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A spring scale \(A\) and a lever scale \(B\) having equal lever arms are fastened to the roof of an elevator, and identical packages are attached to the scales as shown. Knowing that when the elevator moves downward with an acceleration of \(1 \mathrm{m} / \mathrm{s}^{2}\) the spring scale indicates a load of \(60 \mathrm{N}\), determine \((a)\) the weight of the packages, (b) the load indicated by the spring scale and the mass needed to balance the lever scale when the elevator moves upward with an acceleration of \(1 \mathrm{m} / \mathrm{s}^{2}\).

Short Answer

Expert verified
(a) 66.8 N, (b) 73.7 N load; mass to balance: 7.51 kg.

Step by step solution

01

Understand the Physics

When an elevator is accelerating, the apparent force on an object changes due to the additional acceleration (or deceleration) of the elevator. For a downward acceleration, the force of gravity on an object appears reduced, and for an upward acceleration, the force is increased. The apparent weight of an object in an elevator is given by the equation: \( W' = m(g - a) \) for downward acceleration and \( W' = m(g + a) \) for upward acceleration, where \( W' \) is the apparent weight, \( m \) is the mass, \( g \) is the acceleration due to gravity (approximately 9.81 m/s²), and \( a \) is the acceleration of the elevator.
02

Calculate the Mass of the Package

Given that the apparent weight (60 N) is when the elevator accelerates downward at 1 m/s², apply the formula for the apparent weight: \( 60 = m(g - a) \). Now, rearrange to find the mass: \[ m = \frac{60}{9.81 - 1} = \frac{60}{8.81} \approx 6.81 \text{ kg} \]
03

Calculate the True Weight of the Package

Now that we have the mass, we can find the true weight in Newtons by simply multiplying the mass by the acceleration due to gravity: \[ W = 6.81 \times 9.81 \approx 66.8 \text{ N} \]
04

Determine Apparent Weight: Elevator Moving Upward

Now when the elevator moves upward with an acceleration of 1 m/s², the apparent weight changes. Using the formula for upward acceleration, we find:For apparent weight \( W' = m(g + a) \): \[ W' = 6.81(9.81 + 1) = 6.81 \times 10.81 \approx 73.7 \text{ N} \]
05

Determine Mass Needed for Balance

To balance the lever scale, which will indicate a balance force equal to the calculated apparent weight, the mass must be adjusted to provide an equivalent downward force (in the environment of the elevator's upward motion):Rearranging to find the mass that this apparent weight corresponds to:\[ m_{balance} = \frac{73.7}{9.81} \approx 7.51 \text{ kg} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Forces in Elevators
When you ride in an elevator, have you noticed how the weight you experience feels different during starts and stops? This is due to forces acting on you besides gravity. These include the force due to the elevator's acceleration or deceleration, which changes depending on the direction the elevator is moving.
Imagine standing on a scale inside an elevator. The number you see fluctuates as the elevator changes speed, illustrating the concept of apparent weight.
In physics, when an elevator accelerates downwards, you feel lighter because the force due to the elevator's acceleration counteracts some of the gravitational force. Conversely, when the elevator accelerates upwards, you feel heavier because the elevator adds to the gravitational pull.
Apparent Weight
Apparent weight is the weight registered by a scale, and it changes when you're in an accelerating elevator. It's a reflection of the net force acting on you, including gravity and the elevator's acceleration.
This is summarized by the formula:
  • Downwards acceleration: \( W' = m(g - a) \)
  • Upwards acceleration: \( W' = m(g + a) \)

Here, \( W' \) is the apparent weight, \( m \) is mass, \( g \) is the acceleration due to gravity, and \( a \) is the acceleration of the elevator.
By understanding this concept, you can estimate changes in apparent weight during different elevator movements, which is crucial for predicting the load on scales under such conditions.
Spring Scale Mechanics
Spring scales measure weight through the extension of a spring. Hooke’s Law describes the relationship between the force applied to a spring and the amount of stretch:
\[ F = kx \]
Where \( F \) is the force, \( k \) is the spring constant, and \( x \) is the displacement of the spring. The force indicated by the scale is the apparent weight, changing based on external accelerations like those of an elevator.
When the elevator accelerates downward, the spring compresses less than at rest, showing a lower weight. Conversely, upward acceleration causes more compression, indicating a higher weight. Understanding this can help in interpreting readings under different conditions.
Lever Balance Principles
A lever scale balances two opposing torques on either side of a pivot point. When used in an elevator, the balance is affected by apparent weight changes due to acceleration.
With equal lever arms, the torque created by a weight (\( Weight imes Lever imes Arm Length \)) is balanced by an equivalent counterweight on the opposite side.
If the elevator accelerates, the apparent weight changes, necessitating an adjustment in the mass that balances the scale.
This principle is critical in applications where precise weight measurement is required in non-stationary environments, such as elevators or moving vehicles.

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Most popular questions from this chapter

Block \(A\) has a mass of \(10 \mathrm{kg}\), and blocks \(B\) and \(C\) have masses of \(5 \mathrm{kg}\) each. Knowing that the blocks are initially at rest and that \(B\) moves through \(3 \mathrm{m}\) in \(2 \mathrm{s}\), determine (a) the magnitude of the force \(\mathrm{P},(b)\) the tension in the cord \(A D .\) Neglect the masses of the pulleys and axle friction.

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