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91Ó°ÊÓ

The main propulsion system of a space shuttle consists of three identical rocket engines that provide a total thrust of \(6 \mathrm{MN}\). Determine the rate at which the hydrogen-oxygen propellant is burned by each of the three engines, knowing that it is ejected with a relative velocity of \(3750 \mathrm{m} / \mathrm{s}\).

Short Answer

Expert verified
Each engine burns propellant at about 533.33 kg/s.

Step by step solution

01

Identify the Total Thrust per Engine

The total thrust provided by the three engines combined is 6 MN (MegaNewtons). Since the engines are identical, each engine provides an equal share of the total thrust. Therefore, divide the total thrust by the number of engines to find the thrust per engine: \[\text{Thrust per engine} = \frac{6 \text{ MN}}{3} = 2 \text{ MN} = 2 \times 10^6 \text{ N}\]
02

Apply the Thrust Formula

The formula for thrust (\( F \)) of a rocket engine in terms of exhaust velocity (\( v \)) and mass flow rate (\( \dot{m} \)) is given by\[F = \dot{m} \cdot v\]In this case, we know the thrust per engine and the relative velocity, so we can rearrange the formula to solve for mass flow rate.
03

Rearrange the Formula to Solve for Mass Flow Rate

Rearrange the thrust formula to solve for the mass flow rate (\( \dot{m} \)):\[\dot{m} = \frac{F}{v}\]Substitute the known values of thrust per engine and the velocity into this formula.
04

Calculate the Mass Flow Rate

Substitute the thrust of 2 MN for one engine and the exhaust velocity into the equation:\[\dot{m} = \frac{2 \times 10^6 \text{ N}}{3750 \text{ m/s}} \approx 533.33 \text{ kg/s}\]Thus, the rate at which the propellant is burned by each engine is approximately 533.33 kg/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thrust Calculation
Understanding how to calculate thrust in a rocket engine is crucial in rocket science. Thrust is the force which propels a rocket forward, counteracting gravity and allowing it to ascend. In this scenario, thrust is calculated by dividing the total thrust by the number of engines, as all engines are identical. For instance, if a space shuttle's propulsion system generates a collective thrust of 6 MN with three identical engines, each engine would contribute equally. Thus, each engine produces:
  • Thrust per engine: \[ \frac{6 \text{ MN}}{3} = 2 \text{ MN} = 2 \times 10^6 \text{ N} \]
This per-engine thrust helps us analyze how much force each engine contributes to the shuttle's movement.
Mass Flow Rate
The mass flow rate is a measure of how much propellant is expelled from the engine per unit time. It's a crucial factor in determining the efficiency of a rocket engine. In essence, it tells us how fast fuel is being burned. The relationship between thrust, mass flow rate, and exhaust velocity is captured in the thrust equation. For our problem, the thrust produced by an individual rocket engine is directly reliant on its mass flow rate and the exhaust velocity. When these values are known, you can calculate the mass flow rate as follows:
  • Formula: \[ \dot{m} = \frac{F}{v} \]
Substituting the thrust of an individual engine and exhaust velocity, we find the mass flow rate for the engines in our example, which is approximately 533.33 kg/s.
Rocket Engines
Rocket engines are a marvel of modern engineering, allowing space shuttles and other spacecraft to defy gravity and reach orbit. They operate on Newton's third law of motion: for every action, there is an equal and opposite reaction. By expelling hot gases out of the back at high speed, a rocket engine propels itself forward.
  • Components include:
    • Combustion chamber - where fuel and oxidizer mix and ignite.
    • Nozzle - directs the flow of exhaust gases.
Rocket engines need to be highly efficient because carrying extra weight or wasting fuel can affect their performance significantly. This efficiency is closely tied to factors like thrust and exhaust velocity.
Exhaust Velocity
Exhaust velocity is the speed at which exhaust gases are expelled from the rocket engine. It plays a critical role in determining the effectiveness of a rocket engine, and is one of the primary factors influencing thrust. If the exhaust velocity is high, the same mass flow rate will yield a greater thrust. Conversely, a lower exhaust velocity will result in less thrust for the same amount of propellant.
  • Importance:
    • Allows for efficient use of fuel.
    • Directly affects how fast the rocket moves.
In the given problem, the exhaust velocity is known to be 3750 m/s, which significantly influences the engine's thrust based on its mass flow rate. Thus, understanding exhaust velocity helps optimize engine performance for space travel.

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Most popular questions from this chapter

A 300 -kg space vehicle traveling with a velocity \(\mathbf{v}_{0}=(360 \mathrm{m} / \mathrm{s})\) i passes through the origin \(O\) at \(t=0 .\) Explosive charges then separate the vehicle into three parts \(A, B,\) and \(C,\) with mass, respectively, \(150 \mathrm{kg}, 100 \mathrm{kg},\) and \(50 \mathrm{kg}\). Knowing that at \(t=4 \mathrm{s}\), the positions of parts \(A\) and \(B\) are observed to be \(A(1170 \mathrm{m},-290 \mathrm{m},-585 \mathrm{m})\) and \(B(1975 \mathrm{m}, 365 \mathrm{m}, 800 \mathrm{m}),\) determine the corresponding position of part \(C .\) Neglect the effect of gravity.

A \(30-\) g bullet is fired with a horizontal velocity of \(450 \mathrm{m} / \mathrm{s}\) and becomes embedded in block \(B\), which has a mass of \(3 \mathrm{kg}\). After the impact, block \(B\) slides on \(30-\mathrm{kg}\) carrier \(C\) until it impacts the end of the carrier. Knowing the impact between \(B\) and \(C\) is perfectly plastic and the coefficient of kinetic friction between \(B\) and \(C\) is \(0.2,\) determine \((a)\) the velocity of the bullet and \(B\) after the first impact, (b) the final velocity of the carrier.

A 16 -Mg jet airplane maintains a constant speed of \(774 \mathrm{km} / \mathrm{h}\) while climbing at an angle \(\alpha=18^{\circ} .\) The airplane scoops in air at a rate of \(300 \mathrm{kg} / \mathrm{s}\) and discharges it with a velocity of \(665 \mathrm{m} / \mathrm{s}\) relative to the airplane. If the pilot changes to a horizontal flight while maintaining the same engine setting, determine \((a)\) the initial acceleration of the plane, \((b)\) the maximum horizontal speed that will be attained. Assume that the drag due to air friction is proportional to the square of the speed.

A rocket weighs 2600 lb, including \(2200 \mathrm{lb}\) of fuel, which is consumed at the rate of \(25 \mathrm{lb} / \mathrm{s}\) and ejected with a relative velocity of \(13,000 \mathrm{ft} / \mathrm{s}\). Knowing that the rocket is fired vertically from the ground, determine ( \(a\) ) its acceleration as it is fired, \((b)\) its acceleration as the last particle of fuel is being consumed, \((c)\) the altitude at which all the fuel has been consumed, ( \(d\) ) the velocity of the rocket at that time.

In a rocket, the kinetic energy imparted to the consumed and ejected fuel is wasted as far as propelling the rocket is concerned. The useful power is equal to the product of the force available to propel the rocket and the speed of the rocket. If \(v\) is the speed of the rocket and \(u\) is the relative speed of the expelled fuel, show that the mechanical efficiency of the rocket is \(\eta=2 u v /\left(u^{2}+v^{2}\right) .\) Explain why \(\eta=1\) when \(u=v\)

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