/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 A uniform sphere with mass \(M\)... [FREE SOLUTION] | 91Ó°ÊÓ

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A uniform sphere with mass \(M\) and radius \(R\) is rotating with angular speed \(\omega_{1}\) about a frictionless axle along a diameter of the sphere. The sphere has rotational kinetic energy \(K_{1}\). A thin-walled hollow sphere has the same mass and radius as the uniform sphere. It is also rotating about a fixed axis along its diameter. In terms of \(\omega_{1},\) what angular speed must the hollow sphere have if its kinetic energy is also \(K_{1},\) the same as for the uniform sphere?

Short Answer

Expert verified
\(\omega_{2} = \sqrt{\frac{5}{3}}\omega_{1}\)

Step by step solution

01

Moment of Inertia for Uniform Sphere

First, we find the moment of inertia for the uniform (solid) sphere using the formula \(I_{1} = \frac{2}{5} M R^2\). We know that the kinetic energy of this sphere is \(K_{1} = \frac{1}{2} I_{1} \omega_{1}^2\), so we can express \(\omega_{1}^2\) as \(\omega_{1}^2 = \frac{2 K_{1}}{I_{1}}\).
02

Moment of Inertia for Hollow Sphere

Next, we calculate the moment of inertia for the hollow sphere using the formula \(I_{2} = \frac{2}{3} M R^2\). Since we want its kinetic energy to be \(K_{1}\), we can write that as \(K_{1} = \frac{1}{2} I_{2} (\omega_{2})^2\). This implies that \((\omega_{2})^2 = \frac{2 K_{1}}{I_{2}}\).
03

Solve for \(\omega_{2}\)

Finally, we equate \(\omega_{1}^2\) to \((\omega_{2})^2\) and solve for \(\omega_{2}\) to find its value in terms of \(\omega_{1}\). This gives \(\omega_{2}\) = \(\sqrt{\frac{5}{3}\omega_{1}^2}\). This answer is a numerical representation of the argument that the hollow sphere must rotate faster to store the same amount of rotational kinetic energy as the solid one, because its mass is distributed farther from the axis of rotation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
Moment of inertia is a measure of how much a body resists rotational motion. Think of it as rotational mass. It determines how easy or difficult it is to change the rotational speed of an object.
For a solid sphere, the moment of inertia is given by the formula:
  • \(I = \frac{2}{5} M R^2\)
In this formula, \(M\) is the mass of the sphere and \(R\) is its radius, indicating that these two quantities significantly influence how the mass is spread around the axis.
For a hollow sphere, the moment of inertia is:
  • \(I = \frac{2}{3} M R^2\)
The hollow sphere has more mass distributed far from the axis compared to the solid sphere, resulting in a larger moment of inertia. This means it takes more energy for the hollow sphere to rotate at the same speed as the solid sphere.
Angular Speed
Angular speed (\(\omega\) ) indicates how quickly an object rotates or revolves around an axis. It's similar to linear speed but in the context of circular motion.
For the exercise at hand, the uniform sphere rotates at angular speed \(\omega_1\) and needs a certain kinetic energy, \(K_1\).
Rotational kinetic energy is expressed by:
  • \(K = \frac{1}{2} I \omega^2\)
Here, \(I\) is the moment of inertia, showing a clear relationship between the angular speed and rotational kinetic energy.
To achieve the same kinetic energy \(K_1\) in the hollow sphere, where the moment of inertia \(I_2\) is larger, the angular speed \(\omega_2\) must be higher than \(\omega_1\). This is calculated by finding the conditions where:
  • \(\omega_2 = \sqrt{\frac{5}{3}} \omega_1\)
Thus, the hollow sphere must rotate faster than the solid sphere to reach the same kinetic energy due to its larger moment of inertia.
Rotational Dynamics
Rotational dynamics govern how forces affect rotational motion, much like linear dynamics for objects moving in a straight line. These principles help us understand how objects behave as they spin.
An essential part of rotational dynamics is the relationship between torques and moments of inertia. They determine the angular acceleration and the subsequent rotational movement. In our exercise, we're focused on how these dynamics ensure both spheres achieve the same rotational kinetic energy despite having different structures.
The energy equations \(K_1 = \frac{1}{2} I_1 \omega_1^2\) and \(K_1 = \frac{1}{2} I_2 \omega_2^2\) show how different moments of inertia affect the rotational speed necessary to achieve identical kinetic energy levels.
Understanding how the mass distribution within each sphere affects rotational dynamics is crucial. A wider spread mass means that the hollow sphere will need a higher angular speed to match the kinetic energy of the solid sphere, illustrating the core principle that changes in mass distribution change rotational characteristics.

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Most popular questions from this chapter

While riding a multispeed bicycle, the rider can select the radius of the rear sprocket that is fixed to the rear axle. The front sprocket of a bicycle has radius \(12.0 \mathrm{~cm} .\) If the angular speed of the front sprocket is 0.600 rev \(/ \mathrm{s},\) what is the radius of the rear sprocket for which the tangential speed of a point on the rim of the rear wheel will be \(5.00 \mathrm{~m} / \mathrm{s} ?\) The rear wheel has radius \(0.330 \mathrm{~m}\).

A safety device brings the blade of a power mower from an initial angular speed of \(\omega_{1}\) to rest in 1.00 revolution. At the same constant acceleration, how many revolutions would it take the blade to come to rest from an initial angular speed \(\omega_{3}\) that was three times as great, \(\omega_{3}=3 \omega_{1} ?\)

A uniform disk has radius \(R_{0}\) and mass \(M_{0}\). Its moment of inertia for an axis perpendicular to the plane of the disk at the disk's center is \(\frac{1}{2} M_{0} R_{0}^{2}\). You have been asked to halve the disk's moment of inertia by cutting out a circular piece at the center of the disk. In terms of \(R_{0}\), what should be the radius of the circular piece that you remove?

The rotating blade of a blender turns with constant angular acceleration \(1.50 \mathrm{rad} / \mathrm{s}^{2}\). (a) How much time does it take to reach an angular velocity of \(36.0 \mathrm{rad} / \mathrm{s},\) starting from rest? (b) Through how many revolutions does the blade turn in this time interval?

Energy is to be stored in a \(70.0 \mathrm{~kg}\) flywheel in the shape of a uniform solid disk with radius \(R=1.20 \mathrm{~m}\). To prevent structural failure of the flywheel, the maximum allowed radial acceleration of a point on its rim is \(3500 \mathrm{~m} / \mathrm{s}^{2}\). What is the maximum kinetic energy that can be stored in the flywheel?

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