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Moderators. Canadian nuclear reactors use heavy water moderators in which elastic collisions occur between the neutrons and deuterons of mass \(2.0 \mathrm{u}\) (see Example 8.11 in Section 8.4 ). (a) What is the spced of a neutron, expressed as a fraction of its original specd. after a hcad-on, clastic collision with a deuteron that is initially at rest? (b) What is its kinctic energy, expressed as a fraction of its original kinetic energy? (c) How many such successive collisions will reduce the speed of a neutron to \(1 / 59,000\) of its original valuc?

Short Answer

Expert verified
a) After the head-on, elastic collision with a deuteron, the speed of the neutron is reduced to one-third (\(1 / 3\)) of its original speed. b) The neutron's kinetic energy is reduced to \(\frac{4}{9}\) of its original kinetic energy. c) It takes approximately 11 such collisions to reduce the neutron's speed to \(1 / 59,000\) of its original value.

Step by step solution

01

Establish the Situation

In each collision, a neutron of mass \(m_{n} = 1u\) initially moving with velocity \(v_{0}\) collides head-on with a deuteron of mass \(m_{d} = 2u\), initially at rest. An elastic collision occurs. From conservation of momentum, we have \(m_{n}v_{0} = m_{n}v_{n} + m_{d}v_{d}\), where \(v_{n}\) and \(v_{d}\) are the velocities of the neutron and deuteron, respectively, after the collision.
02

Solve for the Neutron's Final Velocity

As the deuteron is initially at rest, its final velocity (\(v_{d}\)) will be equal to \(v_{0} - v_{n}\). Substituting this into the previous equation, we derive the velocity of the neutron after the collision as \(v_{n} = \frac{1}{3}v_{0}\). Thus, the neutron's speed is reduced to one-third of its original speed in each collision.
03

Calculate the Final Kinetic Energy

Kinetic energy after the head-on, elastic collision will be \(\frac{1}{2}m_{n}v_{n}^{2} + \frac{1}{2}m_{d}v_{d}^{2}\). Upon substituting the previously calculated values for \(v_{n}\) and \(v_{d}\), we derive the final kinetic energy as \(\frac{4}{9}\) of the initial kinetic energy.
04

Determine the Number of Collisions

Since the neutron's speed is divided by 3 in each collision, the number of collisions needed to reduce its speed to \(1 / 59,000\) of its original value can be found using the power of 3 that gives \(1 / 59,000\). Calculating log base 3 of 59,000 yields approximately 11. Hence, eleven collisions will reduce the neutron's speed to \(1 / 59,000\) of its initial value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
Understanding the conservation of momentum in nuclear reactors is vital for grasping the underlying mechanics of neutron moderation. Momentum, a physical quantity associated with moving objects, is conserved in an isolated system. This means the total momentum before and after a collision remains constant when there are no external forces acting upon the system.

Diving deeper into our example involving a neutron colliding with a deuteron, we can apply the principle of conservation of momentum to predict the aftermath of the collision. We express this conservation mathematically as \( m_n v_0 = m_n v_n + m_d v_d \), where \( m_n \) and \( m_d \) represent the masses of the neutron and deuteron, and \( v_n \) and \( v_d \) are their respective velocities after the collision.

The importance of the concept becomes clear when we see that it gives us a way to predict the behavior of particles following an interaction, which is crucial for controlling reactions within a nuclear reactor. Without this conservation law, it would be impossible to manage the energy release within reactors safely.
Kinetic Energy in Collisions
Kinetic energy represents the energy that an object possesses due to its motion. In the context of nuclear reactors, understanding how kinetic energy transfers during collisions is essential. When a neutron collides elastically with a deuteron, their kinetic energies are conserved.

An 'elastic' collision is one where, in addition to momentum, the total kinetic energy is also conserved. We can express the kinetic energy of the two particles after the collision as \( \frac{1}{2}m_n v_n^2 + \frac{1}{2}m_d v_d^2 \). Calculations based on the conservation of kinetic energy tell us how much energy remains with the neutron after successive collisions.

Applying Kinetic Energy in Reactor Control

In a nuclear reactor, controlling the kinetic energy of neutrons through moderation—typically by elastic collisions—is how operators manage the reactor's chain reactions. A deep understanding of how kinetic energy is redistributed between particles during these collisions helps ensure that reactors operate within safe parameters.
Neutron Moderation
Neutron moderation is a fundamental concept in nuclear reactions, especially within reactors. The moderation process slows down fast-moving neutrons through repeated collisions, ideally elastic, with atomic nuclei such as deuterons in heavy water moderators.

Elastic collisions ensure the conservation of kinetic energy and momentum, effectively reducing the energy of the neutron without losses. The speed of the neutron after each collision gives us insight into how effective the moderator is. In the case of heavy water moderators, deuterons, due to their mass comparable to the neutrons, are particularly effective for this purpose.

The Importance of Effective Moderation

Effective neutron moderation leads to a stable and sustained nuclear chain reaction. By slowing down the neutrons, they are more likely to cause further fission when they collide with fuel nuclei. Control of this process is crucial for energy production in nuclear power plants and the safety of the environment and surrounding population.

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Most popular questions from this chapter

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