/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 \(\mathrm{A}\) turntable rotates... [FREE SOLUTION] | 91Ó°ÊÓ

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\(\mathrm{A}\) turntable rotates with a constant \(2.25 \mathrm{rad} / \mathrm{s}^{2}\) clockwise angular acceleration. After \(4.00 \mathrm{~s}\) it has rotated through a clockwise angle of 30.0 rad. What was the angular velocity of the wheel at the beginning of the 4.00 s interval?

Short Answer

Expert verified
The initial angular velocity of the wheel at the beginning of the 4.00 s interval is 0.25 rad/s.

Step by step solution

01

Identify the given values

From the question, we can identify the following values: Angular displacement (θ) = 30.0 rad, Time (t) = 4.00 s, and Angular acceleration (α) = 2.25 rad/s^2.
02

Apply the formula for angular displacement

The formula for angular displacement is given by: θ = ω_initial*t + 0.5*α*t^2. Using the given values, we can rewrite the formula as: ω_initial = (θ - 0.5*α*t^2) / t.
03

Substitute the values into the formula

By substituting the values into the formula, we get: ω_initial = (30.0 rad - 0.5*(2.25 rad/s^2)*(4.00 s)^2) / 4.00 s
04

Solve the equation

Now we just need to solve the equation for ω_initial. After doing the math, we get: ω_initial = 0.25 rad/s

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Displacement
Angular displacement is the measure of how much an object has rotated or moved around a central point, often expressed in radians. It captures the extent of rotation and typically denotes the change in the angular position of an object. In our exercise, you can see that the turntable has an angular displacement of 30.0 radians, after a time period of 4 seconds.
This means it completed a significant rotation from its starting point in these 4 seconds.

The formula for angular displacement is crucial in solving such problems. It takes the form:
  • \( \theta = \omega_{\text{initial}} \times t + 0.5 \times \alpha \times t^2 \)
where \( \theta \) is the angular displacement, \( \omega_{\text{initial}} \) is the initial angular velocity, \( t \) is the time, and \( \alpha \) is the angular acceleration.
Understanding this formula helps unravel how initial speed and acceleration affect how much something rotates in a given time.
Angular Acceleration
Angular acceleration refers to how quickly an object's rotation rate (angular velocity) changes. This change happens over time and is measured in radians per second squared ("]\text{rad/s}^2\").

In the given exercise, the turntable experiences a constant angular acceleration of 2.25 \( \text{rad/s}^2 \).
This means that for each passing second, the rotational speed of the turntable increases by 2.25 radians per second. Angular acceleration plays a key role in determining how fast an object reaches its desired rotation speed.

The inclusion of the angular acceleration in rotational kinematics equations helps predict future positions and speeds of rotating bodies. Hence, knowing how to apply it to the displacement formula enables you to find starting or additional kinetic parameters effectively, like initial velocity in this case.
Kinematics
Kinematics is the branch of mechanics that involves the motion of objects without considering the causes of motion. When applied to rotational movement, it focuses on parameters such as angular displacement, angular velocity, and angular acceleration.

Rotational kinematics can be seen as an extension of linear kinematics but for rotating bodies. In rotational kinematics, similar principles apply as those in linear:
  • Displacement (\( \theta \) in rotation)
  • Velocity (\( \omega \) in rotation)
  • Acceleration (\( \alpha \) in rotation)
These parameters help us precisely figure out and solve problems related to objects moving in circular paths.
By understanding both linear and rotational kinematics, such as the equations used for the turntable problem, students can effectively bridge concepts across different types of motion and gain deeper insight into dynamic systems.

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Most popular questions from this chapter

An airplane propeller is rotating at 1900 rpm (rev/min). (a) Compute the propeller's angular velocity in rad/s. (b) How many seconds does it take for the propeller to turn through \(35^{\circ} ?\)

A pulley on a frictionless axle has the shape of a uniform solid disk of mass \(2.50 \mathrm{~kg}\) and radius \(20.0 \mathrm{~cm}\). A \(1.50 \mathrm{~kg}\) stone is attached to a very light wire that is wrapped around the rim of the pulley (Fig. E9.47), and the system is released from rest. (a) How far must the stone fall so that the pulley has \(4.50 \mathrm{~J}\) of kinetic energy? (b) What percent of the total kinetic energy does the pulley have?

A wheel is rotating about an axis that is in the \(z\) -direction. The angular velocity \(\omega_{z}\) is \(-6.00 \mathrm{rad} / \mathrm{s}\) at \(t=0,\) increases linearly with time, and is \(+4.00 \mathrm{rad} / \mathrm{s}\) at \(t=7.00 \mathrm{~s}\). We have taken counterclockwise rotation to be positive. (a) Is the angular acceleration during this time interval positive or negative? (b) During what time interval is the speed of the wheel increasing? Decreasing? (c) What is the angular displacement of the wheel at \(t=7.00 \mathrm{~s}\) ?

Two metal disks, one with radius \(R_{1}=2.50 \mathrm{~cm}\) and mass \(M_{1}=0.80 \mathrm{~kg}\) and the other with radius \(R_{2}=5.00 \mathrm{~cm}\) and mass \(M_{2}=1.60 \mathrm{~kg},\) are welded together and mounted on a frictionless axis through their common center (Fig. \(\mathbf{P 9 . 7 9}\) ). (a) What is the total moment of inertia of the two disks? (b) A light string is wrapped around the edge of the smaller disk, and a \(1.50 \mathrm{~kg}\) block is suspended from the free end of the string. If the block is released from rest at a distance of \(2.00 \mathrm{~m}\) above the floor, what is its speed just before it strikes the floor? (c) Repeat part (b), this time with the string wrapped around the edge of the larger disk. In which case is the final speed of the block greater? Explain.

The Crab Nebula is a cloud of glowing gas about 10 light-years across, located about 6500 light-years from the earth (Fig. P9.86). It is the remnant of a star that underwent a supernova \(e x\) plosion, seen on earth in 1054 A.D. Energy is released by the Crab Nebula at a rate of about \(5 \times 10^{31} \mathrm{~W},\) about \(10^{5}\) times the rate at which the sun radiates energy. The Crab Nebula obtains its energy from the rotational kinetic energy of a rapidly spinning neutron star at its center. This object rotates once every \(0.0331 \mathrm{~s},\) and this period is increasing by \(4.22 \times 10^{-13} \mathrm{~s}\) for each second of time that elapses. (a) If the rate at which energy is lost by the neutron star is equal to the rate at which energy is released by the nebula, find the moment of inertia of the neutron star. (b) Theories of supernovae predict that the neutron star in the Crab Nebula has a mass about 1.4 times that of the sun. Modeling the neutron star as a solid uniform sphere, calculate its radius in kilometers. (c) What is the linear speed of a point on the equator of the neutron star? Compare to the speed of light. (d) Assume that the neutron star is uniform and calculate its density. Compare to the density of ordinary rock \(\left(3000 \mathrm{~kg} / \mathrm{m}^{3}\right)\) and to the density of an atomic nucleus (about \(\left.10^{17} \mathrm{~kg} / \mathrm{m}^{3}\right) .\) Justify the statement that a neutron star is essentially a large atomic nucleus.

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