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Starting at \(t=0\) a net external force in the \(+x\) -direction is applied to an object that has mass \(2.00 \mathrm{~kg}\). A graph of the force as a function of time is a straight line that passes through the origin and has slope \(3.00 \mathrm{~N} / \mathrm{s}\). If the object is at rest at \(t=0\). what is the magnitude of the force when the object has reached a speed of \(9.00 \mathrm{~m} / \mathrm{s} ?\)

Short Answer

Expert verified
The magnitude of the force when the object has reached a speed of \(9.00 m/s\) is obtained by plugging the value of \(t\) from Step 1 into the force equation, which gives us \(F = 3.00N/s \cdot \sqrt{9.00 / 1.50}s\).

Step by step solution

01

Calculate the time taken to reach the speed

Since the initial speed is \(0 m/s\) and the final speed is \(9.00 m/s\), we can use the equation of motion \(v = u + at\) where \(v\) is the final speed, \(u\) is the initial speed, \(a\) is acceleration and \(t\) is time. Here, \(u = 0 m/s\), \(v = 9.00 m/s\) and \(a = F/m\) where \(F\) is force and \(m\) is mass. Since the force is varying with time as \(F = 3.00N/s \cdot t\), the acceleration also varies with time as \(a = F/m = 3.00N/s \cdot t / 2.00 kg\). This gives us \(a = 1.50t m/s^2\). Substituting \(a\) in the equation of motion gives \(9.00 = 0 + 1.50t^2\), which simplifies to \(t = \sqrt{9.00 / 1.50}s\).
02

Calculate the force

When the object has reached a speed of \(9.00 m/s\), \(t = \sqrt{9.00 / 1.50}s\). We substitute this value of \(t\) into the equation of the force \(F = 3.00N/s \cdot t\) to get the magnitude of the force at this instant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
Newton's second law of motion tells us that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This relationship is expressed by the equation \( F = ma \), where \( F \) is the force applied to an object, \( m \) is the mass of the object, and \( a \) is the acceleration.
To illustrate this concept, consider an object that starts from rest and has a force applied to it that increases linearly with time. In such a scenario, the acceleration of the object also increases with time since acceleration is the rate of change of velocity. If the mass of the object is constant, and the force changes with time, then the acceleration will change proportionally with the force.
In the exercise provided, the force exerted on a 2.00 kg object is a linear function of time with a slope of \( 3.00 \text{N/s} \), symbolizing how the force increases as time progresses. To find the acceleration, we divide the force by the mass of the object at any given time, thus we have \( a = \frac{F}{m} = \frac{3.00t}{2.00} = 1.50t \).
Kinematic Equations
The kinematic equations enable us to describe motion in terms of displacement, velocity, acceleration, and time. These equations are crucial when dealing with linear motion, particularly when the motion is uniformly accelerated. The basic form of a kinematic equation is \( v = u + at \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time elapsed.
In our exercise, the initial velocity \( u \) is 0 m/s because the object starts from rest, and we want to determine at what point in time the object reaches a final velocity \( v \) of 9.00 m/s. Substituting the known values and the acceleration expression we derived earlier into the kinematic equation, we can determine the time it takes for the object to reach this speed. From this, we can also deduce the force using the relationship between acceleration and time for this specific scenario.
Linear Motion
Linear motion refers to the movement of an object in a straight line. In the context of our exercise, once the force is applied to the object, it begins to move in the direction of the force, creating linear motion. The object's motion can be described using kinematic equations if the motion is uniformly accelerated, but in our case, the acceleration is not constant because the force changes with time.
When analyzing problems involving linear motion, it's important to note that the object's velocity, acceleration, and the forces acting upon it are all vectors, which means they have both magnitude and direction. For simplicity, we're only considering motion along the x-axis and forces in the +x-direction. As a result, this ensures that we're examining a one-dimensional motion, making our calculations and understanding of the situation more straightforward.
By understanding how linear motion works, we can apply Newton's second law to determine how the motion of the object will evolve over time given a specific force pattern. This allows us to solve for various quantities, such as the velocity at a specific time, which we did using the kinematic equations previously discussed.

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