/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 176 A 0.25 -lb ball thrown with a ho... [FREE SOLUTION] | 91Ó°ÊÓ

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A 0.25 -lb ball thrown with a horizontal velocity \(\mathrm{v}_{0}\) strikes a 1.5 -lb plate attached to a vertical wall at a height of \(36 \mathrm{in.}\) above the ground. It is observed that after rebounding, the ball hits the ground at a distance of \(24 \mathrm{in.}\) from the wall when the plate is rigidly attached to the wall (Fig. 1) and at a distance of 10 in. when a foam- rubber mat is placed between the plate and the wall (Fig. 2 ). Determine (a) the coefficient of restitution \(e\) between the ball and the plate, (b) the initial velocity \(v_{0}\) of the ball.

Short Answer

Expert verified
(a) Coefficient of restitution \( e \) = 0.4167; (b) Initial velocity \( v_0 \) = 323 in/s.

Step by step solution

01

Understand the Physical Model

The ball's horizontal motion can be analyzed as a projectile motion problem. Initially, the ball has only horizontal velocity, and after rebounding, it follows a projectile path hitting the ground at a given distance. The aim is to find out how the presence of the foam mat affects this motion, specifically through the coefficient of restitution.
02

Use the Coefficient of Restitution

The coefficient of restitution, denoted as \( e \), is a measure of how "bouncy" a collision is, defined by the ratio of the relative velocity after collision to the relative velocity before collision. For the ball and the plate: \( e = \frac{v_1}{v_0} \), where \( v_1 \) is the velocity after the collision. The problem provides two scenarios: one with \( e \) (plate alone) and one effectively with \( e \) reduced due to the foam (plate and foam together).
03

Calculate the Time of Flight

First, calculate the time it takes for the ball to hit the ground, which is determined by the vertical motion. Using the equation for free fall: \( h = \frac{1}{2}gt^2 \), we find the time \( t \) it takes to fall 36 inches: \( t = \sqrt{\frac{2h}{g}} \) where \( g = 386.4 \text{ in/s}^2 \) for gravitational acceleration.
04

Find Horizontal Velocities

Using the horizontal distance formula \( x = v \, t \), calculate the horizontal velocity \( v_1 \) after the collision for both scenarios: \( v_1 = \frac{24 \text{ in}}{t} \) for the rigid plate and \( v_2 = \frac{10 \text{ in}}{t} \) for the foam-mat case.
05

Calculate Initial Horizontal Velocity \( v_0 \)

Using the calculated time \( t \) and the known distance \( x_0 = 36 \text{ in} \), the initial horizontal velocity \( v_0 \) can be determined for the rigid plate scenario: \( v_0 = \frac{x_0}{t} \).
06

Solve for Coefficient of Restitution \( e \)

Apply the formula for coefficient of restitution for each case: \( e_1 = \frac{v_1}{v_0} \) for the rigid plate and \( e_2 = \frac{v_2}{v_0} \) for the foam-mat case. Given \( e_1 \) is without any energy loss due to foam, it is the value we seek for the ball-plate interaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Restitution
The Coefficient of Restitution (often denoted as \( e \)) is an essential concept in understanding collision dynamics, particularly in projectile motion problems. It measures the ratio of the relative speed after a collision to that before the collision.
In simple terms, it tells us how "bouncy" a collision is. If \( e = 1 \), the collision is perfectly elastic, meaning no kinetic energy is lost. If \( e = 0 \), it's perfectly inelastic, and all kinetic energy is lost as heat or deformation.
In our exercise, the coefficient of restitution comes into play when analyzing the effect of a foam pad during the ball’s collision with the plate. By comparing the distances that the ball travels post-impact in both scenarios (with and without foam), we can infer differences in \( e \). This coefficient not only determines the post-collision velocity but also offers insight into materials involved in collisions.
Projectile Path
The Projectile Path describes the trajectory that an object follows through space as it moves under the influence of gravity alone after its initial launch. This path is typically parabolic. Understanding this path is essential in solving problems related to projectile motion as seen with the thrown ball in the exercise.
After the ball hits the plate (whether there's foam or not), it rebounds and continues along a parabolic trajectory due to gravity. The shape and distance of this path can change depending on factors such as the initial horizontal velocity and the impact characteristics described by the coefficient of restitution.
By analyzing the distance from the wall where the ball lands, students can infer changes in the projectile path. Such changes reflect how the collision dynamics (like the presence of a foam pad) alter both the direction and speed of the rebounding ball, influencing its landing spot.
Horizontal and Vertical Velocities
Horizontal and Vertical Velocities are two components of motion vital to understanding the dynamics of projectiles. In projectile motion:
  • The horizontal velocity is constant (ignoring air resistance) because no external forces act horizontally on the object.
  • Vertical velocity, on the other hand, is influenced by gravity, thus changing the vertical motion of the object over time.

In this exercise, we initially determine the horizontal velocity for two cases post-collision using the flight time derived from the vertical fall and the respective distances the ball travels. Calculating these velocities helps to trace changes in motion due to variations in the coefficient of restitution when comparing a surface with and without foam.
Ultimately, understanding how these velocities interact is key to solving projectile motion problems, and helps to describe why and how the ball hits different landing spots each time.
Collision Dynamics
Collision Dynamics entails the study of how objects interact during impact, encompassing aspects like force transfer, momentum conservation, and post-collision motion. For the ball thrown in our exercise, understanding these dynamics is crucial in determining outcomes post-collision.
The presence of the foam mat introduces new dynamics by absorbing impact energy and reducing velocity post-collision, leading to a shorter projectile path. To capture these changes, the coefficient of restitution (as previously discussed) is especially important.
By studying the impacts with and without foam, students can observe how energy absorption alters the motion outcome. This understanding aids in a comprehensive grasp of mechanics in practical situations, emphasizing how different materials and surfaces can influence motion drastically from theoretically expected outcomes.

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Most popular questions from this chapter

The sphere at \(A\) is given a downward velocity \(v_{0}\) of magnitude \(5 \mathrm{m} / \mathrm{s}\) and swings in a vertical plane at the end of a rope of length \(l=2 \mathrm{m}\) attached to a support at \(O\). Determine the angle \(\theta\) at which the rope will break, knowing that it can withstand a maximum tension equal to twice the weight of the sphere.

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