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Two carts of cqual mass are on a horizontal, frictionless air track. Initially cart \(A\) is moving toward stationary cart \(B\) with a speed of \(v_{A}\). The carts undergo an inelastic collision, and after the collision the total kinetic energy of the two carts is one-half their initial total kinctic energy before the collision. What is the speed of cach cart after the collision?

Short Answer

Expert verified
The speed of each cart after the collision is 0.5 times the initial speed of cart A, i.e., 0.5\(v_{A}\).

Step by step solution

01

Define Variables

Let's define the initial velocity of cart \(B\) as \(v_{B} = 0\). Let \(v_{F}\) be the velocity of both carts after the collision since they stick together (inelastic collision).
02

Apply Conservation of Momentum

According to the principle of conservation of momentum, the total momentum before collision equals the total momentum after collision. That can be written as: \(m_{A} v_{A} + m_{B} v_{B} = (m_{A} + m_{B}) v_{F}\).\nAs the masses of both carts are equal, let's take the mass of each cart as \(m\). The equation then becomes: \(m v_{A} + m * 0 = (m + m) v_{F} \), which simplifies to \(v_{A} = 2 v_{F}\).
03

Apply Conservation of Energy

As given, after the collision the total kinetic energy is half of the initial. That can be written as: \(0.5 m v_{A}^2 = 0.5 * 0.5 (2m) v_{F}^2\).\nOn simplification, \(v_{A}^2 = 4v_{F}^2\).
04

Solve for Final Velocity

By substituting \(v_{A} = 2 v_{F}\) from step 2 into step 3 expression, we can solve for \(v_{F}\), which will be the velocity of each of the carts after the collision. The solution is \(v_{F} = 0.5 v_{A}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
The concept of conservation of momentum is crucial in understanding inelastic collisions like the one described in the exercise. Momentum is the product of mass and velocity and is a vector, meaning it has both magnitude and direction. In the absence of external forces, the total momentum of a system remains constant before and after a collision.

In our example, both carts have the same mass. Initially, only cart A is moving, and cart B is stationary. This results in an initial momentum solely contributed by cart A. According to momentum conservation, the total momentum before the collision (when cart A is moving) must equal the total momentum after the collision (when both carts move together). This simplifies math since the momentum formula before the collision is:
  • Initial momentum: \[m_{A} v_{A} + m_{B} v_{B} = (m_{A} + m_{B}) v_{F}\]
  • As cart B is not moving initially, its velocity is zero, simplifying the equation to \(v_{A} = 2v_{F}\).
This equation helps us find the relationship between the velocities of the carts before and after the collision.
Conservation of Energy
The conservation of energy is a key principle in physics that states energy in a closed system remains constant. However, during inelastic collisions, such as the one described, some kinetic energy is transformed into other forms, like sound or thermal energy.

In this particular exercise, we're told that after the inelastic collision, the kinetic energy is halved. Initially, only cart A had kinetic energy because cart B was stationary. Therefore, the initial kinetic energy is:
  • Initial kinetic energy: \[0.5 m v_{A}^2\]
After the collision, when carts A and B stick together and move with a common velocity \(v_{F}\), the new kinetic energy is:
  • After collision kinetic energy:\[0.5 \times 0.5 (2m) v_{F}^2\]
When set equal (considering kinetic energy becomes half), it leads us to find the equation: \(v_{A}^2 = 4v_{F}^2\). This allows us to solve for the final velocities of the carts after the collision.
Kinetic Energy
Kinetic energy is the energy an object has due to its movement, calculated with the formula \(KE = 0.5 \, m \, v^2\), where \(m\) is mass and \(v\) is velocity. In collisions, understanding kinetic energy provides insight into how objects share energy during impact.

In this exercise involving carts A and B, kinetic energy helps establish the differences between before and after the collision. Initially, cart A, having velocity \(v_{A}\), possesses kinetic energy. Since we were told that the kinetic energy after the collision is half of what it was initially, it highlights the property of inelastic collisions that kinetic energy is not conserved.

Use the initial expression to find out the loss of kinetic energy:
  • Initial kinetic energy: \[0.5 m v_{A}^2\]
  • After collision, it's half: \[0.5 \times (0.5 m v_{A}^2) = KE_{final}\]
This exercise also underlines inelastic collisions' unique nature. Not all initial kinetic energy is retained in the new motion. Instead, it's redistributed in different forms or lost, which is the opposite of the behavior in elastic collisions.

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Most popular questions from this chapter

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Object \(B\) is at rest when object \(A\) collides with it. The collision is one- dimensional and elastic. After the collision object \(B\) has half the velocity that object \(A\) had before the collision. (a) Which object has the greater mass? (b) How much greater? (c) If the velocity of object \(A\) before the collision was \(6.0 \mathrm{~m} / \mathrm{s}\) to the right. what is its velocity after the collision?

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