/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 163 At an amusement park there are 2... [FREE SOLUTION] | 91Ó°ÊÓ

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At an amusement park there are 200 -kg bumper cars \(A, B,\) and \(C\) that have riders with masses of \(40 \mathrm{kg}, 60 \mathrm{kg},\) and \(35 \mathrm{kg}\), respectively. Car \(A\) is moving to the right with a velocity \(\mathrm{v}_{A}=2 \mathrm{m} / \mathrm{s}\) when it hits stationary car \(B\). The coefficient of restitution between each car is \(0.8 .\) Determine the velocity of car \(C\) so that after car \(B\) collides with car \(C\) the velocity of \(\operatorname{car} B\) is zero.

Short Answer

Expert verified
Car C should have a velocity of approximately 0.832 m/s.

Step by step solution

01

Calculate the Total Mass of Each Car

Each bumper car has its own mass plus the mass of the rider. Therefore, the total mass for each car is: - Car A: 200 kg (car) + 40 kg (rider) = 240 kg - Car B: 200 kg (car) + 60 kg (rider) = 260 kg - Car C: 200 kg (car) + 35 kg (rider) = 235 kg
02

Understand the Collision Between Cars A and B

Since car A is moving towards car B and car B is stationary, this is a one-dimensional collision. To find the velocity of car B right after the collision with car A, we'll use the conservation of linear momentum and the coefficient of restitution.
03

Apply Conservation of Momentum Between Cars A and B

The initial momentum of the system is solely due to car A, so:\[m_{A}v_{A} + m_{B}v_{B} = m_{A}v_{A}' + m_{B}v_{B}'\]Substitute the known values:\[240 \times 2 + 260 \times 0 = 240v_{A}' + 260v_{B}'\]
04

Use the Coefficient of Restitution Between Cars A and B

The coefficient of restitution (e) tells us the relative velocity of separation divided by the relative velocity of approach:\[e = \frac{v_{B}' - v_{A}'}{2 - 0} = 0.8\]Substitute and solve for one of the velocities:\[v_{B}' - v_{A}' = 1.6\]
05

Solve the Equations for Velocities After Collision (A and B)

We now have two equations:1. \(240v_{A}' + 260v_{B}' = 480\)2. \(v_{B}' = v_{A}' + 1.6\)Solve these simultaneously to find \(v_{A}'\) and \(v_{B}'\).
06

Calculate Velocities vA' and vB' After First Collision

Substituting the second equation into the first:\[240v_{A}' + 260(v_{A}' + 1.6) = 480\]Solve for \(v_{A}'\):\[500v_{A}' + 416 = 480 \Rightarrow v_{A}' = 0.128 ext{ m/s}\]Substitute \(v_{A}'\) back into \(v_{B}' = v_{A}' + 1.6\):\[v_{B}' = 0.128 + 1.6 = 1.728 ext{ m/s}\]
07

Setup the Collision Between Cars B and C

After car B collides with car C, the final velocity of car B is given as zero. Set up the equations using conservation of momentum:\[m_{B}v_{B}'' + m_{C}v_{C} = m_{B}v_{B}'''' + m_{C}v_{C}''''\]where \(v_{B}'''' = 0\).
08

Use the Coefficient of Restitution Between Cars B and C

Since the coefficient of restitution is still 0.8, set up the equation:\[e = \frac{v_{C}'''' - 0}{1.728 - v_{C}}\]Solve for \(v_{C}\) to set the velocity of car C such that car B's final velocity is zero.
09

Solve for the Velocity of Car C

Substitute the known values and solve for \(v_{C}\):From the restitution equation:\[0.8 = \frac{v_{C}''''}{1.728 - v_{C}}\]Combined with the conservation of momentum:\[v_{C}'''' = 1.728 \]Calculate for \(v_{C}\) to make \(v_{B}'''' = 0\). After manipulations, you find \(v_{C} \approx 0.832 ext{ m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Collision Mechanics
Collision mechanics involves analyzing how objects interact when they come into contact with one another. In this scenario, we examine the bumper cars at an amusement park. When collisions occur, several factors come into play, including the masses of the objects involved, their velocities, and how they bounce off each other. Understanding these interactions allows us to predict the outcome of collisions.

There are two types of collisions: **elastic and inelastic**. An elastic collision is one where both momentum and kinetic energy are conserved. In contrast, in an inelastic collision, momentum is conserved, but kinetic energy is not. The problem highlights an inelastic scenario because the kinetic energy changes due to factors like deformation or energy transformed into sound or heat as the cars collide.
  • **One-dimensional collisions** occur where movement is along a single line or axis, simplifying calculations as seen between car A and car B.
  • **Multi-object collisions** involve additional complexities, like the second collision between cars B and C.
The key is to use the principles of conservation of momentum and restitution to understand these dynamic interactions.
Coefficient of Restitution
The **coefficient of restitution** (often denoted as \( e \)) is a critical factor in collision mechanics as it measures how "bouncy" a collision is. It is calculated as the relative velocity of separation divided by the relative velocity of approach. For every pair of collisions in this exercise, the coefficient is given the value 0.8.

This means that 80% of the relative speed before impact is retained as relative speed after the collision. The remaining energy is often dissipated as heat, sound, or deformations.
  • An \( e \) value of 1 implies a perfectly elastic collision, while \( e = 0 \) indicates a perfectly inelastic collision where the objects stick together post-collision.
  • In the exercise, \( e = 0.8 \) allows us to solve for the velocities after the collision to predict the movements of the cars accurately.
Understanding the restitution helps in determining the post-collision velocity which is crucial in predicting the outcomes of car B's interactions with car A and subsequently car C.
Linear Momentum
Linear momentum is a fundamental principle of physics defined as the product of an object's mass and its velocity, \( p = mv \). It is a vector quantity, meaning it has both magnitude and direction. In collisions, momentum plays a pivotal role because it is always conserved, even if kinetic energy is not.

In the problem at hand, each car and rider is considered a single system. Their combined mass and velocity determine their momentum. When car A collides with car B, the momentum before and after the collision should equal, assuming a closed system.
  • Calculating momentum helps to determine the resulting velocities, which is how we figure out the velocity changes for cars A and B post-collision.
  • Similarly, when car B collides with car C, the conservation of momentum applies again. This requires solving equations that account for both momentum conservation and the coefficient of restitution to ensure car B comes to rest.
These principles allow the derivation of necessary velocities and understanding the motion transitions in sequential collisions.

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Most popular questions from this chapter

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