velocity over time as the sled burns through its fuel.
Burnout Velocity
Burnout velocity is the speed of the sled at the moment it runs out of fuel. Determining this speed involves understanding how the sled's velocity changes as it loses mass.
From the rocket equation, we calculate the change in velocity \( \Delta v \) by evaluating the integral:\[\Delta v = v_{\mathrm{ex}} \ln\left(\frac{m_0}{m_f}\right)\]Where \( m_0 \) is the initial mass, and \( m_f \) is the final mass. For our sled, this becomes:\[\Delta v = v_{\mathrm{ex}} \ln\left(\frac{1800}{1440}\right)\]This result reflects how the velocity depends on the proportional change in mass.
Mass Function
The mass function is vital for understanding dynamics in problems involving mass loss, like rocket sled dynamics. The mass function \( m(t) \) describes how the sled's total mass decreases as it burns fuel.
Initially, the sled has 1800 lb, including 360 lb of fuel. The mass function is:\[m(t) = 1800 - 120t\]Each second, the sled loses 120 lb of mass, steadily decreasing until the fuel runs out.
Understanding this function is essential as it directly impacts other calculations like acceleration and velocity.

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